如果使用jQuery，请尝试$.grep()。

http://api.jquery.com/jquery.grep/

一行回答。 你可以使用过滤函数来得到结果。

Var数组= [ {name:"string 1"， value:"this"， other: "that"}， {name:"string 2"， value:"this"， other: "that"} ]; Console.log (array.filter(function(arr){return arr.name == 'string 1'})[0]);

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

var foundValue = array.filter(obj=>obj.name==='string 1');

console.log(foundValue);

在ES6中，你可以使用Array.prototype。find(predicate, thisArg?)

array.find(x => x.name === 'string 1')

http://exploringjs.com/es6/ch_arrays.html#_searching-for-array-elements https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/find

然后替换该对象(并使用另一个很酷的ES6方法填充)，你可以这样做:

let obj = array.find(x => x.name === 'string 1');
let index = array.indexOf(obj);
array.fill(obj.name='some new string', index, index++);

与之前的答案类似，我使用了以下答案:

    Array.prototype.getIemtByParam = function(paramPair) {
      var key = Object.keys(paramPair)[0];
      return this.find(function(item){return ((item[key] == paramPair[key]) ? true: false)});
    }

用法:

myArray.getIemtByParam(
    {name: 'Sasha'}
);

你可以使用npm中的查询对象。您可以使用筛选器搜索对象数组。

const queryable = require('query-objects');

const users = [
    {
      firstName: 'George',
      lastName: 'Eracleous',
      age: 28
    },
    {
      firstName: 'Erica',
      lastName: 'Archer',
      age: 50
    },
    {
      firstName: 'Leo',
      lastName: 'Andrews',
      age: 20
    }
];

const filters = [
    {
      field: 'age',
      value: 30,
      operator: 'lt'
    },
    {
      field: 'firstName',
      value: 'Erica',
      operator: 'equals'
    }
];

// Filter all users that are less than 30 years old AND their first name is Erica
const res = queryable(users).and(filters);

// Filter all users that are less than 30 years old OR their first name is Erica
const res = queryable(users).or(filters);