你可以这样做:

def active_action?(controller)
   'active' if controller.remove('/') == controller_name
end

现在，你可以这样用:

<%= link_to users_path, class: "some-class #{active_action? users_path}" %>

我假设你指的是URI:

class BankController < ActionController::Base
  before_filter :pre_process 

  def index
    # do something
  end

  private
    def pre_process
      logger.debug("The URL" + request.url)
    end
end

根据你下面的评论，如果你需要控制器的名称，你可以简单地这样做:

  private
    def pre_process
      self.controller_name        #  Will return "order"
      self.controller_class_name  # Will return "OrderController"
    end

你可以这样做

Rails.application.routes.recognize_path "/your/path"

它在rails 3.1.0.rc4中为我工作

在rails 3中，你可以通过rails .application.routes对象访问Rack::Mount::RouteSet对象，然后直接调用它上的recognition函数

route, match, params = Rails.application.routes.set.recognize(controller.request)

得到第一个(最佳)匹配，下面的块形式循环匹配的路由:

Rails.application.routes.set.recognize(controller.request) do |r, m, p|
  ... do something here ...
end

一旦有了路由，就可以通过route.name获取路由名。如果您需要获取特定URL的路由名称，而不是当前请求路径，那么您需要模拟一个假请求对象以传递到机架，请检查ActionController::Routing::Routes。来看看它们是怎么做的。

你可以通过rake:routes看到所有的路由(这可能对你有帮助)。

要查找URI:

current_uri = request.env['PATH_INFO']
# If you are browsing http://example.com/my/test/path, 
# then above line will yield current_uri as "/my/test/path"

找到路径，即控制器，动作和参数:

path = ActionController::Routing::Routes.recognize_path "/your/path/here/"

# ...or newer Rails versions:
#
path = Rails.application.routes.recognize_path('/your/path/here')

controller = path[:controller]
action = path[:action]
# You will most certainly know that params are available in 'params' hash