//It work in Chrome and IE ... I reviewed and readed a lot of answer. then i used it and tested in both ... 

var link = document.createElement("a");

if (link.download !== undefined) { // feature detection
    // Browsers that support HTML5 download attribute
    var blob = new Blob([CSV], { type: 'text/csv;charset=utf-8;' });
    var url = URL.createObjectURL(blob);            
    link.setAttribute("href", url);
    link.setAttribute("download", fileName);
    link.style = "visibility:hidden";
}

if (navigator.msSaveBlob) { // IE 10+
   link.addEventListener("click", function (event) {
     var blob = new Blob([CSV], {
       "type": "text/csv;charset=utf-8;"
     });
   navigator.msSaveBlob(blob, fileName);
  }, false);
}

document.body.appendChild(link);
link.click();
document.body.removeChild(link);

//Regards

人们尝试创建自己的csv字符串，在边缘情况下失败，例如特殊字符，这肯定是一个解决的问题，对吧?

papaparse -用于JSON到CSV编码。Papa.unparse()。

import Papa from "papaparse";

const downloadCSV = (args) => {  

  let filename = args.filename || 'export.csv';
  let columns = args.columns || null;

  let csv = Papa.unparse({ data: args.data, fields: columns})
  if (csv == null) return;

  var blob = new Blob([csv]);
  if (window.navigator.msSaveOrOpenBlob)  // IE hack; see http://msdn.microsoft.com/en-us/library/ie/hh779016.aspx
      window.navigator.msSaveBlob(blob, args.filename);
  else
  {
      var a = window.document.createElement("a");
      a.href = window.URL.createObjectURL(blob, {type: "text/plain"});
      a.download = filename;
      document.body.appendChild(a);
      a.click();  // IE: "Access is denied"; see: https://connect.microsoft.com/IE/feedback/details/797361/ie-10-treats-blob-url-as-cross-origin-and-denies-access
      document.body.removeChild(a);
  }

}

示例使用

downloadCSV({ 
  filename: "filename.csv",
  data: [{"a": "1", "b": "2"}],
  columns: ["a","b"]
});

https://github.com/mholt/PapaParse/issues/175 -请参阅此评论了解浏览器支持讨论。

上面的答案是可行的，但请记住，如果你以.xls格式打开，列~~可能会用'\t'而不是'，'分隔，答案https://stackoverflow.com/a/14966131/6169225对我来说很好，只要我在数组上使用.join('\t')而不是.join('，')。

下面是我如何在Java GWT应用程序的客户端下载CSV文件。特别感谢Xavier John的解决方案。已验证在FF 24.6.0, IE 11.0.20, Chrome 45.0.2454.99(64位)下运行。我希望这能节省一些时间:

public class ExportFile 
{

    private static final String CRLF = "\r\n";

    public static void exportAsCsv(String filename, List<List<String>> data) 
    {
        StringBuilder sb = new StringBuilder();
        for(List<String> row : data) 
        {
            for(int i=0; i<row.size(); i++)
            {
                if(i>0) sb.append(",");
                sb.append(row.get(i));
            }
            sb.append(CRLF);
        }

        generateCsv(filename, sb.toString());
    }

    private static native void generateCsv(String filename, String text)
    /*-{
        var blob = new Blob([text], { type: 'text/csv;charset=utf-8;' });

        if (navigator.msSaveBlob) // IE 10+
        { 
            navigator.msSaveBlob(blob, filename);
        } 
        else 
        {
            var link = document.createElement("a");
            if (link.download !== undefined) // feature detection
            { 
                // Browsers that support HTML5 download attribute
                var url = URL.createObjectURL(blob);
                link.setAttribute("href", url);
                link.setAttribute("download", filename);
                link.style.visibility = 'hidden';
                document.body.appendChild(link);
                link.click();
                document.body.removeChild(link);
            }
        }
    }-*/;
}

简单地尝试一下，这里的一些答案不处理unicode数据和有逗号的数据，例如date。

function downloadUnicodeCSV(filename, datasource) {
    var content = '', newLine = '\r\n';
    for (var _i = 0, datasource_1 = datasource; _i < datasource_1.length; _i++) {
        var line = datasource_1[_i];
        var i = 0;
        for (var _a = 0, line_1 = line; _a < line_1.length; _a++) {
            var item = line_1[_a];
            var it = item.replace(/"/g, '""');
            if (it.search(/("|,|\n)/g) >= 0) {
                it = '"' + it + '"';
            }
            content += (i > 0 ? ',' : '') + it;
            ++i;
        }
        content += newLine;
    }
    var link = document.createElement('a');
    link.setAttribute('href', 'data:text/csv;charset=utf-8,%EF%BB%BF' + encodeURIComponent(content));
    link.setAttribute('download', filename);
    link.style.visibility = 'hidden';
    document.body.appendChild(link);
    link.click();
    document.body.removeChild(link);
};

这里有两个问题:

如何将数组转换为csv字符串 如何将该字符串保存到文件

第一个问题的所有答案(除了millimetric给出的答案)似乎都有些夸张。Milimetric提供的方法不包括其他要求，比如用引号括住字符串或转换对象数组。

以下是我的看法:

对于一个简单的csv，一个map()和一个join()就足够了:

    var test_array = [["name1", 2, 3], ["name2", 4, 5], ["name3", 6, 7], ["name4", 8, 9], ["name5", 10, 11]];
    var csv = test_array.map(function(d){
        return d.join();
    }).join('\n');

    /* Results in 
    name1,2,3
    name2,4,5
    name3,6,7
    name4,8,9
    name5,10,11

此方法还允许您在内部连接中指定除逗号之外的列分隔符。例如一个制表符:d.join('\t')

另一方面，如果你想正确地将字符串括在引号""中，那么你可以使用一些JSON魔法:

var csv = test_array.map(function(d){
       return JSON.stringify(d);
    })
    .join('\n') 
    .replace(/(^\[)|(\]$)/mg, ''); // remove opening [ and closing ]
                                   // brackets from each line 

/* would produce
"name1",2,3
"name2",4,5
"name3",6,7
"name4",8,9
"name5",10,11

如果你有一个这样的对象数组:

var data = [
  {"title": "Book title 1", "author": "Name1 Surname1"},
  {"title": "Book title 2", "author": "Name2 Surname2"},
  {"title": "Book title 3", "author": "Name3 Surname3"},
  {"title": "Book title 4", "author": "Name4 Surname4"}
];

// use
var csv = data.map(function(d){
        return JSON.stringify(Object.values(d));
    })
    .join('\n') 
    .replace(/(^\[)|(\]$)/mg, '');