这是一个老问题，但这里有一个替代答案，检索SQLite数据库中的所有列，并为每列提供关联表的名称:

WITH tables AS (SELECT name tableName, sql 
FROM sqlite_master WHERE type = 'table' AND tableName NOT LIKE 'sqlite_%')
SELECT fields.name, fields.type, tableName
FROM tables CROSS JOIN pragma_table_info(tables.tableName) fields

返回这样的结果:

{
    "name": "id",
    "type": "integer",
    "tableName": "examples"
}, {
    "name": "content",
    "type": "text",
    "tableName": "examples"
}

对于包含标识符和字符串内容的简单表。

//JUST little bit modified the answer of giuseppe  which returns array of table columns
+(NSMutableArray*)tableInfo:(NSString *)table{

    sqlite3_stmt *sqlStatement;

    NSMutableArray *result = [NSMutableArray array];

    const char *sql = [[NSString stringWithFormat:@"PRAGMA table_info('%@')",table] UTF8String];

    if(sqlite3_prepare(md.database, sql, -1, &sqlStatement, NULL) != SQLITE_OK)

    {
        NSLog(@"Problem with prepare statement tableInfo %@",
                [NSString stringWithUTF8String:(const char *)sqlite3_errmsg(md.database)]);

    }

    while (sqlite3_step(sqlStatement)==SQLITE_ROW)
    {
        [result addObject:
          [NSString stringWithUTF8String:(char*)sqlite3_column_text(sqlStatement, 1)]];
    }

    return result;
}

-(NSMutableDictionary*)tableInfo:(NSString *)table
{
  sqlite3_stmt *sqlStatement;
  NSMutableDictionary *result = [[NSMutableDictionary alloc] init];
  const char *sql = [[NSString stringWithFormat:@"pragma table_info('%s')",[table UTF8String]] UTF8String];
  if(sqlite3_prepare(db, sql, -1, &sqlStatement, NULL) != SQLITE_OK)
  {
    NSLog(@"Problem with prepare statement tableInfo %@",[NSString stringWithUTF8String:(const char *)sqlite3_errmsg(db)]);

  }
  while (sqlite3_step(sqlStatement)==SQLITE_ROW)
  {
    [result setObject:@"" forKey:[NSString stringWithUTF8String:(char*)sqlite3_column_text(sqlStatement, 1)]];

  }

  return result;
  }

function getDetails(){
var data = [];
dBase.executeSql("PRAGMA table_info('table_name') ", [], function(rsp){
    if(rsp.rows.length > 0){
        for(var i=0; i<rsp.rows.length; i++){
            var o = {
                name: rsp.rows.item(i).name,
                type: rsp.rows.item(i).type
            } 
            data.push(o);
        }
    }
    alert(rsp.rows.item(0).name);

},function(error){
    alert(JSON.stringify(error));
});             
}

只是为了像我这样的超级菜鸟想知道人们是如何或什么意思

PRAGMA table_info('table_name') 

你想使用它作为你的准备语句，如下所示。这样做将选择一个与此类似的表，只是填充了属于您的表的值。

cid         name        type        notnull     dflt_value  pk        
----------  ----------  ----------  ----------  ----------  ----------
0           id          integer     99                      1         
1           name                    0                       0

其中id和name是列的实际名称。所以要得到这个值，你需要使用以下命令选择列名:

//returns the name
sqlite3_column_text(stmt, 1);
//returns the type
sqlite3_column_text(stmt, 2);

它将返回当前行的列名。为了获取它们或找到你想要的，你需要遍历所有行。最简单的方法是采用下面的方式。

//where rc is an int variable if wondering :/
rc = sqlite3_prepare_v2(dbPointer, "pragma table_info ('your table name goes here')", -1, &stmt, NULL);

if (rc==SQLITE_OK)
{
    //will continue to go down the rows (columns in your table) till there are no more
    while(sqlite3_step(stmt) == SQLITE_ROW)
    {
        sprintf(colName, "%s", sqlite3_column_text(stmt, 1));
        //do something with colName because it contains the column's name
    }
}

如果您正在搜索任何特定的列，您可以使用Like语句

ex:

SELECT * FROM sqlite_master where sql like('%LAST%')