利用本文中的资源以及来自不同来源的左右信息，我提出了这个优雅的解决方案，创建以下抽象类

import java.util.Date;

import javax.persistence.Column;
import javax.persistence.MappedSuperclass;
import javax.persistence.PrePersist;
import javax.persistence.PreUpdate;
import javax.persistence.Temporal;
import javax.persistence.TemporalType;

@MappedSuperclass
public abstract class AbstractTimestampEntity {

    @Temporal(TemporalType.TIMESTAMP)
    @Column(name = "created", nullable = false)
    private Date created;

    @Temporal(TemporalType.TIMESTAMP)
    @Column(name = "updated", nullable = false)
    private Date updated;

    @PrePersist
    protected void onCreate() {
    updated = created = new Date();
    }

    @PreUpdate
    protected void onUpdate() {
    updated = new Date();
    }
}

并让你的所有实体扩展它，例如:

@Entity
@Table(name = "campaign")
public class Campaign extends AbstractTimestampEntity implements Serializable {
...
}

谢谢所有帮助过我的人。在我自己做了一些研究之后(我是问这个问题的人)，以下是我发现最有意义的:

Database column type: the timezone-agnostic number of milliseconds since 1970 represented as decimal(20) because 2^64 has 20 digits and disk space is cheap; let's be straightforward. Also, I will use neither DEFAULT CURRENT_TIMESTAMP, nor triggers. I want no magic in the DB. Java field type: long. The Unix timestamp is well supported across various libs, long has no Y2038 problems, timestamp arithmetic is fast and easy (mainly operator < and operator +, assuming no days/months/years are involved in the calculations). And, most importantly, both primitive longs and java.lang.Longs are immutable—effectively passed by value—unlike java.util.Dates; I'd be really pissed off to find something like foo.getLastUpdate().setTime(System.currentTimeMillis()) when debugging somebody else's code. The ORM framework should be responsible for filling in the data automatically. I haven't tested this yet, but only looking at the docs I assume that @Temporal will do the job; not sure about whether I might use @Version for this purpose. @PrePersist and @PreUpdate are good alternatives to control that manually. Adding that to the layer supertype (common base class) for all entities, is a cute idea provided that you really want timestamping for all of your entities.

你可以使用@CreationTimestamp和@UpdateTimestamp:

@CreationTimestamp
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "create_date")
private Date createDate;

@UpdateTimestamp
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "modify_date")
private Date modifyDate;

利用本文中的资源以及来自不同来源的左右信息，我提出了这个优雅的解决方案，创建以下抽象类

import java.util.Date;

import javax.persistence.Column;
import javax.persistence.MappedSuperclass;
import javax.persistence.PrePersist;
import javax.persistence.PreUpdate;
import javax.persistence.Temporal;
import javax.persistence.TemporalType;

@MappedSuperclass
public abstract class AbstractTimestampEntity {

    @Temporal(TemporalType.TIMESTAMP)
    @Column(name = "created", nullable = false)
    private Date created;

    @Temporal(TemporalType.TIMESTAMP)
    @Column(name = "updated", nullable = false)
    private Date updated;

    @PrePersist
    protected void onCreate() {
    updated = created = new Date();
    }

    @PreUpdate
    protected void onUpdate() {
    updated = new Date();
    }
}

并让你的所有实体扩展它，例如:

@Entity
@Table(name = "campaign")
public class Campaign extends AbstractTimestampEntity implements Serializable {
...
}

只是强调一下:java.util. calendar不是用于时间戳的。date是指时间上的某一刻，不受时区等区域性事物的影响。大多数数据库以这种方式存储数据(即使它们看起来不是这样;这通常是客户端软件中的时区设置;数据是好的)

作为JAVA中的数据类型，我强烈建议使用JAVA .util. date。在使用Calendar时，我遇到了非常糟糕的时区问题。请看这个帖子。

对于设置时间戳，我建议使用AOP方法，或者您可以简单地在表上使用触发器(实际上，这是我发现使用触发器唯一可以接受的事情)。