console.log("searching Array: "+finding_array);
console.log("searching in:"+reference_array);
var check_match_counter = 0;
for (var j = finding_array.length - 1; j >= 0; j--) 
{
    if(reference_array.indexOf(finding_array[j]) > 0)
    {
        check_match_counter = check_match_counter + 1;
    }
}
 var match = (check_match_counter > 0) ? true : false;
console.log("Final result:"+match);

使用筛选器/indexOf：

函数containsAny（源，目标）{var result=source.filter（函数（项）{return target.indexOf（项）>-1}）；返回（result.length>0）；} //结果var fruits=[“苹果”、“香蕉”、“橙色”]；console.log（包含任何（水果，[“苹果”，“葡萄”]）；console.log（包含任何（水果，[“苹果”，“香蕉”，“菠萝”]）；console.log（包含任何（水果，[“葡萄”，“菠萝”]）；

良好的性能解决方案：

我们应该将其中一个数组转换为对象。

const contains = (arr1, mainObj) => arr1.some(el => el in mainObj);
const includes = (arr1, mainObj) => arr1.every(el => el in mainObj);

用法：

const mainList = ["apple", "banana", "orange"];
// We make object from array, you can use your solution to make it
const main = Object.fromEntries(mainList.map(key => [key, true]));

contains(["apple","grape"], main) // => true
contains(["apple","banana","pineapple"], main) // =>  true
contains(["grape", "pineapple"], main) // =>  false

includes(["apple", "grape"], main) // => false
includes(["banana", "apple"], main) // =>  true

您可能会面临由in运算符检查的一些缺点（例如｛｝//=>true中的“toString”），因此您可以将解决方案更改为obj[key]检查器

带下划线js

var a1 = [1,2,3];
var a2 = [1,2];

_.every(a1, function(e){ return _.include(a2, e); } ); //=> false
_.every(a2, function(e){ return _.include(a1, e); } ); //=> true

更新@Paul Grimshaw答案，使用includes代替indexOf以提高可读性

let found=arr1.some（r=>arr2.indexOf（r）>=0）let found=arr1.some（r=>arr2.includes（r））

var target = ["apple","banana","orange"];
var checkArray = ["apple","banana","pineapple"];

var containsOneCommonItem = target.some(x => checkArray.some(y => y === x));`

["apple","grape"] //returns true;

["apple","banana","pineapple"] //returns true;

["grape", "pineapple"] //returns false;