使用StringBuilder比在循环中连接字符串的性能稍好一些。如果处理的是大字符串，它的性能要高得多。

    public static string getOnlyNumbers(string input)
    {
        StringBuilder stringBuilder = new StringBuilder(input.Length);
        for (int i = 0; i < input.Length; i++)
            if (input[i] >= '0' && input[i] <= '9')
                stringBuilder.Append(input[i]);

        return stringBuilder.ToString();
    }

注意:上面的例子函数只适用于正数

遍历字符串并使用Char。IsDigit

string a = "str123";
string b = string.Empty;
int val;

for (int i=0; i< a.Length; i++)
{
    if (Char.IsDigit(a[i]))
        b += a[i];
}

if (b.Length>0)
    val = int.Parse(b);

string s = "kg g L000145.50\r\n";
        char theCharacter = '.';
        var getNumbers = (from t in s
                          where char.IsDigit(t) || t.Equals(theCharacter)
                          select t).ToArray();
        var _str = string.Empty;
        foreach (var item in getNumbers)
        {
            _str += item.ToString();
        }
        double _dou = Convert.ToDouble(_str);
        MessageBox.Show(_dou.ToString("#,##0.00"));

下面是另一种Linq方法，它从字符串中提取第一个数字。

string input = "123 foo 456";
int result = 0;
bool success = int.TryParse(new string(input
                     .SkipWhile(x => !char.IsDigit(x))
                     .TakeWhile(x => char.IsDigit(x))
                     .ToArray()), out result);

例子:

string input = "123 foo 456"; // 123
string input = "foo 456";     // 456
string input = "123 foo";     // 123

对于那些想要十进制数字的字符串与Regex在两行:

decimal result = 0;
decimal.TryParse(Regex.Match(s, @"\d+").Value, out result);

同样的事情也适用于float, long等等…

使用正则表达式…

Regex re = new Regex(@"\d+");
Match m = re.Match("test 66");

if (m.Success)
{
    Console.WriteLine(string.Format("RegEx found " + m.Value + " at position " + m.Index.ToString()));
}
else
{
    Console.WriteLine("You didn't enter a string containing a number!");
}