如果我有一个JavaScript对象,如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
如果我有一个JavaScript对象,如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
当前回答
找出每个元素的频率,并按频率/值进行排序。
Let response =["苹果","橘子","苹果","香蕉","橘子","香蕉","香蕉"]; 设frequency = {}; response.forEach(函数(项){ 频率[项目]=频率[项目]?频率[项]+ 1:1; }); console.log(频率); let intents = Object.entries(frequency) .sort((a, b) => b[1] - a[1]) . map(函数(x) { 返回x [0]; }); console.log(意图);
输出:
{ apple: 2, orange: 2, banana: 3 }
[ 'banana', 'apple', 'orange' ]
其他回答
我已经用自己的方式尝试过了
var maxSpeed = {
car: 300,
bike: 60,
motorbike: 200,
airplane: 1000,
helicopter: 400,
rocket: 8 * 60 * 60
};
var sorted = {}
Object.keys(maxSpeed).sort ((a,b) => maxSpeed[a] - maxSpeed[b]).map(item => sorted[item] = maxSpeed[item]);
console.log(sorted)
为了完整起见,这个函数返回对象属性的排序数组:
function sortObject(obj) {
var arr = [];
for (var prop in obj) {
if (obj.hasOwnProperty(prop)) {
arr.push({
'key': prop,
'value': obj[prop]
});
}
}
arr.sort(function(a, b) { return a.value - b.value; });
//arr.sort(function(a, b) { return a.value.toLowerCase().localeCompare(b.value.toLowerCase()); }); //use this to sort as strings
return arr; // returns array
}
var list = {"you": 100, "me": 75, "foo": 116, "bar": 15};
var arr = sortObject(list);
console.log(arr); // [{key:"bar", value:15}, {key:"me", value:75}, {key:"you", value:100}, {key:"foo", value:116}]
JSFiddle上面的代码在这里。此解决方案基于本文。
更新的小提琴排序字符串是在这里。您可以从它中删除额外的. tolowercase()转换,以便区分大小写的字符串比较。
let toSort = {a:2323, b: 14, c: 799}
let sorted = Object.entries(toSort ).sort((a,b)=> a[1]-b[1])
输出:
[ [ "b", 14 ], [ "c", 799 ], [ "a", 2323 ] ]
我遵循slebetman给出的解决方案(去阅读它的所有细节),但调整,因为你的对象是非嵌套的。
// First create the array of keys/values so that we can sort it:
var sort_array = [];
for (var key in list) {
sort_array.push({key:key,value:list[key]});
}
// Now sort it:
sort_array.sort(function(x,y){return x.value - y.value});
// Now process that object with it:
for (var i=0;i<sort_array.length;i++) {
var item = list[sort_array[i].key];
// now do stuff with each item
}
我用sort的解决方案:
let list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
let sorted = Object.entries(list).sort((a,b) => a[1] - b[1]);
for(let element of sorted) {
console.log(element[0]+ ": " + element[1]);
}