是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?

我只是想知道我是否错过了一个函数,理想情况下是这样工作的:

fs.copy("/path/to/source/folder", "/path/to/destination/folder");

关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用


当前回答

这是我解决这个问题的方法,没有任何额外的模块。只使用内置的fs和path模块。

注意:这使用fs的读/写函数,所以它不复制任何元数据(创建时间等)。从Node.js 8.5开始,有一个copyFileSync函数可用,它调用操作系统复制函数,因此也复制元数据。我还没有测试它们,但它应该可以替换它们。(见https://nodejs.org/api/fs.html fs_fs_copyfilesync_src_dest_flags)

var fs = require('fs');
var path = require('path');

function copyFileSync( source, target ) {

    var targetFile = target;

    // If target is a directory, a new file with the same name will be created
    if ( fs.existsSync( target ) ) {
        if ( fs.lstatSync( target ).isDirectory() ) {
            targetFile = path.join( target, path.basename( source ) );
        }
    }

    fs.writeFileSync(targetFile, fs.readFileSync(source));
}

function copyFolderRecursiveSync( source, target ) {
    var files = [];

    // Check if folder needs to be created or integrated
    var targetFolder = path.join( target, path.basename( source ) );
    if ( !fs.existsSync( targetFolder ) ) {
        fs.mkdirSync( targetFolder );
    }

    // Copy
    if ( fs.lstatSync( source ).isDirectory() ) {
        files = fs.readdirSync( source );
        files.forEach( function ( file ) {
            var curSource = path.join( source, file );
            if ( fs.lstatSync( curSource ).isDirectory() ) {
                copyFolderRecursiveSync( curSource, targetFolder );
            } else {
                copyFileSync( curSource, targetFolder );
            }
        } );
    }
}

其他回答

有一些模块支持复制文件夹及其内容。最流行的是wrench.js:

// Deep-copy an existing directory
wrench.copyDirSyncRecursive('directory_to_copy', 'location_where_copy_should_end_up');

一个替代方案是node-fs-extra:

fs.copy('/tmp/mydir', '/tmp/mynewdir', function (err) {
  if (err) {
    console.error(err);
  } else {
    console.log("success!");
  }
}); // Copies directory, even if it has subdirectories or files

打印稿版本

async function copyDir(source: string, destination: string): Promise<any> {
  const directoryEntries = await readdir(source, { withFileTypes: true });
  await mkdir(destination, { recursive: true });

  return Promise.all(
    directoryEntries.map(async (entry) => {
      const sourcePath = path.join(source, entry.name);
      const destinationPath = path.join(destination, entry.name);

      return entry.isDirectory()
        ? copyDir(sourcePath, destinationPath)
        : copyFile(sourcePath, destinationPath);
    })
  );
}

我尝试了fs-extra和copy-dir来递归地复制文件夹。但我希望它能

正常工作(copy-dir抛出一个不合理的错误) 在过滤器中提供两个参数:filepath和filetype (fs-extra不告诉文件类型) 有从目录到子目录的检查和从目录到文件的检查吗

所以我自己写了:

// Node.js module for Node.js 8.6+
var path = require("path");
var fs = require("fs");

function copyDirSync(src, dest, options) {
  var srcPath = path.resolve(src);
  var destPath = path.resolve(dest);
  if(path.relative(srcPath, destPath).charAt(0) != ".")
    throw new Error("dest path must be out of src path");
  var settings = Object.assign(Object.create(copyDirSync.options), options);
  copyDirSync0(srcPath, destPath, settings);
  function copyDirSync0(srcPath, destPath, settings) {
    var files = fs.readdirSync(srcPath);
    if (!fs.existsSync(destPath)) {
      fs.mkdirSync(destPath);
    }else if(!fs.lstatSync(destPath).isDirectory()) {
      if(settings.overwrite)
        throw new Error(`Cannot overwrite non-directory '${destPath}' with directory '${srcPath}'.`);
      return;
    }
    files.forEach(function(filename) {
      var childSrcPath = path.join(srcPath, filename);
      var childDestPath = path.join(destPath, filename);
      var type = fs.lstatSync(childSrcPath).isDirectory() ? "directory" : "file";
      if(!settings.filter(childSrcPath, type))
        return;
      if (type == "directory") {
        copyDirSync0(childSrcPath, childDestPath, settings);
      } else {
        fs.copyFileSync(childSrcPath, childDestPath, settings.overwrite ? 0 : fs.constants.COPYFILE_EXCL);
        if(!settings.preserveFileDate)
          fs.futimesSync(childDestPath, Date.now(), Date.now());
      }
    });
  }
}
copyDirSync.options = {
  overwrite: true,
  preserveFileDate: true,
  filter: function(filepath, type) {
    return true;
  }
};

还有一个类似的函数mkdirs,它是mkdirp的替代:

function mkdirsSync(dest) {
  var destPath = path.resolve(dest);
  mkdirsSync0(destPath);
  function mkdirsSync0(destPath) {
    var parentPath = path.dirname(destPath);
    if(parentPath == destPath)
      throw new Error(`cannot mkdir ${destPath}, invalid root`);
    if (!fs.existsSync(destPath)) {
      mkdirsSync0(parentPath);
      fs.mkdirSync(destPath);
    }else if(!fs.lstatSync(destPath).isDirectory()) {
      throw new Error(`cannot mkdir ${destPath}, a file already exists there`);
    }
  }
}

由于我只是构建一个简单的Node.js脚本,我不希望脚本的用户需要导入一堆外部模块和依赖项,所以我开始思考,并从Bash shell中搜索运行命令。

这个Node.js代码片段递归地复制了一个名为node-webkit的文件夹。应用程序到一个名为build的文件夹:

child = exec("cp -r node-webkit.app build", function(error, stdout, stderr) {
    sys.print("stdout: " + stdout);
    sys.print("stderr: " + stderr);
    if(error !== null) {
        console.log("exec error: " + error);
    } else {

    }
});

感谢dzone的兰斯·波拉德让我开始。

上面的代码片段仅限于基于unix的平台,如macOS和Linux,但类似的技术也适用于Windows。

这可能是一个可能的解决方案使用异步生成器函数和迭代等待循环。这个解决方案包括过滤掉一些目录的可能性,将它们作为可选的第三个数组参数传递。

import path from 'path';
import { readdir, copy } from 'fs-extra';

async function* getFilesRecursive(srcDir: string, excludedDir?: PathLike[]): AsyncGenerator<string> {
  const directoryEntries: Dirent[] = await readdir(srcDir, { withFileTypes: true });
  if (!directoryEntries.length) yield srcDir; // If the directory is empty, return the directory path.
  for (const entry of directoryEntries) {
    const fileName = entry.name;
      const sourcePath = resolvePath(`${srcDir}/${fileName}`);
      if (entry.isDirectory()) {
        if (!excludedDir?.includes(sourcePath)) {
          yield* getFilesRecursive(sourcePath, excludedDir);
        }
      } else {
        yield sourcePath;
      }
  }
}

然后:

for await (const filePath of getFilesRecursive(path, ['dir1', 'dir2'])) {
   await copy(filePath, filePath.replace(path, path2));
}