我自己的简单解决方案(区分大小写):

uint8_t strContains(char* string, char* toFind)
{
    uint8_t slen = strlen(string);
    uint8_t tFlen = strlen(toFind);
    uint8_t found = 0;

    if( slen >= tFlen )
    {
        for(uint8_t s=0, t=0; s<slen; s++)
        {
            do{

                if( string[s] == toFind[t] )
                {
                    if( ++found == tFlen ) return 1;
                    s++;
                    t++;
                }
                else { s -= found; found=0; t=0; }

              }while(found);
        }
        return 0;
    }
    else return -1;
}

结果

strContains("this is my sample example", "th") // 1
strContains("this is my sample example", "sample") // 1
strContains("this is my sample example", "xam") // 1
strContains("this is my sample example", "ple") // 1
strContains("this is my sample example", "ssample") // 0
strContains("this is my sample example", "samplee") // 0
strContains("this is my sample example", "") // 0
strContains("str", "longer sentence") // -1
strContains("ssssssample", "sample") // 1
strContains("sample", "sample") // 1

在ATmega328P上测试(avr8-gnu-toolchain-3.5.4.1709);)

尝试使用指针…

#include <stdio.h>
#include <string.h>

int main()
{

  char str[] = "String1 subString1 Strinstrnd subStr ing1subString";
  char sub[] = "subString";

  char *p1, *p2, *p3;
  int i=0,j=0,flag=0;

  p1 = str;
  p2 = sub;

  for(i = 0; i<strlen(str); i++)
  {
    if(*p1 == *p2)
      {
          p3 = p1;
          for(j = 0;j<strlen(sub);j++)
          {
            if(*p3 == *p2)
            {
              p3++;p2++;
            } 
            else
              break;
          }
          p2 = sub;
          if(j == strlen(sub))
          {
             flag = 1;
            printf("\nSubstring found at index : %d\n",i);
          }
      }
    p1++; 
  }
  if(flag==0)
  {
       printf("Substring NOT found");
  }
return (0);
}

我自己的简单解决方案(区分大小写):

uint8_t strContains(char* string, char* toFind)
{
    uint8_t slen = strlen(string);
    uint8_t tFlen = strlen(toFind);
    uint8_t found = 0;

    if( slen >= tFlen )
    {
        for(uint8_t s=0, t=0; s<slen; s++)
        {
            do{

                if( string[s] == toFind[t] )
                {
                    if( ++found == tFlen ) return 1;
                    s++;
                    t++;
                }
                else { s -= found; found=0; t=0; }

              }while(found);
        }
        return 0;
    }
    else return -1;
}

结果

strContains("this is my sample example", "th") // 1
strContains("this is my sample example", "sample") // 1
strContains("this is my sample example", "xam") // 1
strContains("this is my sample example", "ple") // 1
strContains("this is my sample example", "ssample") // 0
strContains("this is my sample example", "samplee") // 0
strContains("this is my sample example", "") // 0
strContains("str", "longer sentence") // -1
strContains("ssssssample", "sample") // 1
strContains("sample", "sample") // 1

在ATmega328P上测试(avr8-gnu-toolchain-3.5.4.1709);)

下面这段简单的代码也能达到同样的效果:

int main(void)
{

    char mainstring[]="The quick brown fox jumps over the lazy dog";
    char substring[20];
    int i=0;
    puts("enter the sub string to find");
    fgets(substring, sizeof(substring), stdin);
    substring[strlen(substring)-1]='\0';
    if (strstr(mainstring,substring))
    {
            printf("substring is present\t");
    }
    printf("and the sub string is:::");
    printf("%s",substring,"\n");
   return 0;
}

但棘手的部分是报告子字符串从原始字符串的哪个位置开始…

if (strstr(sent, word) != NULL) {
    /* ... */
}

注意，如果找到单词word, strstr将返回一个指向在sent中单词开头的指针。

下面是如何报告找到的子字符串的第一个字符的位置:

在上面的代码中替换这一行:

printf("%s",substring,"\n");

:

printf("substring %s was found at position %d \n", substring,((int) (substring - mainstring)));