I am opening a file which has 100,000 URL's. I need to send an HTTP request to each URL and print the status code. I am using Python 2.6, and so far looked at the many confusing ways Python implements threading/concurrency. I have even looked at the python concurrence library, but cannot figure out how to write this program correctly. Has anyone come across a similar problem? I guess generally I need to know how to perform thousands of tasks in Python as fast as possible - I suppose that means 'concurrently'.
当前回答
线程绝对不是这里的答案。它们将提供进程和内核瓶颈,以及吞吐量限制,如果总体目标是“最快的方式”,这些限制是不可接受的。
稍微扭曲一点,它的异步HTTP客户端会给你更好的结果。
其他回答
这个扭曲的异步web客户端运行得相当快。
#!/usr/bin/python2.7
from twisted.internet import reactor
from twisted.internet.defer import Deferred, DeferredList, DeferredLock
from twisted.internet.defer import inlineCallbacks
from twisted.web.client import Agent, HTTPConnectionPool
from twisted.web.http_headers import Headers
from pprint import pprint
from collections import defaultdict
from urlparse import urlparse
from random import randrange
import fileinput
pool = HTTPConnectionPool(reactor)
pool.maxPersistentPerHost = 16
agent = Agent(reactor, pool)
locks = defaultdict(DeferredLock)
codes = {}
def getLock(url, simultaneous = 1):
return locks[urlparse(url).netloc, randrange(simultaneous)]
@inlineCallbacks
def getMapping(url):
# Limit ourselves to 4 simultaneous connections per host
# Tweak this number, but it should be no larger than pool.maxPersistentPerHost
lock = getLock(url,4)
yield lock.acquire()
try:
resp = yield agent.request('HEAD', url)
codes[url] = resp.code
except Exception as e:
codes[url] = str(e)
finally:
lock.release()
dl = DeferredList(getMapping(url.strip()) for url in fileinput.input())
dl.addCallback(lambda _: reactor.stop())
reactor.run()
pprint(codes)
对于您的情况,线程可能会做的技巧,因为您可能会花费大部分时间等待响应。标准库中有一些有用的模块,如Queue,可能会有所帮助。
我以前做过类似的并行下载文件的事情,对我来说已经足够好了,但它不是你所说的那种规模。
如果您的任务对cpu的限制更大,您可能需要考虑multiprocessing模块,它将允许您利用更多的cpu /内核/线程(更多的进程不会相互阻塞,因为锁定是每个进程)
一个解决方案:
from twisted.internet import reactor, threads
from urlparse import urlparse
import httplib
import itertools
concurrent = 200
finished=itertools.count(1)
reactor.suggestThreadPoolSize(concurrent)
def getStatus(ourl):
url = urlparse(ourl)
conn = httplib.HTTPConnection(url.netloc)
conn.request("HEAD", url.path)
res = conn.getresponse()
return res.status
def processResponse(response,url):
print response, url
processedOne()
def processError(error,url):
print "error", url#, error
processedOne()
def processedOne():
if finished.next()==added:
reactor.stop()
def addTask(url):
req = threads.deferToThread(getStatus, url)
req.addCallback(processResponse, url)
req.addErrback(processError, url)
added=0
for url in open('urllist.txt'):
added+=1
addTask(url.strip())
try:
reactor.run()
except KeyboardInterrupt:
reactor.stop()
Testtime:
[kalmi@ubi1:~] wc -l urllist.txt
10000 urllist.txt
[kalmi@ubi1:~] time python f.py > /dev/null
real 1m10.682s
user 0m16.020s
sys 0m10.330s
[kalmi@ubi1:~] head -n 6 urllist.txt
http://www.google.com
http://www.bix.hu
http://www.godaddy.com
http://www.google.com
http://www.bix.hu
http://www.godaddy.com
[kalmi@ubi1:~] python f.py | head -n 6
200 http://www.bix.hu
200 http://www.bix.hu
200 http://www.bix.hu
200 http://www.bix.hu
200 http://www.bix.hu
200 http://www.bix.hu
Pingtime:
bix.hu is ~10 ms away from me
godaddy.com: ~170 ms
google.com: ~30 ms
使用线程池是一个很好的选择,这将使这相当容易。不幸的是,python并没有一个标准库来简化线程池。但这里有一个不错的图书馆,你应该开始: http://www.chrisarndt.de/projects/threadpool/
来自他们网站的代码示例:
pool = ThreadPool(poolsize)
requests = makeRequests(some_callable, list_of_args, callback)
[pool.putRequest(req) for req in requests]
pool.wait()
希望这能有所帮助。
Twistedless解决方案:
from urlparse import urlparse
from threading import Thread
import httplib, sys
from Queue import Queue
concurrent = 200
def doWork():
while True:
url = q.get()
status, url = getStatus(url)
doSomethingWithResult(status, url)
q.task_done()
def getStatus(ourl):
try:
url = urlparse(ourl)
conn = httplib.HTTPConnection(url.netloc)
conn.request("HEAD", url.path)
res = conn.getresponse()
return res.status, ourl
except:
return "error", ourl
def doSomethingWithResult(status, url):
print status, url
q = Queue(concurrent * 2)
for i in range(concurrent):
t = Thread(target=doWork)
t.daemon = True
t.start()
try:
for url in open('urllist.txt'):
q.put(url.strip())
q.join()
except KeyboardInterrupt:
sys.exit(1)
这个方案比twisted方案稍微快一点,并且使用更少的CPU。
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