我刚刚开始学习Python。当我在Windows上执行一个python脚本文件时,输出窗口出现但立即消失。我需要它停留在那里,这样我就可以分析我的输出。我怎么才能让它一直开着?


当前回答

最简单的方法:

your_code()

while True:
   pass

当您打开窗口时,它不会关闭,直到您关闭提示符。

其他回答

试试这个,

import sys

stat='idlelib' in sys.modules

if stat==False:
    input()

这只会停止控制台窗口,而不是IDLE窗口。

你有几个选择:

Run the program from an already-open terminal. Open a command prompt and type: python myscript.py For that to work you need the python executable in your path. Just check on how to edit environment variables on Windows, and add C:\PYTHON26 (or whatever directory you installed python to). When the program ends, it'll drop you back to the cmd prompt instead of closing the window. Add code to wait at the end of your script. For Python2, adding ... raw_input() ... at the end of the script makes it wait for the Enter key. That method is annoying because you have to modify the script, and have to remember removing it when you're done. Specially annoying when testing other people's scripts. For Python3, use input(). Use an editor that pauses for you. Some editors prepared for python will automatically pause for you after execution. Other editors allow you to configure the command line it uses to run your program. I find it particularly useful to configure it as "python -i myscript.py" when running. That drops you to a python shell after the end of the program, with the program environment loaded, so you may further play with the variables and call functions and methods.

最简单的方法:

your_code()

while True:
   pass

当您打开窗口时,它不会关闭,直到您关闭提示符。

你可以组合答案之前:(notepad++用户)

按F5运行当前脚本并输入命令:

cmd /k python -i "$(FULL_CURRENT_PATH)"

这样,在执行notepad++ python脚本后,您将保持在交互模式,并且您能够使用您的变量等等:)

在出现异常时保持窗口打开(打印异常时)

Python 2

if __name__ == '__main__':
    try:
        ## your code, typically one function call
    except Exception:
        import sys
        print sys.exc_info()[0]
        import traceback
        print traceback.format_exc()
        print "Press Enter to continue ..." 
        raw_input() 

在任何情况下保持窗户开着:

if __name__ == '__main__':
    try:
        ## your code, typically one function call
    except Exception:
        import sys
        print sys.exc_info()[0]
        import traceback
        print traceback.format_exc()
    finally:
        print "Press Enter to continue ..." 
        raw_input()

Python 3

对于Python3,你必须使用input()来代替raw_input(),当然还要调整print语句。

if __name__ == '__main__':
    try:
        ## your code, typically one function call
    except BaseException:
        import sys
        print(sys.exc_info()[0])
        import traceback
        print(traceback.format_exc())
        print("Press Enter to continue ...")
        input() 

在任何情况下保持窗户开着:

if __name__ == '__main__':
    try:
        ## your code, typically one function call
except BaseException:
    import sys
    print(sys.exc_info()[0])
    import traceback
    print(traceback.format_exc())
finally:
    print("Press Enter to continue ...")
    input()