我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;
当前的
Str = 'MyLongString:StringIWant;'
期望输出值
newStr = 'StringIWant'
我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;
当前的
Str = 'MyLongString:StringIWant;'
期望输出值
newStr = 'StringIWant'
当前回答
获取所有子字符串。
var out = []; 'MyLongString:StringIWant;'
.replace(/(:)\w+(;)+/g, (e) => {
out.push(e.replace(':', '').replace(';', ''))
return e;
});
console.log(out[0])
其他回答
var str = '[basic_salary]+100/[basic_salary]';
var arr = str.split('');
var myArr = [];
for(var i=0;i<arr.length;i++){
if(arr[i] == '['){
var a = '';
for(var j=i+1;j<arr.length;j++){
if(arr[j] == ']'){
var i = j-1;
break;
}else{
a += arr[j];
}
}
myArr.push(a);
}
var operatorsArr = ['+','-','*','/','%'];
if(operatorsArr.includes(arr[i])){
myArr.push(arr[i]);
}
var numbArr = ['0','1','2','3','4','5','6','7','8','9'];
if(numbArr.includes(arr[i])){
var a = '';
for(var j=i;j<arr.length;j++){
if(numbArr.includes(arr[j])){
a += arr[j];
}else{
var i = j-1;
break;
}
}
myArr.push(a);
}
}
myArr = ["basic_salary", "+", "100", "/", "basic_salary"]
下面的函数获取第一个匹配项
function getStringBetween(x: string, start: string, end: string) {
const regex = new RegExp(`${start}(.*?)${end}`)
if (regex.test(x)) {
return regex.exec(x)![1]
} else return undefined
}
有测试
test("getStringBetween", () => {
const result = getStringBetween("<em> Jai Ram</em>", "<em>", "</em>")
expect(result).toEqual(" Jai Ram")
const result1 = getStringBetween(
"hare Jai Ram hare hare hare",
"hare",
"hare"
)
expect(result1).toEqual(" Jai Ram ")
})
function substringBetween(s, a, b) {
var p = s.indexOf(a) + a.length;
return s.substring(p, s.indexOf(b, p));
}
// substringBetween('MyLongString:StringIWant;', ':', ';') -> StringIWant
// substringBetween('MyLongString:StringIWant;;', ':', ';') -> StringIWant
// substringBetween('MyLongString:StringIWant;:StringIDontWant;', ':', ';') -> StringIWant
var s = 'MyLongString:StringIWant;';
/:([^;]+);/.exec(s)[1]; // StringIWant
使用分割()
var s = 'MyLongString:StringIWant;';
var arrStr = s.split(/[:;]/);
alert(arrStr);
arrStr将包含所有由:或; 通过for循环访问每个字符串
for(var i=0; i<arrStr.length; i++)
alert(arrStr[i]);