@marcusR回答的“箭头”版本供参考

var myObj = { you: 100, me: 75, foo: 116, bar: 15 };
keysSorted = Object.keys(myObj).sort((a, b) => myObj[a] - myObj[b]);
alert(keysSorted); // bar,me,you,foo

更新:2017年4月 返回一个上面定义的排序后的myObj对象。 const myObj ={你:100，我:75,foo: 116, bar: 15}; Const result = 种(myObj) .sort((a, b) => myObj[a] - myObj[b]) .reduce ( (_sortedObj, key) => ({ ……_sortedObj, (例子):myObj(例子) }), {} ）; document . write (JSON.stringify(结果));

更新:2021年3月-对象。带有排序功能的条目(根据注释更新) const myObj ={你:100，我:75,foo: 116, bar: 15}; const result =对象 .entries (myObj) .sort((a, b) => a[1] - b[1]) .reduce((_sortedObj， [k,v]) => ({ ……_sortedObj, [k]: v }, {}) document . write (JSON.stringify(结果));

找不到上面的答案，既工作又小，并支持嵌套对象(不是数组)，所以我写了自己的一个:)工作与字符串和整数。

  function sortObjectProperties(obj, sortValue){
      var keysSorted = Object.keys(obj).sort(function(a,b){return obj[a][sortValue]-obj[b][sortValue]});
      var objSorted = {};
      for(var i = 0; i < keysSorted.length; i++){
          objSorted[keysSorted[i]] = obj[keysSorted[i]];
      }
      return objSorted;
    }

用法:

    /* sample object with unsorder properties, that we want to sort by 
    their "customValue" property */

    var objUnsorted = {
       prop1 : {
          customValue : 'ZZ'
       },
       prop2 : {
          customValue : 'AA'
       }
    }

    // call the function, passing object and property with it should be sorted out
    var objSorted = sortObjectProperties(objUnsorted, 'customValue');

    // now console.log(objSorted) will return:
    { 
       prop2 : {
          customValue : 'AA'
       },
       prop1 : {
          customValue : 'ZZ'
       } 
    }

另一种解决方法:-

var res = [{"s1":5},{"s2":3},{"s3":8}].sort(function(obj1,obj2){ 
 var prop1;
 var prop2;
 for(prop in obj1) {
  prop1=prop;
 }
 for(prop in obj2) {
  prop2=prop;
 }
 //the above two for loops will iterate only once because we use it to find the key
 return obj1[prop1]-obj2[prop2];
});

//res将有结果数组

如果我有一个这样的对象，

var dayObj = {
              "Friday":["5:00pm to 12:00am"] ,
              "Wednesday":["5:00pm to 11:00pm"],
              "Sunday":["11:00am to 11:00pm"], 
              "Thursday":["5:00pm to 11:00pm"],
              "Saturday":["11:00am to 12:00am"]
           }

我想按天排序，

我们应该先有daySorterMap，

var daySorterMap = {
  // "sunday": 0, // << if sunday is first day of week
  "Monday": 1,
  "Tuesday": 2,
  "Wednesday": 3,
  "Thursday": 4,
  "Friday": 5,
  "Saturday": 6,
  "Sunday": 7
}

初始化一个单独的对象sortedDayObj，

var sortedDayObj={};
Object.keys(dayObj)
.sort((a,b) => daySorterMap[a] - daySorterMap[b])
.forEach(value=>sortedDayObj[value]= dayObj[value])

你可以返回sortedDayObj

我为此做了一个插件，它接受1个arg，这是一个未排序的对象，并返回一个对象，已排序的道具值。这将适用于所有二维对象，如{"Nick": 28， "Bob": 52}…

var sloppyObj = {
    'C': 78,
    'A': 3,
    'B': 4
};

// Extend object to support sort method
function sortObj(obj) {
    "use strict";

    function Obj2Array(obj) {
        var newObj = [];
        for (var key in obj) {
            if (!obj.hasOwnProperty(key)) return;
            var value = [key, obj[key]];
            newObj.push(value);
        }
        return newObj;
    }

    var sortedArray = Obj2Array(obj).sort(function(a, b) {
        if (a[1] < b[1]) return -1;
        if (a[1] > b[1]) return 1;
        return 0;
    });

    function recreateSortedObject(targ) {
        var sortedObj = {};
        for (var i = 0; i < targ.length; i++) {
            sortedObj[targ[i][0]] = targ[i][1];
        }
        return sortedObj;
    }
    return recreateSortedObject(sortedArray);
}

var sortedObj = sortObj(sloppyObj);

alert(JSON.stringify(sortedObj));

下面是该函数按预期工作的演示 http://codepen.io/nicholasabrams/pen/RWRqve?editors=001

    var list = {
    "you": 100,
    "me": 75,
    "foo": 116,
    "bar": 15
};
var tmpList = {};
while (Object.keys(list).length) {
    var key = Object.keys(list).reduce((a, b) => list[a] > list[b] ? a : b);
    tmpList[key] = list[key];
    delete list[key];
}
list = tmpList;
console.log(list); // { foo: 116, you: 100, me: 75, bar: 15 }