实际上你有两种方法:

MySQL更新连接语法:

UPDATE tableA a
INNER JOIN tableB b ON a.name_a = b.name_b
SET validation_check = if(start_dts > end_dts, 'VALID', '')
-- where clause can go here

ANSI SQL语法:

UPDATE tableA SET validation_check = 
    (SELECT if(start_DTS > end_DTS, 'VALID', '') AS validation_check
        FROM tableA
        INNER JOIN tableB ON name_A = name_B
        WHERE id_A = tableA.id_A)

挑一个对你来说最自然的。

UPDATE [table_name] AS T1,
      (SELECT [column_name] 
        FROM [table_name] 
        WHERE [column_name] = [value]) AS T2 
  SET T1.[column_name]=T2.[column_name] + 1
WHERE T1.[column_name] = [value];

简单的MySQL:

UPDATE users AS U1, users AS U2 
SET U1.name_one = U2.name_colX
WHERE U2.user_id = U1.user_id

INSERT INTO all_table
SELECT Orders.OrderID,
    Orders.CustomerID,
    Orders.Amount,
    Orders.ProductID,
    Orders.Date,
    Customer.CustomerName,
    Customer.Address
FROM Orders
JOIN Customer ON Orders.CustomerID=Customer.CustomerID
WHERE Orders.OrderID not in (SELECT OrderID FROM all_table)

对于同一张表，

UPDATE PHA_BILL_SEGMENT AS PHA,
     (SELECT BILL_ID, COUNT(REGISTRATION_NUMBER) AS REG 
       FROM PHA_BILL_SEGMENT
        GROUP BY REGISTRATION_NUMBER, BILL_DATE, BILL_AMOUNT
        HAVING REG > 1) T
    SET PHA.BILL_DATE = PHA.BILL_DATE + 2
 WHERE PHA.BILL_ID = T.BILL_ID;

我有一个重复的条目在一个表本身的问题。以下是对我有效的方法。@sibaz也提倡这样做。

最后我用下面的查询解决了这个问题:

The select query is saved in a temp table IF OBJECT_ID(N'tempdb..#New_format_donor_temp', N'U') IS NOT NULL DROP TABLE #New_format_donor_temp; select * into #New_format_donor_temp from DONOR_EMPLOYMENTS where DONOR_ID IN ( 1, 2 ) -- Test New_format_donor_temp -- SELECT * -- FROM #New_format_donor_temp; The temp table is joined in the update query. UPDATE de SET STATUS_CD=de_new.STATUS_CD, STATUS_REASON_CD=de_new.STATUS_REASON_CD, TYPE_CD=de_new.TYPE_CD FROM DONOR_EMPLOYMENTS AS de INNER JOIN #New_format_donor_temp AS de_new ON de_new.EMP_NO = de.EMP_NO WHERE de.DONOR_ID IN ( 3, 4 )

我不是很有经验的SQL请建议任何更好的方法你知道。

以上查询是针对MySql服务器的。