我如何打印错误/异常在except:块?
try:
...
except:
print(exception)
我如何打印错误/异常在except:块?
try:
...
except:
print(exception)
当前回答
对于Python 2.6及更高版本和Python 3.x:
except Exception as e: print(e)
对于Python 2.5及更早版本,使用:
except Exception,e: print str(e)
其他回答
在Python 2.6或更高版本中,它更简洁:
except Exception as e: print(e)
在较旧的版本中,它仍然是相当可读的:
except Exception, e: print e
如果您想这样做的话,可以使用assert语句来引发一行错误。这将帮助您编写静态可修复的代码并及早检查错误。
assert type(A) is type(""), "requires a string"
traceback模块提供了格式化和打印异常及其回溯信息的方法,例如,这将像默认处理程序一样打印异常:
import traceback
try:
1/0
except Exception:
traceback.print_exc()
输出:
Traceback (most recent call last):
File "C:\scripts\divide_by_zero.py", line 4, in <module>
1/0
ZeroDivisionError: division by zero
对于Python 2.6及更高版本和Python 3.x:
except Exception as e: print(e)
对于Python 2.5及更早版本,使用:
except Exception,e: print str(e)
如果你想传递错误字符串,这里有一个来自错误和异常(Python 2.6)的例子
>>> try:
... raise Exception('spam', 'eggs')
... except Exception as inst:
... print type(inst) # the exception instance
... print inst.args # arguments stored in .args
... print inst # __str__ allows args to printed directly
... x, y = inst # __getitem__ allows args to be unpacked directly
... print 'x =', x
... print 'y =', y
...
<type 'exceptions.Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggs