如何将Date对象格式化为字符串?
当前回答
函数convert_month(i=0,option=“num”){//i=索引变量对象月=[{num:01,短:“Jan”,长:“Janer”},{num:02,短:“Feb”,长:“Februari”},{num:03,短:“Mar”,长:“March”},{num:04,短:“Apr”,长:“April”},{num:05,短:“May”,长:“May”},{num:06,短:“Jun”,长:“Juni”},{num:07,短:“Jul”,长:“July”},{num:08,短:“Aug”,长:“August”},{num:09,短:“Sep”,长:“Sept”},{num:10,短:“Oct”,长:“Octo”},{num:11,短:“Nov”,长:“十一月”},{num:12,短:“Dec”,长:“十二月”}];返回object_months[i][option];}var d=新日期();// https://stackoverflow.com/questions/1408289/how-can-i-do-string-interpolation-in-javascriptvar num=`${d.getDate()}-${convert_month(d.getMonth())}--${d.getFullYear()}';var short=`${d.getDate()}-${convert_month(d.getMonth(),“short”)}-${d.getFullYear()}`;var long=`${d.getDate()}-${convert_month(d.getMonth(),“long”)}-${d.getFullYear()}`;document.querySelector(“#num”).innerHTML=num;document.querySelector(“#short”).innerHTML=短;document.querySelector(“#long”).innerHTML=long;<p>数字:<span id=“num”></span>(默认值)</p><p>短:<span id=“Short”></span></p><p>长:<span id=“Long”></span></p>
其他回答
一行中请求的格式-没有库和Date方法,只有正则表达式:
var d = (new Date()).toString().replace(/\S+\s(\S+)\s(\d+)\s(\d+)\s.*/,'$2-$1-$3');
// date will be formatted as "14-Oct-2015" (pass any date object in place of 'new Date()')
在我的测试中,这在主要浏览器(Chrome、Safari、Firefox和IE)中可靠地工作。正如@RobG所指出的,Date.protype.toString()的输出依赖于实现,因此对于国际或非浏览器实现,只需测试输出,以确保它在JavaScript引擎中正常工作。您甚至可以添加一些代码来测试字符串输出,并在执行正则表达式替换之前确保其与预期匹配。
以下代码将允许您将日期格式设置为DD-MM-YYYY(2017年12月27日)或DD-MM-YYYY(2017年10月26日):
/** Pad number to fit into nearest power of 10 */
function padNumber(number, prependChar, count) {
var out = '' + number; var i;
if (number < Math.pow(10, count))
while (out.length < ('' + Math.pow(10, count)).length) out = prependChar + out;
return out;
}
/* Format the date to 'DD-MM-YYYY' or 'DD MMM YYYY' */
function dateToDMY(date, useNumbersOnly) {
var months = [
'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct',
'Nov', 'Dec'
];
return '' + padNumber(date.getDate(), '0', 1) +
(useNumbersOnly? '-' + padNumber(date.getMonth() + 1, '0', 1) + '-' : ' ' + months[date.getMonth()] + ' ')
+ date.getFullYear();
}
更改date.getFullYear()和padNumber(date.getDate(),“0”,1)的顺序,以生成dateToYMD()函数。
有关详细信息,请参见repl.it示例。
var today = new Date();
var formattedToday = today.toLocaleDateString() + ' ' + today.toLocaleTimeString();
如果您已经在项目中使用ExtJS,则可以使用Ext.Date:
var date = new Date();
Ext.Date.format(date, "d-M-Y");
返回:
"11-Nov-2015"
这是我刚刚编写的一些代码,用于处理我正在处理的项目的日期格式。它模仿了PHP日期格式功能,以满足我的需要。请随意使用它,它只是扩展了现有的Date()对象。这可能不是最优雅的解决方案,但它符合我的需求。
var d = new Date();
d_string = d.format("m/d/Y h:i:s");
/**************************************
* Date class extension
*
*/
// Provide month names
Date.prototype.getMonthName = function(){
var month_names = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December'
];
return month_names[this.getMonth()];
}
// Provide month abbreviation
Date.prototype.getMonthAbbr = function(){
var month_abbrs = [
'Jan',
'Feb',
'Mar',
'Apr',
'May',
'Jun',
'Jul',
'Aug',
'Sep',
'Oct',
'Nov',
'Dec'
];
return month_abbrs[this.getMonth()];
}
// Provide full day of week name
Date.prototype.getDayFull = function(){
var days_full = [
'Sunday',
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday'
];
return days_full[this.getDay()];
};
// Provide full day of week name
Date.prototype.getDayAbbr = function(){
var days_abbr = [
'Sun',
'Mon',
'Tue',
'Wed',
'Thur',
'Fri',
'Sat'
];
return days_abbr[this.getDay()];
};
// Provide the day of year 1-365
Date.prototype.getDayOfYear = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((this - onejan) / 86400000);
};
// Provide the day suffix (st,nd,rd,th)
Date.prototype.getDaySuffix = function() {
var d = this.getDate();
var sfx = ["th","st","nd","rd"];
var val = d%100;
return (sfx[(val-20)%10] || sfx[val] || sfx[0]);
};
// Provide Week of Year
Date.prototype.getWeekOfYear = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((((this - onejan) / 86400000) + onejan.getDay()+1)/7);
}
// Provide if it is a leap year or not
Date.prototype.isLeapYear = function(){
var yr = this.getFullYear();
if ((parseInt(yr)%4) == 0){
if (parseInt(yr)%100 == 0){
if (parseInt(yr)%400 != 0){
return false;
}
if (parseInt(yr)%400 == 0){
return true;
}
}
if (parseInt(yr)%100 != 0){
return true;
}
}
if ((parseInt(yr)%4) != 0){
return false;
}
};
// Provide Number of Days in a given month
Date.prototype.getMonthDayCount = function() {
var month_day_counts = [
31,
this.isLeapYear() ? 29 : 28,
31,
30,
31,
30,
31,
31,
30,
31,
30,
31
];
return month_day_counts[this.getMonth()];
}
// format provided date into this.format format
Date.prototype.format = function(dateFormat){
// break apart format string into array of characters
dateFormat = dateFormat.split("");
var date = this.getDate(),
month = this.getMonth(),
hours = this.getHours(),
minutes = this.getMinutes(),
seconds = this.getSeconds();
// get all date properties ( based on PHP date object functionality )
var date_props = {
d: date < 10 ? '0'+date : date,
D: this.getDayAbbr(),
j: this.getDate(),
l: this.getDayFull(),
S: this.getDaySuffix(),
w: this.getDay(),
z: this.getDayOfYear(),
W: this.getWeekOfYear(),
F: this.getMonthName(),
m: month < 10 ? '0'+(month+1) : month+1,
M: this.getMonthAbbr(),
n: month+1,
t: this.getMonthDayCount(),
L: this.isLeapYear() ? '1' : '0',
Y: this.getFullYear(),
y: this.getFullYear()+''.substring(2,4),
a: hours > 12 ? 'pm' : 'am',
A: hours > 12 ? 'PM' : 'AM',
g: hours % 12 > 0 ? hours % 12 : 12,
G: hours > 0 ? hours : "12",
h: hours % 12 > 0 ? hours % 12 : 12,
H: hours,
i: minutes < 10 ? '0' + minutes : minutes,
s: seconds < 10 ? '0' + seconds : seconds
};
// loop through format array of characters and add matching data else add the format character (:,/, etc.)
var date_string = "";
for(var i=0;i<dateFormat.length;i++){
var f = dateFormat[i];
if(f.match(/[a-zA-Z]/g)){
date_string += date_props[f] ? date_props[f] : '';
} else {
date_string += f;
}
}
return date_string;
};
/*
*
* END - Date class extension
*
************************************/
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