有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:
- (BOOL) validEmail:(NSString*) emailString {
if([emailString length]==0){
return NO;
}
NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];
NSLog(@"%i", regExMatches);
if (regExMatches == 0) {
return NO;
} else {
return YES;
}
}
但我无法翻译成斯威夫特。
更新答案@Arsonik对Swift 2.2的回答，使用比其他提供的解决方案更少的冗长代码:
extension String {
func isValidEmail() -> Bool {
let regex = try? NSRegularExpression(pattern: "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$", options: .CaseInsensitive)
return regex?.firstMatchInString(self, options: [], range: NSMakeRange(0, self.characters.count)) != nil
}
}
我唯一添加到响应列表的是，对于Linux, NSRegularExpression不存在，它实际上是RegularExpression
func isEmail() -> Bool {
let patternNormal = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,6}"
#if os(Linux)
let regex = try? RegularExpression(pattern: patternNormal, options: .caseInsensitive)
#else
let regex = try? NSRegularExpression(pattern: patternNormal, options: .caseInsensitive)
#endif
return regex?.firstMatch(in: self, options: [], range: NSMakeRange(0, self.characters.count)) != nil
在macOS和Ubuntu上都能成功编译。
或者你可以扩展可选文本UITextField:
使用方法:
if emailTextField.text.isEmailValid() {
print("email is valid")
}else{
print("wrong email address")
}
扩展:
extension Optional where Wrapped == String {
func isEmailValid() -> Bool{
guard let email = self else { return false }
let emailPattern = "[A-Za-z-0-9.-_]+@[A-Za-z0-9]+\\.[A-Za-z]{2,3}"
do{
let regex = try NSRegularExpression(pattern: emailPattern, options: .caseInsensitive)
let foundPatters = regex.numberOfMatches(in: email, options: .anchored, range: NSRange(location: 0, length: email.count))
if foundPatters > 0 {
return true
}
}catch{
//error
}
return false
}
}
这里有很多正确答案，但许多“正则表达式”是不完整的，可能会发生像“name@domain”这样的电子邮件结果是有效的电子邮件，但它不是。这里是完整的解决方案:
extension String {
var isEmailValid: Bool {
do {
let regex = try NSRegularExpression(pattern: "(?:[a-z0-9!#$%\\&'*+/=?\\^_`{|}~-]+(?:\\.[a-z0-9!#$%\\&'*+/=?\\^_`{|}~-]+)*|\"(?:[\\x01-\\x08\\x0b\\x0c\\x0e-\\x1f\\x21\\x23-\\x5b\\x5d-\\x7f]|\\\\[\\x01-\\x09\\x0b\\x0c\\x0e-\\x7f])*\")@(?:(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?|\\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?|[a-z0-9-]*[a-z0-9]:(?:[\\x01-\\x08\\x0b\\x0c\\x0e-\\x1f\\x21-\\x5a\\x53-\\x7f]|\\\\[\\x01-\\x09\\x0b\\x0c\\x0e-\\x7f])+)\\])", options: .CaseInsensitive)
return regex.firstMatchInString(self, options: NSMatchingOptions(rawValue: 0), range: NSMakeRange(0, self.characters.count)) != nil
} catch {
return false
}
}
}
在Swift 5.7中，在Regex类的帮助下，我们可以以简单有效的方式验证电子邮件地址
private func isValidEmail(_ email: String) -> Bool {
guard let emailRegex = try? Regex("[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}")
else { return false }
return email.firstMatch(of: emailRegex) != nil
}
我们还可以使用属性包装器来提高效率:
@propertyWrapper
struct EmailPropertyWrapper {
private var _value: String
var wrappedValue: String {
get { return isValidEmail(_value) ? _value : String() }
set { _value = newValue }
}
init(email: String) {
_value = email
}
private func isValidEmail(_ email: String) -> Bool {
guard let emailRegex = try? Regex("[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}")
else { return false }
return email.firstMatch(of: emailRegex) != nil
}
}
struct User {
var name: String
@EmailPropertyWrapper var email: String
func validateProperty() -> Bool {
if name.isEmpty || email.isEmpty { return false }
return true
}
}
let user = User(name: "Sy", email: .init(email: "wwdc@icloud.com"))
print(user.validateProperty())
