我很好奇是否有可能使用PDO将值数组绑定到占位符。这里的用例试图传递一个值数组，以便与IN()条件一起使用。
我希望能够这样做:
<?php
$ids=array(1,2,3,7,8,9);
$db = new PDO(...);
$stmt = $db->prepare(
'SELECT *
FROM table
WHERE id IN(:an_array)'
);
$stmt->bindParam('an_array',$ids);
$stmt->execute();
?>
并让PDO绑定并引用数组中的所有值。
目前我正在做:
<?php
$ids = array(1,2,3,7,8,9);
$db = new PDO(...);
foreach($ids as &$val)
$val=$db->quote($val); //iterate through array and quote
$in = implode(',',$ids); //create comma separated list
$stmt = $db->prepare(
'SELECT *
FROM table
WHERE id IN('.$in.')'
);
$stmt->execute();
?>
这当然是工作，但只是想知道是否有一个内置的解决方案，我错过了?
在MySQL和PDO中，我们可以使用JSON数组和JSON_CONTAINS() (https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html#function_json-contains)进行搜索。
$ids = [123, 234, 345, 456]; // Array of users I search
$ids = json_encode($ids); // JSON conversion
$sql = <<<SQL
SELECT ALL user_id, user_login
FROM users
-- Cast is mandatory beaucause JSON_CONTAINS() waits JSON doc candidate
WHERE JSON_CONTAINS(:ids, CAST(user_id AS JSON))
SQL;
$search = $pdo->prepare($sql);
$search->execute([':ids' => $ids]);
$users = $search->fetchAll();
我们也可以使用JSON_TABLE() (https://dev.mysql.com/doc/refman/8.0/en/json-table-functions.html#function_json-table)进行更复杂的情况和JSON数据探索:
$users = [
['id' => 123, 'bday' => ..., 'address' => ...],
['id' => 234, 'bday' => ..., 'address' => ...],
['id' => 345, 'bday' => ..., 'address' => ...],
]; // I'd like to know their login
$users = json_encode($users);
$sql = <<<SQL
SELECT ALL user_id, user_login
FROM users
WHERE user_id IN (
SELECT ALL user_id
FROM JSON_TABLE(:users, '$[*]' COLUMNS (
-- Data exploration...
-- (if needed I can explore really deeply with NESTED kword)
user_id INT PATH '$.id',
-- I could skip these :
user_bday DATE PATH '$.bday',
user_address TINYTEXT PATH '$.address'
)) AS _
)
SQL;
$search = $pdo->prepare($sql);
$search->execute([':users' => $users]);
...
稍微编辑一下施纳勒的代码
<?php
$ids = array(1, 2, 3, 7, 8, 9);
$inQuery = implode(',', array_fill(0, count($ids)-1, '?'));
$db = new PDO(...);
$stmt = $db->prepare(
'SELECT *
FROM table
WHERE id IN(' . $inQuery . ')'
);
foreach ($ids as $k => $id)
$stmt->bindValue(($k+1), $id);
$stmt->execute();
?>
//implode(',', array_fill(0, count($ids)-1), '?'));
//'?' this should be inside the array_fill
//$stmt->bindValue(($k+1), $in);
// instead of $in, it should be $id
以下是我的解决方案:
$total_items = count($array_of_items);
$question_marks = array_fill(0, $total_items, '?');
$sql = 'SELECT * FROM foo WHERE bar IN (' . implode(',', $question_marks ). ')';
$stmt = $dbh->prepare($sql);
$stmt->execute(array_values($array_of_items));
注意array_values的使用。这可以修复键排序问题。
我正在合并id数组，然后删除重复的项。我是这样写的:
$ids = array(0 => 23, 1 => 47, 3 => 17);
那就是失败。
你可以这样转换:
$stmt = $db->prepare('SELECT * FROM table WHERE id IN('.$in.')');
在此:
$stmt = $db->prepare('SELECT * FROM table WHERE id IN(:id1, :id2, :id3, :id7, :id8, :id9)');
然后用这个数组执行它:
$stmt->execute(array(
:id1 =>1, :id2 =>2, :id3 =>3, :id7 =>7, :id8 =>8, :id9 => 9
)
);
因此:
$in = array();
$consultaParam = array();
foreach($ids as $k => $v){
$in[] = ':id'.$v;
$consultaParam[':id'.$v] = $v;
}
最后的代码:
$ids = array(1,2,3,7,8,9);
$db = new PDO(...);
$in = array();
$consultaParam = array();
foreach($ids as $k => $v){
$in[] = ':id'.$v;
$consultaParam[':id'.$v] = $v;
}
$stmt = $db->prepare(
'SELECT *
FROM table
WHERE id IN('.$in.')'
);
$stmt->execute($consultaParam);
您首先在查询中设置“?”的个数，然后由一个“for”发送参数
像这样:
require 'dbConnect.php';
$db=new dbConnect();
$array=[];
array_push($array,'value1');
array_push($array,'value2');
$query="SELECT * FROM sites WHERE kind IN (";
foreach ($array as $field){
$query.="?,";
}
$query=substr($query,0,strlen($query)-1);
$query.=")";
$tbl=$db->connection->prepare($query);
for($i=1;$i<=count($array);$i++)
$tbl->bindParam($i,$array[$i-1],PDO::PARAM_STR);
$tbl->execute();
$row=$tbl->fetchAll(PDO::FETCH_OBJ);
var_dump($row);
在经历了同样的问题之后，我采用了一个更简单的解决方案(尽管仍然没有PDO::PARAM_ARRAY那样优雅):
给定数组$ids = array(2,4,32):
$newparams = array();
foreach ($ids as $n => $val){ $newparams[] = ":id_$n"; }
try {
$stmt = $conn->prepare("DELETE FROM $table WHERE ($table.id IN (" . implode(", ",$newparams). "))");
foreach ($ids as $n => $val){
$stmt->bindParam(":id_$n", intval($val), PDO::PARAM_INT);
}
$stmt->execute();
．.． 等等
所以如果你正在使用一个混合值数组，你将需要更多的代码来测试你的值，然后再分配类型参数:
// inside second foreach..
$valuevar = (is_float($val) ? floatval($val) : is_int($val) ? intval($val) : is_string($val) ? strval($val) : $val );
$stmt->bindParam(":id_$n", $valuevar, (is_int($val) ? PDO::PARAM_INT : is_string($val) ? PDO::PARAM_STR : NULL ));
但是我还没有测试过这个。
