简单的MySQL:

UPDATE users AS U1, users AS U2 
SET U1.name_one = U2.name_colX
WHERE U2.user_id = U1.user_id

实际上你有两种方法:

MySQL更新连接语法:

UPDATE tableA a
INNER JOIN tableB b ON a.name_a = b.name_b
SET validation_check = if(start_dts > end_dts, 'VALID', '')
-- where clause can go here

ANSI SQL语法:

UPDATE tableA SET validation_check = 
    (SELECT if(start_DTS > end_DTS, 'VALID', '') AS validation_check
        FROM tableA
        INNER JOIN tableB ON name_A = name_B
        WHERE id_A = tableA.id_A)

挑一个对你来说最自然的。

如果有人试图将数据从一个数据库更新到另一个数据库，而不管他们的目标是哪个表，那么必须有一些标准来做到这一点。

这个对所有关卡来说都更好更干净:

UPDATE dbname1.content targetTable

LEFT JOIN dbname2.someothertable sourceTable ON
    targetTable.compare_field= sourceTable.compare_field
SET
    targetTable.col1  = sourceTable.cola,
    targetTable.col2 = sourceTable.colb, 
    targetTable.col3 = sourceTable.colc, 
    targetTable.col4 = sourceTable.cold 

Traaa !效果很好!

有了以上的理解，您就可以修改设置的字段和“on”标准来完成您的工作。您还可以执行检查，然后将数据拉入临时表，然后使用替换表和列名的上述语法运行更新。

希望有用，如果不行请告诉我。我会为你写一个精确的查询。

UPDATE [table_name] AS T1,
      (SELECT [column_name] 
        FROM [table_name] 
        WHERE [column_name] = [value]) AS T2 
  SET T1.[column_name]=T2.[column_name] + 1
WHERE T1.[column_name] = [value];

您可以像这样使用内部连接从另一个表更新值

UPDATE [table1_name] AS t1 INNER JOIN [table2_name] AS t2 ON t1.column1_name] = t2.[column1_name] SET t1.[column2_name] = t2.column2_name];

跟随这里了解如何使用这个查询http://www.voidtricks.com/mysql-inner-join-update/

或者您可以使用select作为子查询来完成此操作

UPDATE [table_name] SET [column_name] = (SELECT [column_name] FROM [table_name] WHERE [column_name] = [value]) WHERE [column_name] = [value];

查询详情请参见http://www.voidtricks.com/mysql-update-from-select/

INSERT INTO all_table
SELECT Orders.OrderID,
    Orders.CustomerID,
    Orders.Amount,
    Orders.ProductID,
    Orders.Date,
    Customer.CustomerName,
    Customer.Address
FROM Orders
JOIN Customer ON Orders.CustomerID=Customer.CustomerID
WHERE Orders.OrderID not in (SELECT OrderID FROM all_table)