我想把字符串赋值给bytes数组:
var arr [20]byte
str := "abc"
for k, v := range []byte(str) {
arr[k] = byte(v)
}
还有别的方法吗?
我想把字符串赋值给bytes数组:
var arr [20]byte
str := "abc"
for k, v := range []byte(str) {
arr[k] = byte(v)
}
还有别的方法吗?
当前回答
除了上面提到的方法,你还可以做一个小技巧
s := "hello"
b := *(*[]byte)(unsafe.Pointer((*reflect.SliceHeader)(unsafe.Pointer(&s))))
Go Play: http://play.golang.org/p/xASsiSpQmC
你不应该使用这个:-)
其他回答
string -> []byte用于将字符串转换为字节切片:
[]byte(str)
将数组转换为切片,使用[20]byte -> []byte:
arr[:]
将字符串复制到数组,使用string -> [20]byte:
copy(arr[:], str)
与上面相同,但首先显式地将字符串转换为slice:
copy(arr[:], []byte(str))
The built-in copy function only copies to a slice, from a slice. Arrays are "the underlying data", while slices are "a viewport into underlying data". Using [:] makes an array qualify as a slice. A string does not qualify as a slice that can be copied to, but it qualifies as a slice that can be copied from (strings are immutable). If the string is too long, copy will only copy the part of the string that fits (and multi-byte runes may then be copied only partly, which will corrupt the last rune of the resulting string).
这段代码:
var arr [20]byte
copy(arr[:], "abc")
fmt.Printf("array: %v (%T)\n", arr, arr)
...给出如下输出:
array: [97 98 99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] ([20]uint8)
我还在围棋游乐场提供了它
除了上面提到的方法,你还可以做一个小技巧
s := "hello"
b := *(*[]byte)(unsafe.Pointer((*reflect.SliceHeader)(unsafe.Pointer(&s))))
Go Play: http://play.golang.org/p/xASsiSpQmC
你不应该使用这个:-)
例如,
package main
import "fmt"
func main() {
s := "abc"
var a [20]byte
copy(a[:], s)
fmt.Println("s:", []byte(s), "a:", a)
}
输出:
s: [97 98 99] a: [97 98 99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
小菜一碟:
arr := []byte("That's all folks!!")
我认为这样更好。
package main
import "fmt"
func main() {
str := "abc"
mySlice := []byte(str)
fmt.Printf("%v -> '%s'",mySlice,mySlice )
}
点击这里查看:http://play.golang.org/p/vpnAWHZZk7