我需要做一个简单的字符串分割,但似乎没有一个函数,我测试的手动方式似乎不起作用。我该怎么做呢?
当前回答
对于那些从“在Lua中编程”这本书的练习10.1中学习过的人来说,似乎很清楚我们不能使用后面书中解释的概念(迭代器),而且函数应该接受多个字符分隔符。
split()是一个让模式匹配不需要的内容(split)并在空字符串上返回一个空表的技巧。plainSplit()的返回更像其他语言中的split。
magic = "([%%%.%(%)%+%*%?%[%]%^%$])"
function split(str, sep, plain)
if plain then sep = string.gsub(sep, magic, "%%%1") end
local N = '\255'
str = N..str..N
str = string.gsub(str, sep, N..N)
local result = {}
for word in string.gmatch(str, N.."(.-)"..N) do
if word ~= "" then
table.insert(result, word)
end
end
return result
end
function plainSplit(str, sep)
sep = string.gsub(sep, magic, "%%%1")
local result = {}
local start = 0
repeat
start = start + 1
local from, to = string.find(str, sep, start)
from = from and from-1
local word = string.sub(str, start, from, true)
table.insert(result, word)
start = to
until start == nil
return result
end
function tableToString(t)
local ret = "{"
for _, word in ipairs(t) do
ret = ret .. '"' .. word .. '", '
end
ret = string.sub(ret, 1, -3)
ret = ret .. "}"
return #ret > 1 and ret or "{}"
end
function runSplit(func, title, str, sep, plain)
print("\n" .. title)
print("str: '"..str.."'")
print("sep: '"..sep.."'")
local t = func(str, sep, plain)
print("-- t = " .. tableToString(t))
end
print("\n\n\n=== Pattern split ===")
runSplit(split, "Exercice 10.1", "a whole new world", " ")
runSplit(split, "With trailing seperator", " a whole new world ", " ")
runSplit(split, "A word seperator", "a whole new world", " whole ")
runSplit(split, "Pattern seperator", "a1whole2new3world", "%d")
runSplit(split, "Magic characters as plain seperator", "a$.%whole$.%new$.%world", "$.%", true)
runSplit(split, "Control seperator", "a\0whole\1new\2world", "%c")
runSplit(split, "ISO Time", "2020-07-10T15:00:00.000", "[T:%-%.]")
runSplit(split, " === [Fails] with \\255 ===", "a\255whole\0new\0world", "\0", true)
runSplit(split, "How does your function handle empty string?", "", " ")
print("\n\n\n=== Plain split ===")
runSplit(plainSplit, "Exercice 10.1", "a whole new world", " ")
runSplit(plainSplit, "With trailing seperator", " a whole new world ", " ")
runSplit(plainSplit, "A word seperator", "a whole new world", " whole ")
runSplit(plainSplit, "Magic characters as plain seperator", "a$.%whole$.%new$.%world", "$.%")
runSplit(plainSplit, "How does your function handle empty string?", "", " ")
输出
=== Pattern split ===
Exercice 10.1
str: 'a whole new world'
sep: ' '
-- t = {"a", "whole", "new", "world"}
With trailing seperator
str: ' a whole new world '
sep: ' '
-- t = {"a", "whole", "new", "world"}
A word seperator
str: 'a whole new world'
sep: ' whole '
-- t = {"a", "new world"}
Pattern seperator
str: 'a1whole2new3world'
sep: '%d'
-- t = {"a", "whole", "new", "world"}
Magic characters as plain seperator
str: 'a$.%whole$.%new$.%world'
sep: '$.%'
-- t = {"a", "whole", "new", "world"}
Control seperator
str: 'awholenewworld'
sep: '%c'
-- t = {"a", "whole", "new", "world"}
ISO Time
str: '2020-07-10T15:00:00.000'
sep: '[T:%-%.]'
-- t = {"2020", "07", "10", "15", "00", "00", "000"}
=== [Fails] with \255 ===
str: 'a�wholenewworld'
sep: ''
-- t = {"a"}
How does your function handle empty string?
str: ''
sep: ' '
-- t = {}
=== Plain split ===
Exercice 10.1
str: 'a whole new world'
sep: ' '
-- t = {"a", "whole", "new", "world"}
With trailing seperator
str: ' a whole new world '
sep: ' '
-- t = {"", "", "a", "", "whole", "", "", "new", "world", "", ""}
A word seperator
str: 'a whole new world'
sep: ' whole '
-- t = {"a", "new world"}
Magic characters as plain seperator
str: 'a$.%whole$.%new$.%world'
sep: '$.%'
-- t = {"a", "whole", "new", "world"}
How does your function handle empty string?
str: ''
sep: ' '
-- t = {""}
其他回答
这个问题已经很晚了,但如果有人想要一个处理分裂数量的版本,你想要.....
-- Split a string into a table using a delimiter and a limit
string.split = function(str, pat, limit)
local t = {}
local fpat = "(.-)" .. pat
local last_end = 1
local s, e, cap = str:find(fpat, 1)
while s do
if s ~= 1 or cap ~= "" then
table.insert(t, cap)
end
last_end = e+1
s, e, cap = str:find(fpat, last_end)
if limit ~= nil and limit <= #t then
break
end
end
if last_end <= #str then
cap = str:sub(last_end)
table.insert(t, cap)
end
return t
end
因为剥猫皮的方法不止一种,下面是我的方法:
代码:
#!/usr/bin/env lua
local content = [=[
Lorem ipsum dolor sit amet, consectetur adipisicing elit,
sed do eiusmod tempor incididunt ut labore et dolore magna
aliqua. Ut enim ad minim veniam, quis nostrud exercitation
ullamco laboris nisi ut aliquip ex ea commodo consequat.
]=]
local function split(str, sep)
local result = {}
local regex = ("([^%s]+)"):format(sep)
for each in str:gmatch(regex) do
table.insert(result, each)
end
return result
end
local lines = split(content, "\n")
for _,line in ipairs(lines) do
print(line)
end
输出: 圣洁圣洁的人, sed做eiusmod时间incididunt ut并dolore麦格纳 aliqua。Ut enim ad minivenim, quis nostrud practice 这一切都是徒劳的结果。
解释:
gmatch函数作为一个迭代器,它获取所有与regex匹配的字符串。正则表达式接受所有字符,直到找到分隔符为止。
函数如下:
function split(pString, pPattern)
local Table = {} -- NOTE: use {n = 0} in Lua-5.0
local fpat = "(.-)" .. pPattern
local last_end = 1
local s, e, cap = pString:find(fpat, 1)
while s do
if s ~= 1 or cap ~= "" then
table.insert(Table,cap)
end
last_end = e+1
s, e, cap = pString:find(fpat, last_end)
end
if last_end <= #pString then
cap = pString:sub(last_end)
table.insert(Table, cap)
end
return Table
end
这样称呼它:
list=split(string_to_split,pattern_to_match)
例如:
list=split("1:2:3:4","\:")
更多信息请点击这里: http://lua-users.org/wiki/SplitJoin
下面是一个在Lua 4.0中工作的例程,返回inputstr中由sep分隔的子字符串的表t:
function string_split(inputstr, sep)
local inputstr = inputstr .. sep
local idx, inc, t = 0, 1, {}
local idx_prev, substr
repeat
idx_prev = idx
inputstr = strsub(inputstr, idx + 1, -1) -- chop off the beginning of the string containing the match last found by strfind (or initially, nothing); keep the rest (or initially, all)
idx = strfind(inputstr, sep) -- find the 0-based r_index of the first occurrence of separator
if idx == nil then break end -- quit if nothing's found
substr = strsub(inputstr, 0, idx) -- extract the substring occurring before the separator (i.e., data field before the next delimiter)
substr = gsub(substr, "[%c" .. sep .. " ]", "") -- eliminate control characters, separator and spaces
t[inc] = substr -- store the substring (i.e., data field)
inc = inc + 1 -- iterate to next
until idx == nil
return t
end
这个简单的测试
inputstr = "the brown lazy fox jumped over the fat grey hen ... or something."
sep = " "
t = {}
t = string_split(inputstr,sep)
for i=1,15 do
print(i, t[i])
end
收益率:
--> t[1]=the
--> t[2]=brown
--> t[3]=lazy
--> t[4]=fox
--> t[5]=jumped
--> t[6]=over
--> t[7]=the
--> t[8]=fat
--> t[9]=grey
--> t[10]=hen
--> t[11]=...
--> t[12]=or
--> t[13]=something.
如果你在Lua中拆分字符串,你应该尝试string.gmatch()或string.sub()方法。如果知道要分割字符串的索引,则使用string.sub()方法;如果要解析字符串以找到要分割字符串的位置,则使用string.gmatch()方法。
使用Lua 5.1参考手册中的string.gmatch()示例:
t = {}
s = "from=world, to=Lua"
for k, v in string.gmatch(s, "(%w+)=(%w+)") do
t[k] = v
end
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