对于那些正在寻找Swift 2.2版本的答案的人:

if self.isViewLoaded() && (self.view.window != nil) {
     // viewController is visible
}

Swift 3:

if self.isViewLoaded && (self.view.window != nil) {
         // viewController is visible
}

你可以通过window属性来检查

if(viewController.view.window){

// view visible

}else{

// no visible

}

我根据@ program的回答做了一个快速扩展。

它允许你很容易地检查UIViewController是否在屏幕上，就像这样:

if someViewController.isOnScreen {
    // Do stuff here
}

扩展:

//
//  UIViewControllerExtension.swift
//

import UIKit

extension UIViewController{
    var isOnScreen: Bool{
        return self.isViewLoaded() && view.window != nil
    }
}

下面是@ program作为UIViewController类别的解决方案:

// UIViewController+Additions.h

@interface UIViewController (Additions)

- (BOOL)isVisible;

@end


// UIViewController+Additions.m

#import "UIViewController+Additions.h"

@implementation UIViewController (Additions)

- (BOOL)isVisible {
    return [self isViewLoaded] && self.view.window;
}

@end

亮点:

window.isVisible

viewController.view.window?.isVisible ?? false

View (macOS):

extension NSViewController {
    var isOnScreen: Bool {
        return ( self.isViewLoaded && view.window != nil )
    }
}

上述解决方案存在几个问题。如果你正在使用，例如，一个UISplitViewController，主视图总是会返回true

if(viewController.isViewLoaded && viewController.view.window) {
    //Always true for master view in split view controller
}

相反，采用这种简单的方法似乎在大多数情况下都很有效，如果不是所有情况:

- (void)viewDidDisappear:(BOOL)animated {
    [super viewDidDisappear:animated];

    //We are now invisible
    self.visible = false;
}

- (void)viewDidAppear:(BOOL)animated {
    [super viewDidAppear:animated];

    //We are now visible
    self.visible = true;
}