如何在PHP中获得每月的最后一天?
考虑到:
$a_date = "2009-11-23"
我想要2009-11-30;鉴于
$a_date = "2009-12-23"
我要2009-12-31。
如何在PHP中获得每月的最后一天?
考虑到:
$a_date = "2009-11-23"
我想要2009-11-30;鉴于
$a_date = "2009-12-23"
我要2009-12-31。
当前回答
如果你知道一个月的最后一天,
public function getLastDateOfMonth($month)
{
$date = date('Y').'-'.$month.'-01'; //make date of month
return date('t', strtotime($date));
}
$this->getLastDateOfMonth(01); //31
其他回答
有很多方法可以得到一个月的最后一天。
//to get last day of current month
echo date("t", strtotime('now'));
//to get last day from specific date
$date = "2014-07-24";
echo date("t", strtotime($date));
//to get last day from specific date by calendar
$date = "2014-07-24";
$dateArr=explode('-',$date);
echo cal_days_in_month(CAL_GREGORIAN, $dateArr[1], $dateArr[0]);
2行代码,你就完成了:
$oDate = new DateTime("2019-11-23");
// now your date object has been updated with last day of month
$oDate->setDate($oDate->format("Y"),$oDate->format("m"),$oDate->format("t"));
// or to just echo you can skip the above line using this
echo $oDate->format("Y-m-t");
碳API扩展PHP DateTime
Carbon::parse("2009-11-23")->lastOfMonth()->day;
or
Carbon::createFromDate(2009, 11, 23)->lastOfMonth()->day;
将返回
30
现在,如果你有月份和年份,DateTime可以很方便地做到这一点
$date = new DateTime('last day of '.$year.'-'.$month);
来自另一个DateTime对象
$date = new DateTime('last day of '.$otherdate->format('Y-m'));
T返回给定日期当月的天数(date参见文档):
$a_date = "2009-11-23";
echo date("Y-m-t", strtotime($a_date));