如何可能生成一个随机的,唯一的字符串使用数字和字母用于验证链接?就像你在一个网站上创建了一个账户,它会给你发一封带有链接的电子邮件,你必须点击那个链接才能验证你的账户
如何使用PHP生成其中一个?
如何可能生成一个随机的,唯一的字符串使用数字和字母用于验证链接?就像你在一个网站上创建了一个账户,它会给你发一封带有链接的电子邮件,你必须点击那个链接才能验证你的账户
如何使用PHP生成其中一个?
当前回答
这个人被一杯水呛到……
$random= substr(str_shuffle(" 0123456789abcdefghijklmnopqrstuvxyzabcdefghijklmnopqrstuvwxyz *.-_"), 0,10);
简单。 这个随机字符串重复的可能性是0,000000000000000000000000000001^70
其他回答
斯科特,是的,你写得很好,解决得很好!谢谢。
我还需要为我的每个用户生成唯一的API令牌。以下是我的方法,我使用用户信息(Userid和Username):
public function generateUniqueToken($userid, $username){
$rand = mt_rand(100,999);
$md5 = md5($userid.'!(&^ 532567_465 ///'.$username);
$md53 = substr($md5,0,3);
$md5_remaining = substr($md5,3);
$md5 = $md53. $rand. $userid. $md5_remaining;
return $md5;
}
请看看,如果我能做什么改进,请告诉我。谢谢
一个简单的解决方案是通过丢弃非字母数字字符将64进制转换为字母数字。
它使用random_bytes()来获得加密安全的结果。
function random_alphanumeric(int $length): string
{
$result='';
do
{
//Base 64 produces 4 characters for each 3 bytes, so most times this will give enough bytes in a single pass
$bytes=random_bytes(($length+3-strlen($result))*2);
//Discard non-alhpanumeric characters
$result.=str_replace(['/','+','='],['','',''],base64_encode($bytes));
//Keep adding characters until the string is long enough
//Add a few extra because the last 2 or 3 characters of a base 64 string tend to be less diverse
}while(strlen($result)<$length+3);
return substr($result,0,$length);
}
编辑:我只是重新审视了一下,因为我需要一些更灵活的东西。这里有一个解决方案,执行得比上面的好一点,并提供了指定ASCII字符集的任何子集的选项:
<?php
class RandomText
{
protected
$allowedChars,
//Maximum index to use
$allowedCount,
//Index values will be taken from a pool of this size
//It is a power of 2 to keep the distribution of values even
$distributionSize,
//This many characters will be generated for each output character
$ratio;
/**
* @param string $allowedChars characters to choose from
*/
public function __construct(string $allowedChars)
{
$this->allowedCount = strlen($allowedChars);
if($this->allowedCount < 1 || $this->allowedCount > 256) throw new \Exception('At least 1 and no more than 256 allowed character(s) must be specified.');
$this->allowedChars = $allowedChars;
//Find the power of 2 equal or greater than the number of allowed characters
$this->distributionSize = pow(2,ceil(log($this->allowedCount, 2)));
//Generating random bytes is the expensive part of this algorithm
//In most cases some will be wasted so it is helpful to produce some extras, but not too many
//On average, this is how many characters needed to produce 1 character in the allowed set
//50% of the time, more characters will be needed. My tests have shown this to perform well.
$this->ratio = $this->distributionSize / $this->allowedCount;
}
/**
* @param int $length string length of required result
* @return string random text
*/
public function get(int $length) : string
{
if($length < 1) throw new \Exception('$length must be >= 1.');
$result = '';
//Keep track of result length to prevent having to compute strlen()
$l = 0;
$indices = null;
$i = null;
do
{
//Bytes will be used to index the character set. Convert to integers.
$indices = unpack('C*', random_bytes(ceil(($length - $l) * $this->ratio)));
foreach($indices as $i)
{
//Reduce to the smallest range that gives an even distribution
$i %= $this->distributionSize;
//If the index is within the range of characters, add one char to the string
if($i < $this->allowedCount)
{
$l++;
$result .= $this->allowedChars[$i];
}
if($l >= $length) break;
}
}while($l < $length);
return $result;
}
}
这是一个有趣的问题
public function randomStr($length = 16) {
$string = '';
while (($len = strlen($string)) < $length) {
$size = $length - $len;
$bytes = random_bytes($size);
$string .= substr(str_replace(['/', '+', '='], '', base64_encode($bytes)), 0, $size);
}
return $string;
}
从laravel偷来的
生成一个随机数使用 你最喜欢的随机数 发电机 乘除 得到一个与数字匹配的数字 你的代码字母表中的字符 将该索引处的项插入 你的代码字母。 重复1),直到你有你想要的长度 想要
例如(伪代码)
int myInt = random(0, numcharacters)
char[] codealphabet = 'ABCDEF12345'
char random = codealphabet[i]
repeat until long enough
在阅读了之前的例子后,我得出了以下结论:
protected static $nonce_length = 32;
public static function getNonce()
{
$chars = array();
for ($i = 0; $i < 10; $i++)
$chars = array_merge($chars, range(0, 9), range('A', 'Z'));
shuffle($chars);
$start = mt_rand(0, count($chars) - self::$nonce_length);
return substr(join('', $chars), $start, self::$nonce_length);
}
我复制了10倍的数组[0-9,a - z]和洗牌的元素,在我得到一个随机的起始点substr()更“创造性”:) 你可以添加[a-z]和其他元素到数组中,或多或少地复制,比我更有创造力