对上面答案的改进，原因如下:

Code should be as self-explanatory as possible. Enumerating over an array using for...in... should be avoided. for...in... enumeration should be validated to ensure the object's being enumerated over contains the property you're looking for. As JavaScript is loosely typed and the for...in... can be handed any arbitrary object to handle; it's safer to validate the property we're looking for is available. var os = require('os'), interfaces = os.networkInterfaces(), address, addresses = [], i, l, interfaceId, interfaceArray; for (interfaceId in interfaces) { if (interfaces.hasOwnProperty(interfaceId)) { interfaceArray = interfaces[interfaceId]; l = interfaceArray.length; for (i = 0; i < l; i += 1) { address = interfaceArray[i]; if (address.family === 'IPv4' && !address.internal) { addresses.push(address.address); } } } } console.log(addresses);

这是对已接受答案的修改，它不考虑vEthernet IP地址，如Docker等。

/**
 * Get local IP address, while ignoring vEthernet IP addresses (like from Docker, etc.)
 */
let localIP;
var os = require('os');
var ifaces = os.networkInterfaces();
Object.keys(ifaces).forEach(function (ifname) {
   var alias = 0;

   ifaces[ifname].forEach(function (iface) {
      if ('IPv4' !== iface.family || iface.internal !== false) {
         // Skip over internal (i.e. 127.0.0.1) and non-IPv4 addresses
         return;
      }

      if(ifname === 'Ethernet') {
         if (alias >= 1) {
            // This single interface has multiple IPv4 addresses
            // console.log(ifname + ':' + alias, iface.address);
         } else {
            // This interface has only one IPv4 address
            // console.log(ifname, iface.address);
         }
         ++alias;
         localIP = iface.address;
      }
   });
});
console.log(localIP);

这将返回一个类似192.168.2.169的IP地址，而不是10.55.1.1。

如果你不想安装依赖，并且正在运行*nix系统，你可以这样做:

hostname -I

你会得到主机的所有地址，你可以在node中使用这个字符串:

const exec = require('child_process').exec;
let cmd = "hostname -I";
exec(cmd, function(error, stdout, stderr)
{
  console.log(stdout + error + stderr);
});

是一行代码，你不需要像'os'或'node-ip'这样可能会意外增加代码复杂性的其他库。

hostname -h

也是你的朋友;-)

希望能有所帮助!

一行程序只用于macOS的第一个本地主机地址。

当在macOS上开发应用程序时，你想在手机上测试它，并且需要你的应用程序自动选择本地主机IP地址。

require('os').networkInterfaces().en0.find(elm => elm.family=='IPv4').address

这只是提到如何自动查找ip地址。 要测试这个，你可以去终端点击

node
os.networkInterfaces().en0.find(elm => elm.family=='IPv4').address

输出将是您的本地主机IP地址。

这些信息可以在os.networkInterfaces()中找到，这是一个对象，它将网络接口名称映射到它的属性(例如，一个接口可以有几个地址):

'use strict';

const { networkInterfaces } = require('os');

const nets = networkInterfaces();
const results = Object.create(null); // Or just '{}', an empty object

for (const name of Object.keys(nets)) {
    for (const net of nets[name]) {
        // Skip over non-IPv4 and internal (i.e. 127.0.0.1) addresses
        // 'IPv4' is in Node <= 17, from 18 it's a number 4 or 6
        const familyV4Value = typeof net.family === 'string' ? 'IPv4' : 4
        if (net.family === familyV4Value && !net.internal) {
            if (!results[name]) {
                results[name] = [];
            }
            results[name].push(net.address);
        }
    }
}

// 'results'
{
  "en0": [
    "192.168.1.101"
  ],
  "eth0": [
    "10.0.0.101"
  ],
  "<network name>": [
    "<ip>",
    "<ip alias>",
    "<ip alias>",
    ...
  ]
}

// results["en0"][0]
"192.168.1.101"

下面是前面例子的一个变种。它会小心过滤掉VMware接口等。如果你不传递索引，它会返回所有地址。否则，您可能希望将其默认值设置为0，然后传递null以获取所有值，但您将整理这些。如果想要添加的话，还可以为regex过滤器传入另一个参数。

function getAddress(idx) {

    var addresses = [],
        interfaces = os.networkInterfaces(),
        name, ifaces, iface;

    for (name in interfaces) {
        if(interfaces.hasOwnProperty(name)){
            ifaces = interfaces[name];
            if(!/(loopback|vmware|internal)/gi.test(name)){
                for (var i = 0; i < ifaces.length; i++) {
                    iface = ifaces[i];
                    if (iface.family === 'IPv4' &&  !iface.internal && iface.address !== '127.0.0.1') {
                        addresses.push(iface.address);
                    }
                }
            }
        }
    }

    // If an index is passed only return it.
    if(idx >= 0)
        return addresses[idx];
    return addresses;
}