我正在为移动设备建立一个网站。有一页特别适合在横屏模式下浏览。

是否有一种方法来检测访问该页面的用户是否在纵向模式下查看它,如果是的话,显示一条消息通知用户该页面在横向模式下查看最好?如果用户已经在横屏模式下查看,则不会出现任何消息。

所以基本上,我想让网站检测视口的方向,如果方向是纵向,然后显示一个警告消息,建议用户这个页面最好在横向模式下查看。


当前回答

CCS只

@media (max-width: 1024px) and (orientation: portrait){ /* tablet and smaller */
  body:after{
    position: absolute;
    z-index: 9999;
    width: 100%;
    top: 0;
    bottom: 0;
    content: "";
    background: #212121 url(http://i.stack.imgur.com/sValK.png) 0 0 no-repeat; /* replace with an image that tells the visitor to rotate the device to landscape mode */
    background-size: 100% auto;
    opacity: 0.95;
  }
}

在某些情况下,你可能想要添加一小段代码,以便在访问者旋转设备后重新加载到页面,这样CSS就能正确呈现:

window.onorientationchange = function() { 
    var orientation = window.orientation; 
        switch(orientation) { 
            case 0:
            case 90:
            case -90: window.location.reload(); 
            break; } 
};

其他回答

我不同意投票最多的答案。用屏风而不是窗户

    if(screen.innerHeight > screen.innerWidth){
    alert("Please use Landscape!");
}

是正确的方法。如果用窗口计算。高度,你在Android上就会遇到麻烦。当键盘打开时,窗口收缩。所以用screen代替window。

screen.orientation.type是一个很好的答案,但是使用IE。 https://caniuse.com/#search=screen.orientation

//see also http://stackoverflow.com/questions/641857/javascript-window-resize-event
//see also http://mbccs.blogspot.com/2007/11/fixing-window-resize-event-in-ie.html
/*
Be wary of this:
While you can just hook up to the standard window resize event, you'll find that in IE, the event is fired once for every X and once for every Y axis movement, resulting in a ton of events being fired which might have a performance impact on your site if rendering is an intensive task.
*/

//setup 
window.onresize = function(event) {
    window_resize(event);
}

//timeout wrapper points with doResizeCode as callback
function window_resize(e) { 
     window.clearTimeout(resizeTimeoutId); 
     resizeTimeoutId = window.setTimeout('doResizeCode();', 10); 
}

//wrapper for height/width check
function doResizeCode() {
    if(window.innerHeight > window.innerWidth){
        alert("Please view in landscape");
    }
}

为了将所有这些伟大的注释应用到我的日常编码中,为了所有应用程序之间的连续性,我决定在我的jquery和jquery移动代码中使用以下内容。

window.onresize = function (event) {
  applyOrientation();
}

function applyOrientation() {
  if (window.innerHeight > window.innerWidth) {
    alert("You are now in portrait");
  } else {
    alert("You are now in landscape");
  }
}

iOS不更新屏幕。宽度和屏幕。方向改变时的高度。Android不更新窗口。当它改变方向时。

我对这个问题的解决方案是:

var isAndroid = /(android)/i.test(navigator.userAgent);

if(isAndroid)
{
    if(screen.width < screen.height){
        //portrait mode on Android
    }
} else {
    if(window.orientation == 0){
        //portrait mode iOS and other devices
    }
}

你可以通过以下代码在Android和iOS上检测这种方向变化:

var supportsOrientationChange = "onorientationchange" in window,
    orientationEvent = supportsOrientationChange ? "orientationchange" : "resize";

window.addEventListener(orientationEvent, function() {
    alert("the orientation has changed");
}, false);

如果onorientationchange事件不受支持,事件绑定将是resize事件。

我用的是Android Chrome的“屏幕朝向API”

要查看当前的方向,请调用console.log(screen.orientation.type)(也可以调用screen.orientation.angle)。

结果:肖像-主|肖像-次|景观-主|景观-次

下面是我的代码,希望对大家有所帮助:

var m_isOrientation = ("orientation" in screen) && (typeof screen.orientation.lock == 'function') && (typeof screen.orientation.unlock == 'function');
...
if (!isFullscreen()) return;
screen.orientation.lock('landscape-secondary').then(
    function() {
        console.log('new orientation is landscape-secondary');
    },
    function(e) {
        console.error(e);
    }
);//here's Promise
...
screen.orientation.unlock();

我只测试了Android Chrome -好的