我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;
当前的
Str = 'MyLongString:StringIWant;'
期望输出值
newStr = 'StringIWant'
我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;
当前的
Str = 'MyLongString:StringIWant;'
期望输出值
newStr = 'StringIWant'
当前回答
使用分割()
var s = 'MyLongString:StringIWant;';
var arrStr = s.split(/[:;]/);
alert(arrStr);
arrStr将包含所有由:或; 通过for循环访问每个字符串
for(var i=0; i<arrStr.length; i++)
alert(arrStr[i]);
其他回答
var str = '[basic_salary]+100/[basic_salary]';
var arr = str.split('');
var myArr = [];
for(var i=0;i<arr.length;i++){
if(arr[i] == '['){
var a = '';
for(var j=i+1;j<arr.length;j++){
if(arr[j] == ']'){
var i = j-1;
break;
}else{
a += arr[j];
}
}
myArr.push(a);
}
var operatorsArr = ['+','-','*','/','%'];
if(operatorsArr.includes(arr[i])){
myArr.push(arr[i]);
}
var numbArr = ['0','1','2','3','4','5','6','7','8','9'];
if(numbArr.includes(arr[i])){
var a = '';
for(var j=i;j<arr.length;j++){
if(numbArr.includes(arr[j])){
a += arr[j];
}else{
var i = j-1;
break;
}
}
myArr.push(a);
}
}
myArr = ["basic_salary", "+", "100", "/", "basic_salary"]
function substringBetween(s, a, b) {
var p = s.indexOf(a) + a.length;
return s.substring(p, s.indexOf(b, p));
}
// substringBetween('MyLongString:StringIWant;', ':', ';') -> StringIWant
// substringBetween('MyLongString:StringIWant;;', ':', ';') -> StringIWant
// substringBetween('MyLongString:StringIWant;:StringIDontWant;', ':', ';') -> StringIWant
这是我刚做的东西。
注意,如果在启动后没有找到end,函数将返回启动后的所有内容。它还期望只有一次出现的开始和结束,如果有多次,它将只考虑第一次。
许可:公共领域
/**
* Extracts a string from `source` that is placed between `start` and `end`. The function
* considers only one instance of start and before, or the first instance and does not support
* multiple occurences otherwise. If end string is not found, it will return everything after
* `start` to the end of the string.
*/
export function stringBetween(source, start, end) {
if (source.indexOf(start) === -1) {
return null;
}
const sourceSplitByStartString = source.split(start);
// Note: If start string is the very first occurence in source string, the result will be an
// array where the first item is an empty string and the next item is of interest.
if (
sourceSplitByStartString.length === 1
|| sourceSplitByStartString[1] === ''
) {
// It means that start is either the entire string or is at the very end of the string, so there
// is not anything between
return '';
}
const afterStart = sourceSplitByStartString[1];
// If the after separator is not found, return everything after the start separator to the end
// of the string
if (afterStart.indexOf(end) === -1) {
return afterStart;
}
const afterStartSplitByEnd = afterStart.split(end);
if (afterStartSplitByEnd[0] === '') {
return '';
}
return afterStartSplitByEnd[0];
}
测试:
import { stringBetween } from './string';
describe('string utlities', () => {
describe('stringBetween', () => {
it('Extracts a substring between 2 other substrings', () => {
const sample1 = stringBetween('Black cat climbed the tree fast.', 'cat ', ' the tree');
expect(sample1).toBe('climbed');
const sample2 = stringBetween('Black cat climbed the tree fast.', 'Black ', ' fast.');
expect(sample2).toBe('cat climbed the tree');
});
it('extracts everything after start if end is not found', () => {
const sample2 = stringBetween('Black cat climbed the tree fast.', 'Black ', 'not-there');
expect(sample2).toBe('cat climbed the tree fast.');
});
it('returns empty string if start string occurs at the end', () => {
const sample = stringBetween('Black cat climbed the tree fast.', 'fast.', 'climbed');
expect(sample).toBe('');
});
it('returns empty string if start string is the entire string', () => {
const sample = stringBetween('Black cat', 'Black cat', 'climbed');
expect(sample).toBe('');
});
it('returns empty string if there is not anything between start and end', () => {
const sample = stringBetween('Black cat climbed the tree fast.', 'climbed ', 'the tree');
expect(sample).toBe('');
});
it('returns null if start string does not exist in the source string', () => {
const sample = stringBetween('Black cat climbed the tree fast.', 'not-there ', 'the tree');
expect(sample).toBe(null);
});
});
});
上面的代码适用于简单的例子,但可以帮助… 使用打印稿。
参数
句子:你想要得到部分的字符串 第一个:开头字符(对于初始示例,它将是:) 最后:你的部分的最后一个字符(对于初始示例,它将是;)
输出
字符串数组(string[])。如果句子中没有好的部分,则返回[]。
Code
function getParts(sentence: string, first: string, last: string): string[] {
let goodParts: string[] = [];
const allParts = sentence.split(first);
allParts.forEach((part: string) => {
if (part.indexOf(last) > -1) {
const goodOne = (part.split(last))[0];
goodParts = goodParts.concat(goodOne);
}
});
return goodParts;
}
例子
const origin = "wrongString1:rightString1;wrongString2:rightString2;wrongString3:rightString3;wrongString4:rightString4;";
const result = getParts(origin, ':', ';');
console.log(result);
// ["rightString1", "rightString2", "rightString3", "rightString4"]
如果您想从一个字符串中提取发生在两个分隔符(不同或相同)之间的所有子字符串,可以使用此函数。它返回一个包含所有子字符串的数组:
function get_substrings_between(str, startDelimiter, endDelimiter)
{
var contents = [];
var startDelimiterLength = startDelimiter.length;
var endDelimiterLength = endDelimiter.length;
var startFrom = contentStart = contentEnd = 0;
while(false !== (contentStart = strpos(str, startDelimiter, startFrom)))
{
contentStart += startDelimiterLength;
contentEnd = strpos(str, endDelimiter, contentStart);
if(false === contentEnd)
{
break;
}
contents.push( str.substr(contentStart, contentEnd - contentStart) );
startFrom = contentEnd + endDelimiterLength;
}
return contents;
}
// https://stackoverflow.com/a/3978237/1066234
function strpos(haystack, needle, offset)
{
var i = (haystack+'').indexOf(needle, (offset || 0));
return i === -1 ? false : i;
}
// Example usage
var string = "We want to extract all infos (essential ones) from within the brackets (this should be fun).";
var extracted = get_substrings_between(string, '(', ')');
console.log(extracted);
// output: (2) ["essential ones", "this should be fun"]
最初从PHP由raina77ow,移植到Javascript。