我试图从一个更大的字符串中提取一个字符串,它得到了a:和a之间的所有东西;

当前的

Str = 'MyLongString:StringIWant;'

期望输出值

newStr = 'StringIWant'

当前回答

下面的函数获取第一个匹配项


function getStringBetween(x: string, start: string, end: string) {
  const regex = new RegExp(`${start}(.*?)${end}`)

  if (regex.test(x)) {
    return regex.exec(x)![1]
  } else return undefined
}

有测试


test("getStringBetween", () => {
  const result = getStringBetween("<em> Jai Ram</em>", "<em>", "</em>")
  expect(result).toEqual(" Jai Ram")
  const result1 = getStringBetween(
    "hare Jai Ram hare hare hare",
    "hare",
    "hare"
  )
  expect(result1).toEqual(" Jai Ram ")
})

其他回答

@Babasaheb Gosavi回答是完美的,如果你有一个子字符串出现(“:”和“;”)。但一旦出现多次,就有点棘手了。


我在多个项目中提出的最佳解决方案是在一个对象中使用四个方法。

第一种方法:实际上是从两个字符串之间获得一个子字符串(但是它只会找到一个结果)。 第二种方法:删除(可能的)最近发现的结果及其前后的子字符串。 第三种方法:将上述两种方法递归地处理一个字符串。 第四种方法:将应用第三种方法并返回结果。


Code

说得够多了,让我们看看代码:

var getFromBetween = {
    results:[],
    string:"",
    getFromBetween:function (sub1,sub2) {
        if(this.string.indexOf(sub1) < 0 || this.string.indexOf(sub2) < 0) return false;
        var SP = this.string.indexOf(sub1)+sub1.length;
        var string1 = this.string.substr(0,SP);
        var string2 = this.string.substr(SP);
        var TP = string1.length + string2.indexOf(sub2);
        return this.string.substring(SP,TP);
    },
    removeFromBetween:function (sub1,sub2) {
        if(this.string.indexOf(sub1) < 0 || this.string.indexOf(sub2) < 0) return false;
        var removal = sub1+this.getFromBetween(sub1,sub2)+sub2;
        this.string = this.string.replace(removal,"");
    },
    getAllResults:function (sub1,sub2) {
        // first check to see if we do have both substrings
        if(this.string.indexOf(sub1) < 0 || this.string.indexOf(sub2) < 0) return;

        // find one result
        var result = this.getFromBetween(sub1,sub2);
        // push it to the results array
        this.results.push(result);
        // remove the most recently found one from the string
        this.removeFromBetween(sub1,sub2);

        // if there's more substrings
        if(this.string.indexOf(sub1) > -1 && this.string.indexOf(sub2) > -1) {
            this.getAllResults(sub1,sub2);
        }
        else return;
    },
    get:function (string,sub1,sub2) {
        this.results = [];
        this.string = string;
        this.getAllResults(sub1,sub2);
        return this.results;
    }
};

如何使用?

例子:

var str = 'this is the haystack {{{0}}} {{{1}}} {{{2}}} {{{3}}} {{{4}}} some text {{{5}}} end of haystack';
var result = getFromBetween.get(str,"{{{","}}}");
console.log(result);
// returns: [0,1,2,3,4,5]

获取两个子字符串之间的字符串(包含多于1个字符)

function substrInBetween(whole_str, str1, str2){
   if (whole_str.indexOf(str1) === -1 || whole_str.indexOf(str2) === -1) {
       return undefined; // or ""
  }
  var strlength1 = str1.length;
  return whole_str.substring(
                whole_str.indexOf(str1) + strlength1, 
                whole_str.indexOf(str2)
               );

   }

注意,我使用indexOf()而不是lastIndexOf(),因此它将检查这些字符串的第一次出现

下面是一个可重用的函数,它允许你使返回的子字符串包含或排除,然后可选地修剪它:

function get_substring(full_string, substring_1, substring_2, inclusive, trim)
{
    if (full_string === null) { return null; };
    let substring_1_start = full_string.indexOf(substring_1);
    if (substring_1_start === -1 ) { return null; }
    let substring_2_start = full_string.indexOf(substring_2, substring_1_start);
    if (substring_2_start === -1 ) { return null; }
    let substring_1_end = substring_1_start + substring_1.length;
    let substring_2_end = substring_2_start + substring_2.length;
    let return_string = inclusive ? (full_string.substring(substring_1_start, substring_2_end)) : (full_string.substring(substring_1_end, substring_2_start));
    return trim ? return_string.trim() : return_string;
}

使用例子:

//Returns 'cake and ice cream'
get_substring('I like cake and ice cream', 'cake', 'cream', true, true);

//Returns ' and ice '
get_substring('I like cake and ice cream', 'cake', 'cream', false, false);

//Returns 'and ice'
get_substring('I like cake and ice cream', 'cake', 'cream', false, true);

//Returns null
get_substring('I like cake and ice cream', 'cake', 'cookies', false, false);

//Returns null
get_substring('I like cake and ice cream', null, 'cream', false, false);

你可以试试这个

var mySubString = str.substring(
    str.indexOf(":") + 1, 
    str.lastIndexOf(";")
);

您可以使用这个函数-

function getStringInBetween(string, start , end) {
    // start and end will be excluded
    var indexOfStart = string.indexOf(start)
    indexOfStart = indexOfStart + start.length;
    var newString = string.slice(indexOfStart)
    var indexOfEnd = newString.indexOf(end)
    return newString.slice(0, indexOfEnd)
}

对于前-

let string = "<div class = 'mice'> I know how to code </div>"
let start = "<div class = 'mice'> "
let end = " </div>"
//then, getStringInBetween(string, start, end) returns "I know how to code"