我有一个Rakefile以两种方式编译项目，根据全局变量$build_type，它可以是:debug或:release(结果在单独的目录中):
task :build => [:some_other_tasks] do
end
我想创建一个任务，编译项目的两个配置依次，像这样:
task :build_all do
[ :debug, :release ].each do |t|
$build_type = t
# call task :build with all the tasks it depends on (?)
end
end
是否有一种方法可以像调用方法一样调用任务?或者我怎样才能实现类似的目标?
当前回答
task :build_all do
[ :debug, :release ].each do |t|
$build_type = t
Rake::Task["build"].reenable
Rake::Task["build"].invoke
end
end
这应该能解决你的问题，我也需要一样的东西。
其他回答
task :build_all do
[ :debug, :release ].each do |t|
$build_type = t
Rake::Task["build"].execute
end
end
例如:
Rake::Task["db:migrate"].invoke
task :build_all do
[ :debug, :release ].each do |t|
$build_type = t
Rake::Task["build"].reenable
Rake::Task["build"].invoke
end
end
这应该能解决你的问题，我也需要一样的东西。
如果您需要将任务作为一个方法来执行，那么使用一个实际的方法如何?
task :build => [:some_other_tasks] do
build
end
task :build_all do
[:debug, :release].each { |t| build t }
end
def build(type = :debug)
# ...
end
如果你更愿意坚持rake的习语，下面是你从过去的答案中编译出来的可能性:
This always executes the task, but it doesn't execute its dependencies: Rake::Task["build"].execute This one executes the dependencies, but it only executes the task if it has not already been invoked: Rake::Task["build"].invoke This first resets the task's already_invoked state, allowing the task to then be executed again, dependencies and all: Rake::Task["build"].reenable Rake::Task["build"].invoke Note that dependencies already invoked are not automatically re-executed unless they are re-enabled. In Rake >= 10.3.2, you can use the following to re-enable those as well: Rake::Task["build"].all_prerequisite_tasks.each(&:reenable)
task :invoke_another_task do
# some code
Rake::Task["another:task"].invoke
end
