我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;
当前的
Str = 'MyLongString:StringIWant;'
期望输出值
newStr = 'StringIWant'
我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;
当前的
Str = 'MyLongString:StringIWant;'
期望输出值
newStr = 'StringIWant'
当前回答
获取两个子字符串之间的字符串(包含多于1个字符)
function substrInBetween(whole_str, str1, str2){
if (whole_str.indexOf(str1) === -1 || whole_str.indexOf(str2) === -1) {
return undefined; // or ""
}
var strlength1 = str1.length;
return whole_str.substring(
whole_str.indexOf(str1) + strlength1,
whole_str.indexOf(str2)
);
}
注意,我使用indexOf()而不是lastIndexOf(),因此它将检查这些字符串的第一次出现
其他回答
尝试使用javascript在两个字符之间获取子字符串。
$("button").click(function(){
var myStr = "MyLongString:StringIWant;";
var subStr = myStr.match(":(.*);");
alert(subStr[1]);
});
从@ Find子字符串之间的两个字符与jQuery
var str = '[basic_salary]+100/[basic_salary]';
var arr = str.split('');
var myArr = [];
for(var i=0;i<arr.length;i++){
if(arr[i] == '['){
var a = '';
for(var j=i+1;j<arr.length;j++){
if(arr[j] == ']'){
var i = j-1;
break;
}else{
a += arr[j];
}
}
myArr.push(a);
}
var operatorsArr = ['+','-','*','/','%'];
if(operatorsArr.includes(arr[i])){
myArr.push(arr[i]);
}
var numbArr = ['0','1','2','3','4','5','6','7','8','9'];
if(numbArr.includes(arr[i])){
var a = '';
for(var j=i;j<arr.length;j++){
if(numbArr.includes(arr[j])){
a += arr[j];
}else{
var i = j-1;
break;
}
}
myArr.push(a);
}
}
myArr = ["basic_salary", "+", "100", "/", "basic_salary"]
使用分割()
var s = 'MyLongString:StringIWant;';
var arrStr = s.split(/[:;]/);
alert(arrStr);
arrStr将包含所有由:或; 通过for循环访问每个字符串
for(var i=0; i<arrStr.length; i++)
alert(arrStr[i]);
您可以使用这个函数-
function getStringInBetween(string, start , end) {
// start and end will be excluded
var indexOfStart = string.indexOf(start)
indexOfStart = indexOfStart + start.length;
var newString = string.slice(indexOfStart)
var indexOfEnd = newString.indexOf(end)
return newString.slice(0, indexOfEnd)
}
对于前-
let string = "<div class = 'mice'> I know how to code </div>"
let start = "<div class = 'mice'> "
let end = " </div>"
//then, getStringInBetween(string, start, end) returns "I know how to code"
你可以试试这个
var mySubString = str.substring(
str.indexOf(":") + 1,
str.lastIndexOf(";")
);