获取所有子字符串。

var out = []; 'MyLongString:StringIWant;'
.replace(/(:)\w+(;)+/g, (e) => {
    out.push(e.replace(':', '').replace(';', ''))
    return e;
});
console.log(out[0])

如果您想从一个字符串中提取发生在两个分隔符(不同或相同)之间的所有子字符串，可以使用此函数。它返回一个包含所有子字符串的数组:

function get_substrings_between(str, startDelimiter, endDelimiter) 
{
    var contents = [];
    var startDelimiterLength = startDelimiter.length;
    var endDelimiterLength = endDelimiter.length;
    var startFrom = contentStart = contentEnd = 0;
    
    while(false !== (contentStart = strpos(str, startDelimiter, startFrom))) 
    {
        contentStart += startDelimiterLength;
        contentEnd = strpos(str, endDelimiter, contentStart);
        if(false === contentEnd) 
        {
            break;
        }
        contents.push( str.substr(contentStart, contentEnd - contentStart) );
        startFrom = contentEnd + endDelimiterLength;
    }

    return contents;
}

// https://stackoverflow.com/a/3978237/1066234
function strpos(haystack, needle, offset) 
{
    var i = (haystack+'').indexOf(needle, (offset || 0));
    return i === -1 ? false : i;
}

// Example usage
var string = "We want to extract all infos (essential ones) from within the brackets (this should be fun).";
var extracted = get_substrings_between(string, '(', ')');
console.log(extracted); 
// output: (2) ["essential ones", "this should be fun"]

最初从PHP由raina77ow，移植到Javascript。

你也可以试试这个:

var str = 'one:two;three';    
str.split(':').pop().split(';')[0]; // returns 'two'

你可以试试这个

var mySubString = str.substring(
    str.indexOf(":") + 1, 
    str.lastIndexOf(";")
);

尝试使用javascript在两个字符之间获取子字符串。

        $("button").click(function(){
            var myStr = "MyLongString:StringIWant;";
            var subStr = myStr.match(":(.*);");
            alert(subStr[1]);
        });

从@ Find子字符串之间的两个字符与jQuery

使用' get_between '实用函数:

get_between <- function(str, first_character, last_character) {
    new_str = str.match(first_character + "(.*)" + last_character)[1].trim()
    return(new_str)
    }

字符串

my_string = 'and the thing that ! on the @ with the ^^ goes now' 

用法:

get_between(my_string, 'that', 'now')

结果:

"! on the @ with the ^^ goes