在Java中,可以使用for循环遍历数组中的对象,如下所示:

String[] myStringArray = {"Hello", "World"};
for (String s : myStringArray) {
    // Do something
}

我可以在JavaScript中做同样的事情吗?


当前回答

//Make array
var array = ["1","2","3","4","5","6","7","8","9","10"]
//Loop
for(var i = 0; i < array.length; i++){
 console.log((i+1) + " --> " + array[i])
}

对于i的实际值,如果需要,需要将(i+1)更改为i或(i)。希望这有所帮助。

其他回答

简短回答:是的。你可以这样做:

var myArray = ["element1", "element2", "element3", "element4"];

for (i = 0; i < myArray.length; i++) {
  console.log(myArray[i]);
}

在浏览器控制台中,您可以看到打印的“element1”、“element2”等内容。

在JavaScript中以函数编程方式循环数组的一些用例:

1.只需循环遍历数组

const myArray = [{x:100}, {x:200}, {x:300}];

myArray.forEach((element, index, array) => {
    console.log(element.x); // 100, 200, 300
    console.log(index); // 0, 1, 2
    console.log(array); // same myArray object 3 times
});

注意:严格来说,Array.prototype.forEach()不是一种函数方式,因为它作为输入参数的函数不应该返回值,因此不能将其视为纯函数。

2.检查数组中的任何元素是否通过测试

const people = [
    {name: 'John', age: 23}, 
    {name: 'Andrew', age: 3}, 
    {name: 'Peter', age: 8}, 
    {name: 'Hanna', age: 14}, 
    {name: 'Adam', age: 37}];

const anyAdult = people.some(person => person.age >= 18);
console.log(anyAdult); // true

3.转换为新阵列

const myArray = [{x:100}, {x:200}, {x:300}];

const newArray= myArray.map(element => element.x);
console.log(newArray); // [100, 200, 300]

注意:map()方法使用对调用数组中的每个元素调用所提供函数的结果创建一个新数组。

4.总结某一特定属性,并计算其平均值

const myArray = [{x:100}, {x:200}, {x:300}];

const sum = myArray.map(element => element.x).reduce((a, b) => a + b, 0);
console.log(sum); // 600 = 0 + 100 + 200 + 300

const average = sum / myArray.length;
console.log(average); // 200

5.基于原始数组创建新数组,但不进行修改

const myArray = [{x:100}, {x:200}, {x:300}];

const newArray= myArray.map(element => {
    return {
        ...element,
        x: element.x * 2
    };
});

console.log(myArray); // [100, 200, 300]
console.log(newArray); // [200, 400, 600]

6.统计每个类别的数量

const people = [
    {name: 'John', group: 'A'}, 
    {name: 'Andrew', group: 'C'}, 
    {name: 'Peter', group: 'A'}, 
    {name: 'James', group: 'B'}, 
    {name: 'Hanna', group: 'A'}, 
    {name: 'Adam', group: 'B'}];

const groupInfo = people.reduce((groups, person) => {
    const {A = 0, B = 0, C = 0} = groups;
    if (person.group === 'A') {
        return {...groups, A: A + 1};
    } else if (person.group === 'B') {
        return {...groups, B: B + 1};
    } else {
        return {...groups, C: C + 1};
    }
}, {});

console.log(groupInfo); // {A: 3, C: 1, B: 2}

7.基于特定条件检索数组的子集

const myArray = [{x:100}, {x:200}, {x:300}];

const newArray = myArray.filter(element => element.x > 250);
console.log(newArray); // [{x:300}] 

注意:filter()方法创建一个新数组,其中包含通过所提供函数实现的测试的所有元素。

8.对数组进行排序

const people = [
  { name: "John", age: 21 },
  { name: "Peter", age: 31 },
  { name: "Andrew", age: 29 },
  { name: "Thomas", age: 25 }
];

let sortByAge = people.sort(function (p1, p2) {
  return p1.age - p2.age;
});

console.log(sortByAge);

9.在数组中查找元素

const people = [ {name: "john", age:23},
                {name: "john", age:43},
                {name: "jim", age:101},
                {name: "bob", age:67} ];

const john = people.find(person => person.name === 'john');
console.log(john);

方法返回数组中满足所提供测试函数的第一个元素的值。

工具书类

Array.prototype.some()Array.prototype.forEach()Array.prototype.map()Array.prototype.filter()Array.prototype.sort()Spread语法Array.prototype.find()

优化的方法是缓存数组长度,并使用单变量模式,用一个var关键字初始化所有变量。

var i, max, myStringArray = ["Hello", "World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);

    // Do something
}

如果迭代的顺序无关紧要,那么您应该尝试反向循环。它是最快的,因为它减少了开销条件测试,并且减少了一个声明:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

或者使用while循环更好更干净:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // Do something with fruits[i]
}
var myStringArray = ["hello", "World"];
myStringArray.forEach(function(val, index){
   console.log(val, index);
})

有多种方法可以在javascript中实现。下面是处理数组的常用方法。

方法1:

const students = ["Arun","Jos","John","Kiran"]
for (var index = 0; index < students.length; index++) {
  console.log(students[index]);
}

方法2:

students.forEach((学生,索引)=>console.log(学生));

方法3:

for (const student of students) {
      console.log(student);
}