我刚刚开始学习Python。当我在Windows上执行一个python脚本文件时,输出窗口出现但立即消失。我需要它停留在那里,这样我就可以分析我的输出。我怎么才能让它一直开着?
当前回答
Go here and download and install Notepad++ Go here and download and install Python 2.7 not 3. Start, Run Powershell. Enter the following. [Environment]::SetEnvironmentVariable("Path", "$env:Path;C:\Python27", "User") Close Powershell and reopen it. Make a directory for your programs. mkdir scripts Open that directory cd scripts In Notepad++, in a new file type: print "hello world" Save the file as hello.py Go back to powershell and make sure you are in the right directory by typing dir. You should see your file hello.py there. At the Powershell prompt type: python hello.py
其他回答
我也遇到过类似的问题。在notepad++中,我曾经使用命令:C:\Python27\python.exe "$(FULL_CURRENT_PATH)"在代码终止后立即关闭cmd窗口。 现在我使用cmd /k c:\Python27\python.exe "$(FULL_CURRENT_PATH)"它保持cmd窗口打开。
创建一个像dontClose()这样的函数或带有while循环的函数:
import time
def dontClose():
n = 1
while n > 0:
n += 1
time.sleep(n)
然后在代码之后运行函数。例如:
print("Hello, World!")
dontClose()
在python 2中,你可以使用:raw_input()
>>print("Hello World!")
>>raw_input('Waiting a key...')
在python 3中,你可以使用:input()
>>print("Hello world!")
>>input('Waiting a key...')
你也可以用时间。sleep(time)
>>import time
>>print("The program will close in 5 seconds")
>>time.sleep(5)
最简单的方法:
import time
#Your code here
time.sleep(60)
#end of code (and console shut down)
这将使代码保持1分钟,然后关闭它。
在出现异常时保持窗口打开(打印异常时)
Python 2
if __name__ == '__main__':
try:
## your code, typically one function call
except Exception:
import sys
print sys.exc_info()[0]
import traceback
print traceback.format_exc()
print "Press Enter to continue ..."
raw_input()
在任何情况下保持窗户开着:
if __name__ == '__main__':
try:
## your code, typically one function call
except Exception:
import sys
print sys.exc_info()[0]
import traceback
print traceback.format_exc()
finally:
print "Press Enter to continue ..."
raw_input()
Python 3
对于Python3,你必须使用input()来代替raw_input(),当然还要调整print语句。
if __name__ == '__main__':
try:
## your code, typically one function call
except BaseException:
import sys
print(sys.exc_info()[0])
import traceback
print(traceback.format_exc())
print("Press Enter to continue ...")
input()
在任何情况下保持窗户开着:
if __name__ == '__main__':
try:
## your code, typically one function call
except BaseException:
import sys
print(sys.exc_info()[0])
import traceback
print(traceback.format_exc())
finally:
print("Press Enter to continue ...")
input()
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