如果不存在,我需要添加一个特定的列。我有类似以下的内容,但它总是返回false:

IF EXISTS(SELECT *
          FROM   INFORMATION_SCHEMA.COLUMNS
          WHERE  TABLE_NAME = 'myTableName'
                 AND COLUMN_NAME = 'myColumnName') 

如何检查SQL Server数据库的表中是否存在列?


当前回答

首先检查dbo.syscolumns(包含字段定义的内部SQL Server表)中是否存在表/列(id/name)组合,如果不存在,则发出适当的ALTER table查询以添加它。例如:

IF NOT EXISTS ( SELECT  *
            FROM    syscolumns
            WHERE   id = OBJECT_ID('Client')
                    AND name = 'Name' ) 
ALTER TABLE Client
ADD Name VARCHAR(64) NULL

其他回答

试试这个。。。

IF NOT EXISTS(
  SELECT TOP 1 1
  FROM INFORMATION_SCHEMA.COLUMNS
  WHERE 
    [TABLE_NAME] = 'Employees'
    AND [COLUMN_NAME] = 'EmployeeID')
BEGIN
  ALTER TABLE [Employees]
    ADD [EmployeeID] INT NULL
END

SQL Server 2005及以后版本:

IF EXISTS(SELECT 1 FROM sys.columns 
          WHERE Name = N'columnName'
          AND Object_ID = Object_ID(N'schemaName.tableName'))
BEGIN
    -- Column Exists
END

马丁·史密斯的版本更短:

IF COL_LENGTH('schemaName.tableName', 'columnName') IS NOT NULL
BEGIN
    -- Column Exists
END

尝试以下操作:

CREATE FUNCTION ColumnExists(@TableName varchar(100), @ColumnName varchar(100))
RETURNS varchar(1) AS
BEGIN
DECLARE @Result varchar(1);
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.Columns WHERE TABLE_NAME = @TableName AND COLUMN_NAME = @ColumnName)
BEGIN
    SET @Result = 'T'
END
ELSE
BEGIN
    SET @Result = 'F'
END
RETURN @Result;
END
GO

GRANT EXECUTE ON  [ColumnExists] TO [whoever]
GO

然后这样使用:

IF ColumnExists('xxx', 'yyyy') = 'F'
BEGIN
  ALTER TABLE xxx
  ADD yyyyy varChar(10) NOT NULL
END
GO

它应该可以在SQL Server 2000和SQL Server 2005上运行。我不确定SQL Server 2008,但我不知道为什么不这样做。

IF EXISTS (
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_CATALOG = 'Database Name'
and TABLE_SCHEMA = 'Schema Name'
and TABLE_NAME = 'Table Name'
and COLUMN_NAME = 'Column Name'
and DATA_TYPE = 'Column Type') -- Where statement lines can be deleted.

BEGIN
  -- Column exists in table
END

ELSE BEGIN
  -- Column does not exist in table
END
select distinct object_name(sc.id)
from syscolumns sc,sysobjects so  
where sc.name like '%col_name%' and so.type='U'