如何将Date对象格式化为字符串?
当前回答
这是我实现npm插件的方式
var monthNames = [
"January", "February", "March",
"April", "May", "June", "July",
"August", "September", "October",
"November", "December"
];
var Days = [
"Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday"
];
var formatDate = function(dt,format){
format = format.replace('ss', pad(dt.getSeconds(),2));
format = format.replace('s', dt.getSeconds());
format = format.replace('dd', pad(dt.getDate(),2));
format = format.replace('d', dt.getDate());
format = format.replace('mm', pad(dt.getMinutes(),2));
format = format.replace('m', dt.getMinutes());
format = format.replace('MMMM', monthNames[dt.getMonth()]);
format = format.replace('MMM', monthNames[dt.getMonth()].substring(0,3));
format = format.replace('MM', pad(dt.getMonth()+1,2));
format = format.replace(/M(?![ao])/, dt.getMonth()+1);
format = format.replace('DD', Days[dt.getDay()]);
format = format.replace(/D(?!e)/, Days[dt.getDay()].substring(0,3));
format = format.replace('yyyy', dt.getFullYear());
format = format.replace('YYYY', dt.getFullYear());
format = format.replace('yy', (dt.getFullYear()+"").substring(2));
format = format.replace('YY', (dt.getFullYear()+"").substring(2));
format = format.replace('HH', pad(dt.getHours(),2));
format = format.replace('H', dt.getHours());
return format;
}
pad = function(n, width, z) {
z = z || '0';
n = n + '';
return n.length >= width ? n : new Array(width - n.length + 1).join(z) + n;
}
其他回答
这可能有助于解决问题:
var d=新日期();var选项={day:'数字',月份:'long',年份:'数字'};console.log(d.toLocaleDateString('en-ZA',选项));
这可以帮助:
export const formatDateToString = date => {
if (!date) {
return date;
}
try {
return format(parse(date, 'yyyy-MM-dd', new Date()), 'dd/MM/yyyy');
} catch (error) {
return 'invalid date';
}
};
如果您需要使用普通JavaScript快速格式化日期,请使用getDate、getMonth+1、getFullYear、getHours和getMinutes:
var d = new Date();
var datestring = d.getDate() + "-" + (d.getMonth()+1) + "-" + d.getFullYear() + " " +
d.getHours() + ":" + d.getMinutes();
// 16-5-2015 9:50
或者,如果需要用零填充:
var datestring = ("0" + d.getDate()).slice(-2) + "-" + ("0"+(d.getMonth()+1)).slice(-2) + "-" +
d.getFullYear() + " " + ("0" + d.getHours()).slice(-2) + ":" + ("0" + d.getMinutes()).slice(-2);
// 16-05-2015 09:50
简单格式化程序:
function fmt(date, format = 'YYYY-MM-DDThh:mm:ss') {
const pad2 = (n) => n.toString().padStart(2, '0');
const map = {
YYYY: date.getFullYear(),
MM: pad2(date.getMonth() + 1),
DD: pad2(date.getDate()),
hh: pad2(date.getHours()),
mm: pad2(date.getMinutes()),
ss: pad2(date.getSeconds()),
};
return Object.entries(map).reduce((prev, entry) => prev.replace(...entry), format);
}
用法:
fmt(new Date(), 'YYYY-MM-DDThh:mm:ss'); // '2022-11-07T12:47:59'
这是我实现npm插件的方式
var monthNames = [
"January", "February", "March",
"April", "May", "June", "July",
"August", "September", "October",
"November", "December"
];
var Days = [
"Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday"
];
var formatDate = function(dt,format){
format = format.replace('ss', pad(dt.getSeconds(),2));
format = format.replace('s', dt.getSeconds());
format = format.replace('dd', pad(dt.getDate(),2));
format = format.replace('d', dt.getDate());
format = format.replace('mm', pad(dt.getMinutes(),2));
format = format.replace('m', dt.getMinutes());
format = format.replace('MMMM', monthNames[dt.getMonth()]);
format = format.replace('MMM', monthNames[dt.getMonth()].substring(0,3));
format = format.replace('MM', pad(dt.getMonth()+1,2));
format = format.replace(/M(?![ao])/, dt.getMonth()+1);
format = format.replace('DD', Days[dt.getDay()]);
format = format.replace(/D(?!e)/, Days[dt.getDay()].substring(0,3));
format = format.replace('yyyy', dt.getFullYear());
format = format.replace('YYYY', dt.getFullYear());
format = format.replace('yy', (dt.getFullYear()+"").substring(2));
format = format.replace('YY', (dt.getFullYear()+"").substring(2));
format = format.replace('HH', pad(dt.getHours(),2));
format = format.replace('H', dt.getHours());
return format;
}
pad = function(n, width, z) {
z = z || '0';
n = n + '';
return n.length >= width ? n : new Array(width - n.length + 1).join(z) + n;
}
推荐文章
- 如何使用Jest测试对象键和值是否相等?
- 将长模板文字行换行为多行,而无需在字符串中创建新行
- 如何在JavaScript中映射/减少/过滤一个集?
- Bower: ENOGIT Git未安装或不在PATH中
- 添加javascript选项选择
- 在Node.js中克隆对象
- 为什么在JavaScript的Date构造函数中month参数的范围从0到11 ?
- 使用JavaScript更改URL参数并指定默认值
- 在window.setTimeout()发生之前取消/终止
- 如何删除未定义和空值从一个对象使用lodash?
- 检测当用户滚动到底部的div与jQuery
- 在JavaScript中检查字符串包含另一个子字符串的最快方法?
- 检测视口方向,如果方向是纵向显示警告消息通知用户的指示
- ASP。NET MVC 3 Razor:在head标签中包含JavaScript文件
- 禁用从HTML页面中拖动图像