我如何才能改变我的DateTime变量“s”的时间?
DateTime s = some datetime;
我如何才能改变我的DateTime变量“s”的时间?
DateTime s = some datetime;
当前回答
Using an extencion to DateTime:
public enum eTimeFragment
{
hours,
minutes,
seconds,
milliseconds
}
public static DateTime ClearTimeFrom(this DateTime dateToClear, eTimeFragment etf)
{
DateTime dtRet = dateToClear;
switch (etf)
{
case eTimeFragment.hours:
dtRet = dateToClear.Date;
break;
case eTimeFragment.minutes:
dtRet = dateToClear.AddMinutes(dateToClear.Minute * -1);
dtRet = dtRet.ClearTimeFrom(eTimeFragment.seconds);
break;
case eTimeFragment.seconds:
dtRet = dateToClear.AddSeconds(dateToClear.Second * -1);
dtRet = dtRet.ClearTimeFrom(eTimeFragment.milliseconds);
break;
case eTimeFragment.milliseconds:
dtRet = dateToClear.AddMilliseconds(dateToClear.Millisecond * -1);
break;
}
return dtRet;
}
像这样使用:
游戏机。WriteLine (DateTime。Now ClearTimeFrom (eTimeFragment时间)。
这个必须返回: 2016-06-06 00:00:00.000
其他回答
我刚刚遇到这篇文章,因为我有一个类似的问题,我想在MVC中为一个实体框架对象设置时间,从视图(datepicker)中获取日期,所以时间组件是00:00:00,但我需要它是当前时间。根据这篇文章中的回答,我想出了:
myEntity.FromDate += DateTime.Now.TimeOfDay;
这难道不能解决你的问题吗?
Dateime dt = DateTime.Now;
dt = dt.AddSeconds(10);
碰巧看到这篇文章,因为我正在寻找相同的功能,这可能会做什么人想要的。取原日期,更换时间部分
DateTime dayOpen = DateTime.Parse(processDay.ToShortDateString() + " 05:00 AM");
DateTime ts = DateTime.Now;
ts = new DateTime ( ts.Year, ts.Month, ts.Day, 0, 0, 0 ) ;
Console.WriteLine ( "Today = " + ts.ToString("M/dd/yy HH:mm:ss") ) ;
执行: 今天= 9/04/15 00:00:00
//The fastest way to copy time
DateTime justDate = new DateTime(2011, 1, 1); // 1/1/2011 12:00:00AM the date you will be adding time to, time ticks = 0
DateTime timeSource = new DateTime(1999, 2, 4, 10, 15, 30); // 2/4/1999 10:15:30AM - time tick = x
justDate = new DateTime(justDate.Date.Ticks + timeSource.TimeOfDay.Ticks);
Console.WriteLine(justDate); // 1/1/2011 10:15:30AM
Console.Read();