我知道这个问题已经有人回答了，但为了历史的目的，我还是把我的答案写下来，因为我认为这是直截了当的。

import numpy as np
import datetime as dt
listOfDates=[date for date in np.arange(firstDate,lastDate,dt.timedelta(days=x))]

当然，它不会像代码高尔夫那样赢得任何东西，但我认为它很优雅。

下面是bash脚本获得工作日列表的一行代码，这是python 3。很容易修改为任何东西，末尾的int是你想要的过去的天数。

python -c "import sys,datetime; print('\n'.join([(datetime.datetime.today() - datetime.timedelta(days=x)).strftime(\"%Y/%m/%d\") for x in range(0,int(sys.argv[1])) if (datetime.datetime.today() - datetime.timedelta(days=x)).isoweekday()<6]))" 10

这里是提供开始(或者确切地说，结束)日期的变体

python -c "import sys,datetime; print('\n'.join([(datetime.datetime.strptime(sys.argv[1],\"%Y/%m/%d\") - datetime.timedelta(days=x)).strftime(\"%Y/%m/%d \") for x in range(0,int(sys.argv[2])) if (datetime.datetime.today() - datetime.timedelta(days=x)).isoweekday()<6]))" 2015/12/30 10

这里是任意开始和结束日期的变体。并不是说这不是非常有效，而是在bash脚本中放入for循环很好:

python -c "import sys,datetime; print('\n'.join([(datetime.datetime.strptime(sys.argv[1],\"%Y/%m/%d\") + datetime.timedelta(days=x)).strftime(\"%Y/%m/%d\") for x in range(0,int((datetime.datetime.strptime(sys.argv[2], \"%Y/%m/%d\") - datetime.datetime.strptime(sys.argv[1], \"%Y/%m/%d\")).days)) if (datetime.datetime.strptime(sys.argv[1], \"%Y/%m/%d\") + datetime.timedelta(days=x)).isoweekday()<6]))" 2015/12/15 2015/12/30

获取指定的开始日期和结束日期之间的日期范围(优化的时间和空间复杂性):

import datetime

start = datetime.datetime.strptime("21-06-2014", "%d-%m-%Y")
end = datetime.datetime.strptime("07-07-2014", "%d-%m-%Y")
date_generated = [start + datetime.timedelta(days=x) for x in range(0, (end-start).days)]

for date in date_generated:
    print date.strftime("%d-%m-%Y")

一个带有datetime和dateutil的月日期范围生成器。简单易懂的:

import datetime as dt
from dateutil.relativedelta import relativedelta

def month_range(start_date, n_months):
        for m in range(n_months):
            yield start_date + relativedelta(months=+m)

以下是我从自己的代码中创建的要点，这可能会有所帮助。(我知道这个问题太老了，但其他人可以用)

https://gist.github.com/2287345

(下同)

import datetime
from time import mktime

def convert_date_to_datetime(date_object):
    date_tuple = date_object.timetuple()
    date_timestamp = mktime(date_tuple)
    return datetime.datetime.fromtimestamp(date_timestamp)

def date_range(how_many=7):
    for x in range(0, how_many):
        some_date = datetime.datetime.today() - datetime.timedelta(days=x)
        some_datetime = convert_date_to_datetime(some_date.date())
        yield some_datetime

def pick_two_dates(how_many=7):
    a = b = convert_date_to_datetime(datetime.datetime.now().date())
    for each_date in date_range(how_many):
        b = a
        a = each_date
        if a == b:
            continue
        yield b, a

Matplotlib相关

from matplotlib.dates import drange
import datetime

base = datetime.date.today()
end  = base + datetime.timedelta(days=100)
delta = datetime.timedelta(days=1)
l = drange(base, end, delta)