下面是bar# do_things:

class Bar   
  def do_things
    Foo.some_method(x) do |x|
      y = x.do_something
      return y_is_bad if y.bad? # how do i tell it to stop and return do_things? 
      y.do_something_else
    end
    keep_doing_more_things
  end
end

这里是Foo#some_method:

class Foo
  def self.some_method(targets, &block)
    targets.each do |target|
      begin
        r = yield(target)
      rescue 
        failed << target
      end
    end
  end
end

我想过使用raise,但我想让它通用,所以我不想在Foo中放任何特定的东西。


当前回答

也许您可以使用内置的方法来查找数组中的特定项,而不是逐个查找目标并手动完成所有操作。举几个例子:

class Array
  def first_frog
    detect {|i| i =~ /frog/ }
  end

  def last_frog
    select {|i| i =~ /frog/ }.last
  end
end

p ["dog", "cat", "godzilla", "dogfrog", "woot", "catfrog"].first_frog
# => "dogfrog"
p ["hats", "coats"].first_frog
# => nil
p ["houses", "frogcars", "bottles", "superfrogs"].last_frog
# => "superfrogs"

一个例子是这样做的:

class Bar
  def do_things
    Foo.some_method(x) do |i|
      # only valid `targets` here, yay.
    end
  end
end

class Foo
  def self.failed
    @failed ||= []
  end

  def self.some_method(targets, &block)
    targets.reject {|t| t.do_something.bad? }.each(&block)
  end
end

其他回答

在这个简化的例子中,Next和break似乎做了正确的事情!

class Bar
  def self.do_things
      Foo.some_method(1..10) do |x|
            next if x == 2
            break if x == 9
            print "#{x} "
      end
  end
end

class Foo
    def self.some_method(targets, &block)
      targets.each do |target|
        begin
          r = yield(target)
        rescue  => x
          puts "rescue #{x}"
        end
     end
   end
end

Bar.do_things

输出:1 3 4 5 6 7 8

要从ruby块中跳出,只需使用return关键字return if value.nil?下一个。

Next终止它所在的lambda、block或proc。 Break终止向块让步或调用它所在的proc或lambda的方法。

出处:Ruby块返回,断开,下一个

使用关键字next。如果你不想继续下一个项目,使用休息。

当在块中使用next时,它会导致块立即退出,将控制权返回给迭代器方法,然后迭代器方法可以通过再次调用块来开始新的迭代:

f.each do |line|              # Iterate over the lines in file f
  next if line[0,1] == "#"    # If this line is a comment, go to the next
  puts eval(line)
end

当在一个块中使用时,break将控制权从块转移到调用块的迭代器之外,转移到调用迭代器之后的第一个表达式:

f.each do |line|             # Iterate over the lines in file f
  break if line == "quit\n"  # If this break statement is executed...
  puts eval(line)
end
puts "Good bye"              # ...then control is transferred here

最后,return在block中的用法:

Return总是导致封闭方法返回,不管它在块内嵌套有多深(lambdas除外):

def find(array, target)
  array.each_with_index do |element,index|
    return index if (element == target)  # return from find
  end
  nil  # If we didn't find the element, return nil
end

使用关键字break而不是return

也许您可以使用内置的方法来查找数组中的特定项,而不是逐个查找目标并手动完成所有操作。举几个例子:

class Array
  def first_frog
    detect {|i| i =~ /frog/ }
  end

  def last_frog
    select {|i| i =~ /frog/ }.last
  end
end

p ["dog", "cat", "godzilla", "dogfrog", "woot", "catfrog"].first_frog
# => "dogfrog"
p ["hats", "coats"].first_frog
# => nil
p ["houses", "frogcars", "bottles", "superfrogs"].last_frog
# => "superfrogs"

一个例子是这样做的:

class Bar
  def do_things
    Foo.some_method(x) do |i|
      # only valid `targets` here, yay.
    end
  end
end

class Foo
  def self.failed
    @failed ||= []
  end

  def self.some_method(targets, &block)
    targets.reject {|t| t.do_something.bad? }.each(&block)
  end
end