我刚刚开始学习Python。当我在Windows上执行一个python脚本文件时,输出窗口出现但立即消失。我需要它停留在那里,这样我就可以分析我的输出。我怎么才能让它一直开着?


当前回答

在windows 10上插入以下语句:

#!/usr/bin/env python
# -*- coding: utf-8 -*-

奇怪,但对我很管用!(当然是和input()一起放在末尾)

其他回答

你可以使用-i选项启动python,或者设置环境变量PYTHONINSPECT=x。从文档中可以看出:

运行脚本后进行交互检查;强制执行提示符甚至 如果stdin看起来不是终结符;还PYTHONINSPECT = x

所以当你的脚本崩溃或完成时,你会得到一个python提示符,你的窗口不会关闭。

Go here and download and install Notepad++ Go here and download and install Python 2.7 not 3. Start, Run Powershell. Enter the following. [Environment]::SetEnvironmentVariable("Path", "$env:Path;C:\Python27", "User") Close Powershell and reopen it. Make a directory for your programs. mkdir scripts Open that directory cd scripts In Notepad++, in a new file type: print "hello world" Save the file as hello.py Go back to powershell and make sure you are in the right directory by typing dir. You should see your file hello.py there. At the Powershell prompt type: python hello.py

从已经打开的cmd窗口或启动脚本 在Python 2中,在脚本的末尾添加如下内容:

 raw_input("Press enter to exit;")

或者,在Python 3中:

input("Press enter to exit;")

在出现异常时保持窗口打开(打印异常时)

Python 2

if __name__ == '__main__':
    try:
        ## your code, typically one function call
    except Exception:
        import sys
        print sys.exc_info()[0]
        import traceback
        print traceback.format_exc()
        print "Press Enter to continue ..." 
        raw_input() 

在任何情况下保持窗户开着:

if __name__ == '__main__':
    try:
        ## your code, typically one function call
    except Exception:
        import sys
        print sys.exc_info()[0]
        import traceback
        print traceback.format_exc()
    finally:
        print "Press Enter to continue ..." 
        raw_input()

Python 3

对于Python3,你必须使用input()来代替raw_input(),当然还要调整print语句。

if __name__ == '__main__':
    try:
        ## your code, typically one function call
    except BaseException:
        import sys
        print(sys.exc_info()[0])
        import traceback
        print(traceback.format_exc())
        print("Press Enter to continue ...")
        input() 

在任何情况下保持窗户开着:

if __name__ == '__main__':
    try:
        ## your code, typically one function call
except BaseException:
    import sys
    print(sys.exc_info()[0])
    import traceback
    print(traceback.format_exc())
finally:
    print("Press Enter to continue ...")
    input()

让窗户一直开着的简单方法:

counter = 0

While (True):

    If (counter == 0):

        # Code goes here

    counter += 1

计数器是这样代码就不会重复自己。