我如何打印错误/异常在except:块?

try:
    ...
except:
    print(exception)

当前回答

对于Python 2.6及更高版本和Python 3.x:

except Exception as e: print(e)

对于Python 2.5及更早版本,使用:

except Exception,e: print str(e)

其他回答

在Python 2.6或更高版本中,它更简洁:

except Exception as e: print(e)

在较旧的版本中,它仍然是相当可读的:

except Exception, e: print e

如果您想这样做的话,可以使用assert语句来引发一行错误。这将帮助您编写静态可修复的代码并及早检查错误。

assert type(A) is type(""), "requires a string"

traceback模块提供了格式化和打印异常及其回溯信息的方法,例如,这将像默认处理程序一样打印异常:

import traceback

try:
    1/0
except Exception:
    traceback.print_exc()

输出:

Traceback (most recent call last):
  File "C:\scripts\divide_by_zero.py", line 4, in <module>
    1/0
ZeroDivisionError: division by zero

对于Python 2.6及更高版本和Python 3.x:

except Exception as e: print(e)

对于Python 2.5及更早版本,使用:

except Exception,e: print str(e)

如果你想传递错误字符串,这里有一个来自错误和异常(Python 2.6)的例子

>>> try:
...    raise Exception('spam', 'eggs')
... except Exception as inst:
...    print type(inst)     # the exception instance
...    print inst.args      # arguments stored in .args
...    print inst           # __str__ allows args to printed directly
...    x, y = inst          # __getitem__ allows args to be unpacked directly
...    print 'x =', x
...    print 'y =', y
...
<type 'exceptions.Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggs