string -> []byte用于将字符串转换为字节切片:

[]byte(str)

将数组转换为切片，使用[20]byte -> []byte:

arr[:]

将字符串复制到数组，使用string -> [20]byte:

copy(arr[:], str)

与上面相同，但首先显式地将字符串转换为slice:

copy(arr[:], []byte(str))

The built-in copy function only copies to a slice, from a slice. Arrays are "the underlying data", while slices are "a viewport into underlying data". Using [:] makes an array qualify as a slice. A string does not qualify as a slice that can be copied to, but it qualifies as a slice that can be copied from (strings are immutable). If the string is too long, copy will only copy the part of the string that fits (and multi-byte runes may then be copied only partly, which will corrupt the last rune of the resulting string).

这段代码:

var arr [20]byte
copy(arr[:], "abc")
fmt.Printf("array: %v (%T)\n", arr, arr)

.．.给出如下输出:

array: [97 98 99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] ([20]uint8)

我还在围棋游乐场提供了它

除了上面提到的方法，你还可以做一个小技巧

s := "hello"
b := *(*[]byte)(unsafe.Pointer((*reflect.SliceHeader)(unsafe.Pointer(&s))))

Go Play: http://play.golang.org/p/xASsiSpQmC

你不应该使用这个:-)

string -> []byte用于将字符串转换为字节切片:

[]byte(str)

将数组转换为切片，使用[20]byte -> []byte:

arr[:]

将字符串复制到数组，使用string -> [20]byte:

copy(arr[:], str)

与上面相同，但首先显式地将字符串转换为slice:

copy(arr[:], []byte(str))

The built-in copy function only copies to a slice, from a slice. Arrays are "the underlying data", while slices are "a viewport into underlying data". Using [:] makes an array qualify as a slice. A string does not qualify as a slice that can be copied to, but it qualifies as a slice that can be copied from (strings are immutable). If the string is too long, copy will only copy the part of the string that fits (and multi-byte runes may then be copied only partly, which will corrupt the last rune of the resulting string).

这段代码:

var arr [20]byte
copy(arr[:], "abc")
fmt.Printf("array: %v (%T)\n", arr, arr)

.．.给出如下输出:

array: [97 98 99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] ([20]uint8)

我还在围棋游乐场提供了它

将字符串转换为字节片

您需要一种快速的方法将[]字符串转换为[]字节类型。用于将文本数据存储到随机访问文件或要求输入数据为[]字节类型的其他类型的数据操作等情况。

package main

func main() {

    var s string

    //...

    b := []byte(s)

    //...
}

这在使用ioutil时很有用。WriteFile，它接受字节片作为它的数据参数:

WriteFile func(filename string, data []byte, perm os.FileMode) error

另一个例子

package main

import (
    "fmt"
    "strings"
)

func main() {

    stringSlice := []string{"hello", "world"}

    stringByte := strings.Join(stringSlice, " ")

    // Byte array value
    fmt.Println([]byte(stringByte))

    // Corresponding string value
    fmt.Println(string([]byte(stringByte)))
}

输出:

你好，世界

请检查链接操场

最终创建了特定于数组的方法来实现这一点。很像每个int类型都有特定方法的编码/二进制包。例如binary.BigEndian。uint16 PutUint16([]字节)。

func byte16PutString(s string) [16]byte {
    var a [16]byte
    if len(s) > 16 {
        copy(a[:], s)
    } else {
        copy(a[16-len(s):], s)
    }
    return a
}

var b [16]byte
b = byte16PutString("abc")
fmt.Printf("%v\n", b)

输出:

[0 0 0 0 0 0 0 0 0 0 0 0 0 97 98 99]

请注意，我希望填充在左边，而不是右边。

http://play.golang.org/p/7tNumnJaiN

小菜一碟:

arr := []byte("That's all folks!!")