我知道函数debug_backtrace,但我正在寻找一些准备使用函数的实现,如GetCallingMethodName()?如果它也给出了方法的类(如果它确实是一个方法),那就太完美了。
当前回答
debug_backtrace()函数是知道这一点的唯一方法,如果你很懒,这是你应该自己编写GetCallingMethodName()的另一个原因。战胜懒惰!: D
其他回答
debug_backtrace()函数是知道这一点的唯一方法,如果你很懒,这是你应该自己编写GetCallingMethodName()的另一个原因。战胜懒惰!: D
我需要一些东西来列出调用类/方法(在Magento项目上工作)。
虽然debug_backtrace提供了大量有用的信息,但它为Magento安装提供的信息量是压倒性的(超过82,000行!)因为我只关心调用函数和类,所以我想出了这个小解决方案:
$callers = debug_backtrace();
foreach( $callers as $call ) {
echo "<br>" . $call['class'] . '->' . $call['function'];
}
我刚刚写了一个名为“get_caller”的版本,我希望它能有所帮助。我的爸爸很懒。你可以从函数中运行get_caller(),你不需要像这样指定它:
get_caller(__FUNCTION__);
下面是完整的脚本和一个古怪的测试用例:
<?php
/* This function will return the name string of the function that called $function. To return the
caller of your function, either call get_caller(), or get_caller(__FUNCTION__).
*/
function get_caller($function = NULL, $use_stack = NULL) {
if ( is_array($use_stack) ) {
// If a function stack has been provided, used that.
$stack = $use_stack;
} else {
// Otherwise create a fresh one.
$stack = debug_backtrace();
echo "\nPrintout of Function Stack: \n\n";
print_r($stack);
echo "\n";
}
if ($function == NULL) {
// We need $function to be a function name to retrieve its caller. If it is omitted, then
// we need to first find what function called get_caller(), and substitute that as the
// default $function. Remember that invoking get_caller() recursively will add another
// instance of it to the function stack, so tell get_caller() to use the current stack.
$function = get_caller(__FUNCTION__, $stack);
}
if ( is_string($function) && $function != "" ) {
// If we are given a function name as a string, go through the function stack and find
// it's caller.
for ($i = 0; $i < count($stack); $i++) {
$curr_function = $stack[$i];
// Make sure that a caller exists, a function being called within the main script
// won't have a caller.
if ( $curr_function["function"] == $function && ($i + 1) < count($stack) ) {
return $stack[$i + 1]["function"];
}
}
}
// At this stage, no caller has been found, bummer.
return "";
}
// TEST CASE
function woman() {
$caller = get_caller(); // No need for get_caller(__FUNCTION__) here
if ($caller != "") {
echo $caller , "() called " , __FUNCTION__ , "(). No surprises there.\n";
} else {
echo "no-one called ", __FUNCTION__, "()\n";
}
}
function man() {
// Call the woman.
woman();
}
// Don't keep him waiting
man();
// Try this to see what happens when there is no caller (function called from main script)
//woman();
?>
Man()调用woman(),后者调用get_caller()。Get_caller()还不知道是谁调用了它,因为woman()很谨慎,没有告诉它,所以它递归查找。然后返回谁调用了woman()。在浏览器中以源代码模式的打印输出显示了函数堆栈:
Printout of Function Stack:
Array
(
[0] => Array
(
[file] => /Users/Aram/Development/Web/php/examples/get_caller.php
[line] => 46
[function] => get_caller
[args] => Array
(
)
)
[1] => Array
(
[file] => /Users/Aram/Development/Web/php/examples/get_caller.php
[line] => 56
[function] => woman
[args] => Array
(
)
)
[2] => Array
(
[file] => /Users/Aram/Development/Web/php/examples/get_caller.php
[line] => 60
[function] => man
[args] => Array
(
)
)
)
man() called woman(). No surprises there.
从php 5.4开始就可以使用
$dbt=debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS,2);
$caller = isset($dbt[1]['function']) ? $dbt[1]['function'] : null;
这不会浪费内存,因为它忽略参数,只返回最后2个回溯堆栈条目,并且不会像这里的其他答案一样生成通知。
最简单的方法是:
echo debug_backtrace()[1]['function'];
正如下面的评论所指出的,可以通过将参数传递给:
省略object和args索引 限制返回的堆栈帧数
echo debug_backtrace(!DEBUG_BACKTRACE_PROVIDE_OBJECT|DEBUG_BACKTRACE_IGNORE_ARGS,2)[1]['function'];
推荐文章
- 致命错误:未找到类“SoapClient”
- 我目前使用的是哪个版本的CodeIgniter ?
- 合并两个PHP对象的最佳方法是什么?
- 如何使HTTP请求在PHP和不等待响应
- 发送附件与PHP邮件()?
- 如何获得当前的路线在Symfony 2?
- 如何设置断点在内联Javascript在谷歌Chrome?
- 用PHP删除字符串的前4个字符
- mysql_connect():[2002]没有这样的文件或目录(试图通过unix:///tmp/mysql.sock连接)在
- 一个函数的多个返回值
- 在PHP中使用foreach循环时查找数组的最后一个元素
- 检查数组是否为空
- PHP DOMDocument loadHTML没有正确编码UTF-8
- PHP在个位数数前加上前导零
- PHPMailer字符编码问题