如何在PHP中获得每月的最后一天?
考虑到:
$a_date = "2009-11-23"
我想要2009-11-30;鉴于
$a_date = "2009-12-23"
我要2009-12-31。
如何在PHP中获得每月的最后一天?
考虑到:
$a_date = "2009-11-23"
我想要2009-11-30;鉴于
$a_date = "2009-12-23"
我要2009-12-31。
当前回答
对我来说,最优雅的是使用DateTime
我不知道我没有看到DateTime::createFromFormat,一行程序
$lastDay = \DateTime::createFromFormat("Y-m-d", "2009-11-23")->format("Y-m-t");
其他回答
你可以为下个月的第一天创建一个日期,然后使用strtotime("-1 day", $firstOfNextMonth)
现在,如果你有月份和年份,DateTime可以很方便地做到这一点
$date = new DateTime('last day of '.$year.'-'.$month);
来自另一个DateTime对象
$date = new DateTime('last day of '.$otherdate->format('Y-m'));
$date1 = $year.'-'.$month;
$d = date_create_from_format('Y-m',$date1);
$last_day = date_format($d, 't');
2行代码,你就完成了:
$oDate = new DateTime("2019-11-23");
// now your date object has been updated with last day of month
$oDate->setDate($oDate->format("Y"),$oDate->format("m"),$oDate->format("t"));
// or to just echo you can skip the above line using this
echo $oDate->format("Y-m-t");
这应该可以工作:
$week_start = strtotime('last Sunday', time());
$week_end = strtotime('next Sunday', time());
$month_start = strtotime('first day of this month', time());
$month_end = strtotime('last day of this month', time());
$year_start = strtotime('first day of January', time());
$year_end = strtotime('last day of December', time());
echo date('D, M jS Y', $week_start).'<br/>';
echo date('D, M jS Y', $week_end).'<br/>';
echo date('D, M jS Y', $month_start).'<br/>';
echo date('D, M jS Y', $month_end).'<br/>';
echo date('D, M jS Y', $year_start).'<br/>';
echo date('D, M jS Y', $year_end).'<br/>';