我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。
基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)
或者,如果找不到,有没有可能找到最高处的风景?
我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。
基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)
或者,如果找不到,有没有可能找到最高处的风景?
当前回答
这是一个Swift的应用程序的实现与UINavigationController的根。
if let nav = UIApplication.sharedApplication().keyWindow?.rootViewController as? UINavigationController{
//get the current's navigation view controller
var vc = nav.topViewController
while vc?.presentedViewController != nil {
vc = vc?.presentedViewController
}
return vc
}
其他回答
另一个Swift解决方案
func topController() -> UIViewController? {
// recursive follow
func follow(from:UIViewController?) -> UIViewController? {
if let to = (from as? UITabBarController)?.selectedViewController {
return follow(to)
} else if let to = (from as? UINavigationController)?.visibleViewController {
return follow(to)
} else if let to = from?.presentedViewController {
return follow(to)
}
return from
}
let root = UIApplication.sharedApplication().keyWindow?.rootViewController
return follow(root)
}
斯威夫特5
试试这个
let topVisibleVC = UIApplication.shared.keyWindow?.rootViewController?.visibleViewController
简单的扩展UIApplication在Swift:
注意:
它关心UITabBarController中的moreNavigationController
extension UIApplication {
class func topViewController(baseViewController: UIViewController? = UIApplication.sharedApplication().keyWindow?.rootViewController) -> UIViewController? {
if let navigationController = baseViewController as? UINavigationController {
return topViewController(navigationController.visibleViewController)
}
if let tabBarViewController = baseViewController as? UITabBarController {
let moreNavigationController = tabBarViewController.moreNavigationController
if let topViewController = moreNavigationController.topViewController where topViewController.view.window != nil {
return topViewController(topViewController)
} else if let selectedViewController = tabBarViewController.selectedViewController {
return topViewController(selectedViewController)
}
}
if let splitViewController = baseViewController as? UISplitViewController where splitViewController.viewControllers.count == 1 {
return topViewController(splitViewController.viewControllers[0])
}
if let presentedViewController = baseViewController?.presentedViewController {
return topViewController(presentedViewController)
}
return baseViewController
}
}
简单的用法:
if let topViewController = UIApplication.topViewController() {
//do sth with top view controller
}
这个解决方案是最完整的。它考虑到: UINavigationController UIPageViewController UITabBarController 最上面的视图控制器来自顶部视图控制器
以Swift 3为例。
有3个重载
//Get the topmost view controller for the current application.
public func MGGetTopMostViewController() -> UIViewController? {
if let currentWindow:UIWindow = UIApplication.shared.keyWindow {
return MGGetTopMostViewController(fromWindow: currentWindow)
}
return nil
}
//Gets the topmost view controller from a specific window.
public func MGGetTopMostViewController(fromWindow window:UIWindow) -> UIViewController? {
if let rootViewController:UIViewController = window.rootViewController
{
return MGGetTopMostViewController(fromViewController: rootViewController)
}
return nil
}
//Gets the topmost view controller starting from a specific UIViewController
//Pass the rootViewController into this to get the apps top most view controller
public func MGGetTopMostViewController(fromViewController viewController:UIViewController) -> UIViewController {
//UINavigationController
if let navigationViewController:UINavigationController = viewController as? UINavigationController {
let viewControllers:[UIViewController] = navigationViewController.viewControllers
if navigationViewController.viewControllers.count >= 1 {
return MGGetTopMostViewController(fromViewController: viewControllers[viewControllers.count - 1])
}
}
//UIPageViewController
if let pageViewController:UIPageViewController = viewController as? UIPageViewController {
if let viewControllers:[UIViewController] = pageViewController.viewControllers {
if viewControllers.count >= 1 {
return MGGetTopMostViewController(fromViewController: viewControllers[0])
}
}
}
//UITabViewController
if let tabBarController:UITabBarController = viewController as? UITabBarController {
if let selectedViewController:UIViewController = tabBarController.selectedViewController {
return MGGetTopMostViewController(fromViewController: selectedViewController)
}
}
//Lastly, Attempt to get the topmost presented view controller
var presentedViewController:UIViewController! = viewController.presentedViewController
var nextPresentedViewController:UIViewController! = presentedViewController?.presentedViewController
//If there is a presented view controller, get the top most prensentedViewController and return it.
if presentedViewController != nil {
while nextPresentedViewController != nil {
//Set the presented view controller as the next one.
presentedViewController = nextPresentedViewController
//Attempt to get the next presented view controller
nextPresentedViewController = presentedViewController.presentedViewController
}
return presentedViewController
}
//If there is no topmost presented view controller, return the view controller itself.
return viewController
}
以下是对我有效的方法。
我发现有时候控制器在键窗口上是nil,因为键窗口是一些操作系统的东西,如警报等。
+ (UIViewController*)topMostController
{
UIWindow *topWndow = [UIApplication sharedApplication].keyWindow;
UIViewController *topController = topWndow.rootViewController;
if (topController == nil)
{
// The windows in the array are ordered from back to front by window level; thus,
// the last window in the array is on top of all other app windows.
for (UIWindow *aWndow in [[UIApplication sharedApplication].windows reverseObjectEnumerator])
{
topController = aWndow.rootViewController;
if (topController)
break;
}
}
while (topController.presentedViewController) {
topController = topController.presentedViewController;
}
return topController;
}