这是一个老问题，但这里有一个替代答案，检索SQLite数据库中的所有列，并为每列提供关联表的名称:

WITH tables AS (SELECT name tableName, sql 
FROM sqlite_master WHERE type = 'table' AND tableName NOT LIKE 'sqlite_%')
SELECT fields.name, fields.type, tableName
FROM tables CROSS JOIN pragma_table_info(tables.tableName) fields

返回这样的结果:

{
    "name": "id",
    "type": "integer",
    "tableName": "examples"
}, {
    "name": "content",
    "type": "text",
    "tableName": "examples"
}

对于包含标识符和字符串内容的简单表。

为了获得列信息，你可以使用下面的代码片段:

String sql = "select * from "+oTablename+" LIMIT 0";
Statement statement = connection.createStatement();
ResultSet rs = statement.executeQuery(sql);
ResultSetMetaData mrs = rs.getMetaData();
for(int i = 1; i <= mrs.getColumnCount(); i++)
{
    Object row[] = new Object[3];
    row[0] = mrs.getColumnLabel(i);
    row[1] = mrs.getColumnTypeName(i);
    row[2] = mrs.getPrecision(i);
}

//JUST little bit modified the answer of giuseppe  which returns array of table columns
+(NSMutableArray*)tableInfo:(NSString *)table{

    sqlite3_stmt *sqlStatement;

    NSMutableArray *result = [NSMutableArray array];

    const char *sql = [[NSString stringWithFormat:@"PRAGMA table_info('%@')",table] UTF8String];

    if(sqlite3_prepare(md.database, sql, -1, &sqlStatement, NULL) != SQLITE_OK)

    {
        NSLog(@"Problem with prepare statement tableInfo %@",
                [NSString stringWithUTF8String:(const char *)sqlite3_errmsg(md.database)]);

    }

    while (sqlite3_step(sqlStatement)==SQLITE_ROW)
    {
        [result addObject:
          [NSString stringWithUTF8String:(char*)sqlite3_column_text(sqlStatement, 1)]];
    }

    return result;
}

我知道已经太迟了，但这会帮助其他人。

要找到表的列名，您应该执行select * from tbl_name，您将得到sqlite3_stmt *格式的结果。并检查列对所获取的总列的迭代。请参考以下代码相同。

// sqlite3_stmt *statement ;
int totalColumn = sqlite3_column_count(statement);
for (int iterator = 0; iterator<totalColumn; iterator++) {
   NSLog(@"%s", sqlite3_column_name(statement, iterator));
}

这将打印结果集的所有列名。

这是一个老问题，但这里有一个替代答案，检索SQLite数据库中的所有列，并为每列提供关联表的名称:

WITH tables AS (SELECT name tableName, sql 
FROM sqlite_master WHERE type = 'table' AND tableName NOT LIKE 'sqlite_%')
SELECT fields.name, fields.type, tableName
FROM tables CROSS JOIN pragma_table_info(tables.tableName) fields

返回这样的结果:

{
    "name": "id",
    "type": "integer",
    "tableName": "examples"
}, {
    "name": "content",
    "type": "text",
    "tableName": "examples"
}

对于包含标识符和字符串内容的简单表。

. schema table_name

这将从数据库中列出表的列名。

希望这能有所帮助!!