Ryan Cook的答案与我的目标接近，可能更适合其他开发人员。然而，它在字符串的开头添加了http://，并且一般来说，它的格式比我想要的要多一些。

此外，对于我的用例，解析相对路径并不重要。

mdsharp的答案也包含了一个好主意的种子，尽管实际实现需要更多细节才能完成。这是一种充实它的尝试（我在生产中使用了这一点）：

C#

public string UrlCombine(string url1, string url2)
{
    if (url1.Length == 0) {
        return url2;
    }

    if (url2.Length == 0) {
        return url1;
    }

    url1 = url1.TrimEnd('/', '\\');
    url2 = url2.TrimStart('/', '\\');

    return string.Format("{0}/{1}", url1, url2);
}

VB.NET

Public Function UrlCombine(ByVal url1 As String, ByVal url2 As String) As String
    If url1.Length = 0 Then
        Return url2
    End If

    If url2.Length = 0 Then
        Return url1
    End If

    url1 = url1.TrimEnd("/"c, "\"c)
    url2 = url2.TrimStart("/"c, "\"c)

    Return String.Format("{0}/{1}", url1, url2)
End Function

这段代码通过了以下测试，恰好是在VB中：

<TestMethod()> Public Sub UrlCombineTest()
    Dim target As StringHelpers = New StringHelpers()

    Assert.IsTrue(target.UrlCombine("test1", "test2") = "test1/test2")
    Assert.IsTrue(target.UrlCombine("test1/", "test2") = "test1/test2")
    Assert.IsTrue(target.UrlCombine("test1", "/test2") = "test1/test2")
    Assert.IsTrue(target.UrlCombine("test1/", "/test2") = "test1/test2")
    Assert.IsTrue(target.UrlCombine("/test1/", "/test2/") = "/test1/test2/")
    Assert.IsTrue(target.UrlCombine("", "/test2/") = "/test2/")
    Assert.IsTrue(target.UrlCombine("/test1/", "") = "/test1/")
End Sub

您使用Uri.TryCreate（…）：

Uri result = null;

if (Uri.TryCreate(new Uri("http://msdn.microsoft.com/en-us/library/"), "/en-us/library/system.uri.trycreate.aspx", out result))
{
    Console.WriteLine(result);
}

将返回：

http://msdn.microsoft.com/en-us/library/system.uri.trycreate.aspx

如果任何人正在寻找一个单行，并且只想在不创建新方法或引用新库的情况下连接路径的一部分，或者构造URI值并将其转换为字符串，那么。。。

string urlToImage = String.Join("/", "websiteUrl", "folder1", "folder2", "folder3", "item");

这很基本，但我看不出你还需要什么。如果你害怕“/”加倍，那么你可以简单地在后面做一个替换（“//”，“/”）。如果您害怕替换“https://”中的双引号“//”，那么请执行一次连接，替换双引号“/”，然后加入网站url（但是我很确定大多数浏览器会自动将前面带有“https://的内容转换为正确格式）。这看起来像：

string urlToImage = String.Join("/","websiteUrl", String.Join("/", "folder1", "folder2", "folder3", "item").Replace("//","/"));

这里有很多答案可以解决以上所有问题，但在我的情况下，我只需要在一个地方使用一次，不需要过度依赖它。此外，很容易看到这里发生了什么。

参见：https://learn.microsoft.com/en-us/dotnet/api/system.string.join?view=netframework-4.8

这可能是一个合适的简单解决方案：

public static string Combine(string uri1, string uri2)
{
    uri1 = uri1.TrimEnd('/');
    uri2 = uri2.TrimStart('/');
    return string.Format("{0}/{1}", uri1, uri2);
}

我只是拼凑了一个小的扩展方法：

public static string UriCombine (this string val, string append)
        {
            if (String.IsNullOrEmpty(val)) return append;
            if (String.IsNullOrEmpty(append)) return val;
            return val.TrimEnd('/') + "/" + append.TrimStart('/');
        }

它可以这样使用：

"www.example.com/".UriCombine("/images").UriCombine("first.jpeg");

如果您不想拥有像Flurl这样的依赖项，可以使用它的源代码：

    /// <summary>
    /// Basically a Path.Combine for URLs. Ensures exactly one '/' separates each segment,
    /// and exactly on '&amp;' separates each query parameter.
    /// URL-encodes illegal characters but not reserved characters.
    /// </summary>
    /// <param name="parts">URL parts to combine.</param>
    public static string Combine(params string[] parts) {
        if (parts == null)
            throw new ArgumentNullException(nameof(parts));

        string result = "";
        bool inQuery = false, inFragment = false;

        string CombineEnsureSingleSeparator(string a, string b, char separator) {
            if (string.IsNullOrEmpty(a)) return b;
            if (string.IsNullOrEmpty(b)) return a;
            return a.TrimEnd(separator) + separator + b.TrimStart(separator);
        }

        foreach (var part in parts) {
            if (string.IsNullOrEmpty(part))
                continue;

            if (result.EndsWith("?") || part.StartsWith("?"))
                result = CombineEnsureSingleSeparator(result, part, '?');
            else if (result.EndsWith("#") || part.StartsWith("#"))
                result = CombineEnsureSingleSeparator(result, part, '#');
            else if (inFragment)
                result += part;
            else if (inQuery)
                result = CombineEnsureSingleSeparator(result, part, '&');
            else
                result = CombineEnsureSingleSeparator(result, part, '/');

            if (part.Contains("#")) {
                inQuery = false;
                inFragment = true;
            }
            else if (!inFragment && part.Contains("?")) {
                inQuery = true;
            }
        }
        return EncodeIllegalCharacters(result);
    }

    /// <summary>
    /// URL-encodes characters in a string that are neither reserved nor unreserved. Avoids encoding reserved characters such as '/' and '?'. Avoids encoding '%' if it begins a %-hex-hex sequence (i.e. avoids double-encoding).
    /// </summary>
    /// <param name="s">The string to encode.</param>
    /// <param name="encodeSpaceAsPlus">If true, spaces will be encoded as + signs. Otherwise, they'll be encoded as %20.</param>
    /// <returns>The encoded URL.</returns>
    public static string EncodeIllegalCharacters(string s, bool encodeSpaceAsPlus = false) {
        if (string.IsNullOrEmpty(s))
            return s;

        if (encodeSpaceAsPlus)
            s = s.Replace(" ", "+");

        // Uri.EscapeUriString mostly does what we want - encodes illegal characters only - but it has a quirk
        // in that % isn't illegal if it's the start of a %-encoded sequence https://stackoverflow.com/a/47636037/62600

        // no % characters, so avoid the regex overhead
        if (!s.Contains("%"))
            return Uri.EscapeUriString(s);

        // pick out all %-hex-hex matches and avoid double-encoding 
        return Regex.Replace(s, "(.*?)((%[0-9A-Fa-f]{2})|$)", c => {
            var a = c.Groups[1].Value; // group 1 is a sequence with no %-encoding - encode illegal characters
            var b = c.Groups[2].Value; // group 2 is a valid 3-character %-encoded sequence - leave it alone!
            return Uri.EscapeUriString(a) + b;
        });
    }