我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。
基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)
或者,如果找不到,有没有可能找到最高处的风景?
我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。
基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)
或者,如果找不到,有没有可能找到最高处的风景?
当前回答
为了避免很多复杂性,我通过在委托中创建一个viewController来跟踪当前的viewController,并在每个viewDidLoad方法中设置它为self,这样每当你加载一个新视图时,委托中持有的viewController将对应于该视图的viewController。这可能是丑陋的,但它工作得很好,没有必要有一个导航控制器或任何废话。
其他回答
伟大的解决方案在Swift,实现在AppDelegate
func getTopViewController()->UIViewController{
return topViewControllerWithRootViewController(UIApplication.sharedApplication().keyWindow!.rootViewController!)
}
func topViewControllerWithRootViewController(rootViewController:UIViewController)->UIViewController{
if rootViewController is UITabBarController{
let tabBarController = rootViewController as! UITabBarController
return topViewControllerWithRootViewController(tabBarController.selectedViewController!)
}
if rootViewController is UINavigationController{
let navBarController = rootViewController as! UINavigationController
return topViewControllerWithRootViewController(navBarController.visibleViewController)
}
if let presentedViewController = rootViewController.presentedViewController {
return topViewControllerWithRootViewController(presentedViewController)
}
return rootViewController
}
以下是对我有效的方法。
我发现有时候控制器在键窗口上是nil,因为键窗口是一些操作系统的东西,如警报等。
+ (UIViewController*)topMostController
{
UIWindow *topWndow = [UIApplication sharedApplication].keyWindow;
UIViewController *topController = topWndow.rootViewController;
if (topController == nil)
{
// The windows in the array are ordered from back to front by window level; thus,
// the last window in the array is on top of all other app windows.
for (UIWindow *aWndow in [[UIApplication sharedApplication].windows reverseObjectEnumerator])
{
topController = aWndow.rootViewController;
if (topController)
break;
}
}
while (topController.presentedViewController) {
topController = topController.presentedViewController;
}
return topController;
}
- (UIViewController*)topViewController {
return [self topViewControllerWithRootViewController:[UIApplication sharedApplication].keyWindow.rootViewController];
}
- (UIViewController*)topViewControllerWithRootViewController:(UIViewController*)rootViewController {
if ([rootViewController isKindOfClass:[UITabBarController class]]) {
UITabBarController* tabBarController = (UITabBarController*)rootViewController;
return [self topViewControllerWithRootViewController:tabBarController.selectedViewController];
} else if ([rootViewController isKindOfClass:[UINavigationController class]]) {
UINavigationController* navigationController = (UINavigationController*)rootViewController;
return [self topViewControllerWithRootViewController:navigationController.visibleViewController];
} else if (rootViewController.presentedViewController) {
UIViewController* presentedViewController = rootViewController.presentedViewController;
return [self topViewControllerWithRootViewController:presentedViewController];
} else {
return rootViewController;
}
}
这个解决方案是最完整的。它考虑到: UINavigationController UIPageViewController UITabBarController 最上面的视图控制器来自顶部视图控制器
以Swift 3为例。
有3个重载
//Get the topmost view controller for the current application.
public func MGGetTopMostViewController() -> UIViewController? {
if let currentWindow:UIWindow = UIApplication.shared.keyWindow {
return MGGetTopMostViewController(fromWindow: currentWindow)
}
return nil
}
//Gets the topmost view controller from a specific window.
public func MGGetTopMostViewController(fromWindow window:UIWindow) -> UIViewController? {
if let rootViewController:UIViewController = window.rootViewController
{
return MGGetTopMostViewController(fromViewController: rootViewController)
}
return nil
}
//Gets the topmost view controller starting from a specific UIViewController
//Pass the rootViewController into this to get the apps top most view controller
public func MGGetTopMostViewController(fromViewController viewController:UIViewController) -> UIViewController {
//UINavigationController
if let navigationViewController:UINavigationController = viewController as? UINavigationController {
let viewControllers:[UIViewController] = navigationViewController.viewControllers
if navigationViewController.viewControllers.count >= 1 {
return MGGetTopMostViewController(fromViewController: viewControllers[viewControllers.count - 1])
}
}
//UIPageViewController
if let pageViewController:UIPageViewController = viewController as? UIPageViewController {
if let viewControllers:[UIViewController] = pageViewController.viewControllers {
if viewControllers.count >= 1 {
return MGGetTopMostViewController(fromViewController: viewControllers[0])
}
}
}
//UITabViewController
if let tabBarController:UITabBarController = viewController as? UITabBarController {
if let selectedViewController:UIViewController = tabBarController.selectedViewController {
return MGGetTopMostViewController(fromViewController: selectedViewController)
}
}
//Lastly, Attempt to get the topmost presented view controller
var presentedViewController:UIViewController! = viewController.presentedViewController
var nextPresentedViewController:UIViewController! = presentedViewController?.presentedViewController
//If there is a presented view controller, get the top most prensentedViewController and return it.
if presentedViewController != nil {
while nextPresentedViewController != nil {
//Set the presented view controller as the next one.
presentedViewController = nextPresentedViewController
//Attempt to get the next presented view controller
nextPresentedViewController = presentedViewController.presentedViewController
}
return presentedViewController
}
//If there is no topmost presented view controller, return the view controller itself.
return viewController
}
I am thinking that perhaps one thing is being overlooked here. Perhaps it is better to pass the parent viewController into the function that is using the viewController. If you are fishing around in the view hierarchy to find the top view controller that it is probably violating separation of the Model layer and UI layer and is a code smell. Just pointing this out, I did the same, then realized it was much simpler just to pass it in to function, by having the model operation return to the UI layer where I have a reference to the view controller.