我的代码如下:
public void ReadListItem()
{
List<uint> lst = new List<uint>() { 1, 2, 3, 4, 5 };
string str = string.Empty;
foreach (var item in lst)
str = str + item + ",";
str = str.Remove(str.Length - 1);
Console.WriteLine(str);
}
输出:1、2、3、4、5所示
将List<uint>转换为逗号分隔的字符串的最简单方法是什么?
当前回答
Try
Console.WriteLine((string.Join(",", lst.Select(x=>x.ToString()).ToArray())));
HTH
其他回答
如果你的列表项有多个字符串，你也可以重写ToString():
public class ListItem
{
public string string1 { get; set; }
public string string2 { get; set; }
public string string3 { get; set; }
public override string ToString()
{
return string.Join(
","
, string1
, string2
, string3);
}
}
获取CSV字符串:
ListItem item = new ListItem();
item.string1 = "string1";
item.string2 = "string2";
item.string3 = "string3";
List<ListItem> list = new List<ListItem>();
list.Add(item);
string strinCSV = (string.Join("\n", list.Select(x => x.ToString()).ToArray()));
你可以像这样用逗号分隔列表实体:
//phones is a list of PhoneModel
var phoneNumbers = phones.Select(m => m.PhoneNumber)
.Aggregate(new StringBuilder(),
(current, next) => current.Append(next).Append(" , ")).ToString();
// Remove the trailing comma and space
if (phoneNumbers.Length > 1)
phoneNumbers = phoneNumbers.Remove(phoneNumbers.Length - 2, 2);
你可以使用字符串。Join方法组合项目:
var str = String.Join(",", lst);
Try
Console.WriteLine((string.Join(",", lst.Select(x=>x.ToString()).ToArray())));
HTH
使用字符串。加入:
string.Join<string>(",", lst);
使用LINQ聚合:
lst .Aggregate((a, x) => a + "," + x);
