我在谷歌上搜索了很多,找到了很多解决方案,但没有一个能告诉我2012-12-31的正确周数。即使是MSDN上的例子(链接)也失败了。

2012-12-31是星期一,所以应该是第一周,但是我尝试的每一种方法都给了我53。以下是我尝试过的一些方法:

从MDSN库:

DateTimeFormatInfo dfi = DateTimeFormatInfo.CurrentInfo;
Calendar cal = dfi.Calendar;

return cal.GetWeekOfYear(date, dfi.CalendarWeekRule, dfi.FirstDayOfWeek);

解决方案2:

return new GregorianCalendar(GregorianCalendarTypes.Localized).GetWeekOfYear(date, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);

解决方案3:

CultureInfo ciCurr = CultureInfo.CurrentCulture;
int weekNum = ciCurr.Calendar.GetWeekOfYear(dtPassed, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
return weekNum;

更新

当date为2012-12-31时,下面的方法实际返回1。换句话说,我的问题是我的方法没有遵循ISO-8601标准。

// This presumes that weeks start with Monday.
// Week 1 is the 1st week of the year with a Thursday in it.
public static int GetIso8601WeekOfYear(DateTime time)
{
    // Seriously cheat.  If its Monday, Tuesday or Wednesday, then it'll 
    // be the same week# as whatever Thursday, Friday or Saturday are,
    // and we always get those right
    DayOfWeek day = CultureInfo.InvariantCulture.Calendar.GetDayOfWeek(time);
    if (day >= DayOfWeek.Monday && day <= DayOfWeek.Wednesday)
    {
        time = time.AddDays(3);
    }

    // Return the week of our adjusted day
    return CultureInfo.InvariantCulture.Calendar.GetWeekOfYear(time, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
}

当前回答

如果您想要全球化的周数,另一个答案是: 我也把答案贴在这里了

从原来的答案:

基于这个答案:@bunny4

但并不是每个人都在美国,或者可能需要支持多种文化。 使用此解决方案来支持文化定义的周规则和第一天规则。例:丹麦有“一周的头四天”规则,“星期一”是一周的第一天。

//for now, take the the current executing thread's Culture
var cultureInfo = Thread.CurrentThread.CurrentCulture;

//let's pick a date
DateTime dt = new DateTime(2020, 12, 21);

DayOfWeek firstDay = cultureInfo.DateTimeFormat.FirstDayOfWeek;
CalendarWeekRule weekRule = cultureInfo.DateTimeFormat.CalendarWeekRule;
Calendar cal = cultureInfo.Calendar;
int week = cal.GetWeekOfYear(dt, weekRule, firstDay);

其他回答

public int GetWeekNumber()
{
   CultureInfo ciCurr = CultureInfo.CurrentCulture;
   int weekNum = ciCurr.Calendar.GetWeekOfYear(DateTime.Now, 
   CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
   return weekNum;
}

使用c#和DateTime类确定周数ISO 8601样式的最简单方法。

问这个问题:一年的多少个星期四是本周的星期四。 答案等于需要的周数。

var dayOfWeek = (int)moment.DayOfWeek;
// Make monday the first day of the week
if (--dayOfWeek < 0)
    dayOfWeek = 6;
// The whole nr of weeks before this thursday plus one is the week number
var weekNumber = (moment.AddDays(3 - dayOfWeek).DayOfYear - 1) / 7 + 1;

是这样的:

public int GetWeekNumber()
{
    CultureInfo ciCurr = CultureInfo.CurrentCulture;
    int weekNum = ciCurr.Calendar.GetWeekOfYear(DateTime.Now, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
    return weekNum;
}

最重要的是CalendarWeekRule参数。

在这里看到的: https://msdn.microsoft.com/query/dev14.query?appId=Dev14IDEF1&l=IT-IT&k=k (System.Globalization.CalendarWeekRule)、k (TargetFrameworkMoniker -.NETFramework

由于似乎没有. net文化可以产生正确的ISO-8601周数,因此我宁愿完全绕过内置的周数确定,并手动执行计算,而不是试图更正部分正确的结果。

我最终得到了以下扩展方法:

/// <summary>
/// Converts a date to a week number.
/// ISO 8601 week 1 is the week that contains the first Thursday that year.
/// </summary>
public static int ToIso8601Weeknumber(this DateTime date)
{
    var thursday = date.AddDays(3 - date.DayOfWeek.DayOffset());
    return (thursday.DayOfYear - 1) / 7 + 1;
}

/// <summary>
/// Converts a week number to a date.
/// Note: Week 1 of a year may start in the previous year.
/// ISO 8601 week 1 is the week that contains the first Thursday that year, so
/// if December 28 is a Monday, December 31 is a Thursday,
/// and week 1 starts January 4.
/// If December 28 is a later day in the week, week 1 starts earlier.
/// If December 28 is a Sunday, it is in the same week as Thursday January 1.
/// </summary>
public static DateTime FromIso8601Weeknumber(int weekNumber, int? year = null, DayOfWeek day = DayOfWeek.Monday)
{
    var dec28 = new DateTime((year ?? DateTime.Today.Year) - 1, 12, 28);
    var monday = dec28.AddDays(7 * weekNumber - dec28.DayOfWeek.DayOffset());
    return monday.AddDays(day.DayOffset());
}

/// <summary>
/// Iso8601 weeks start on Monday. This returns 0 for Monday.
/// </summary>
private static int DayOffset(this DayOfWeek weekDay)
{
    return ((int)weekDay + 6) % 7;
}

首先,(int)date。DayOfWeek + 6) % 7)决定工作日的数字,0=周一,6=周日。

date.AddDays (- ((int)日期。DayOfWeek + 6) % 7)确定所请求的周数之前的星期一。

三天后是目标星期四,这决定了一周是哪一年。

如果将一年中(以零为基数)的天数除以7(四舍五入),就会得到一年中(以零为基数)的周数。

在c#中,整数计算结果隐式向下舍入。

如果没有。net 5.0,扩展DateTime类以包含周数。

public static class Extension {
    public static int Week(this DateTime date) {
        var day = (int)CultureInfo.CurrentCulture.Calendar.GetDayOfWeek(date);
        return CultureInfo.CurrentCulture.Calendar.GetWeekOfYear(date.AddDays(4 - (day == 0 ? 7 : day)), CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
    }
}