我知道以前也有人问过类似的问题，但这个问题有点不同。我有一个未命名对象的数组，其中包含一个命名对象的数组，我需要得到其中“name”为“string 1”的对象。下面是一个示例数组。
var array = [
{ name:"string 1", value:"this", other: "that" },
{ name:"string 2", value:"this", other: "that" }
];
更新:我应该早点说，但一旦我找到它，我想用一个编辑过的对象替换它。
当前回答
一行回答。 你可以使用过滤函数来得到结果。
Var数组= [ {name:"string 1"， value:"this"， other: "that"}， {name:"string 2"， value:"this"， other: "that"} ]; Console.log (array.filter(function(arr){return arr.name == 'string 1'})[0]);
其他回答
你可以使用npm中的查询对象。您可以使用筛选器搜索对象数组。
const queryable = require('query-objects');
const users = [
{
firstName: 'George',
lastName: 'Eracleous',
age: 28
},
{
firstName: 'Erica',
lastName: 'Archer',
age: 50
},
{
firstName: 'Leo',
lastName: 'Andrews',
age: 20
}
];
const filters = [
{
field: 'age',
value: 30,
operator: 'lt'
},
{
field: 'firstName',
value: 'Erica',
operator: 'equals'
}
];
// Filter all users that are less than 30 years old AND their first name is Erica
const res = queryable(users).and(filters);
// Filter all users that are less than 30 years old OR their first name is Erica
const res = queryable(users).or(filters);
您是否在对象列表中查找跨项目的通用搜索(筛选器)而不指定项目键
输入
var productList = [{category: 'Sporting Goods', price: '$49.99', stocked: true, name: 'Football'}, {category: 'Sporting Goods', price: '$9.99', stocked: true, name: 'Baseball'}, {category: 'Sporting Goods', price: '$29.99', stocked: false, name: 'Basketball'}, {category: 'Electronics', price: '$99.99', stocked: true, name: 'iPod Touch'}, {category: 'Electronics', price: '$399.99', stocked: false, name: 'iPhone 5'}, {category: 'Electronics', price: '$199.99', stocked: true, name: 'Nexus 7'}]
function customFilter(objList, text){
if(undefined === text || text === '' ) return objList;
return objList.filter(product => {
let flag;
for(let prop in product){
flag = false;
flag = product[prop].toString().indexOf(text) > -1;
if(flag)
break;
}
return flag;
});}
执行
customFilter(productList, '$9');
用foreach:
let itemYouWant = null;
array.forEach((item) => {
if (item.name === 'string 1') {
itemYouWant = item;
}
});
console.log(itemYouWant);
如果有地图就更好了:
const itemYouWant = array.map((item) => {
if (item.name === 'string 1') {
return item;
}
return null;
});
console.log(itemYouWant);
另一种方法(帮助@NullUserException和@Wexoni的注释)是在数组中检索对象的索引，然后从那里开始:
var index = array.map(function(obj){ return obj.name; }).indexOf('name-I-am-looking-for');
// Then we can access it to do whatever we want
array[index] = {name: 'newName', value: 'that', other: 'rocks'};
根据ECMAScript 6，您可以使用findIndex函数。
array[array.findIndex(x => x.name == 'string 1')]
