考虑:
var myArray = ['January', 'February', 'March'];
如何使用JavaScript从这个数组中选择一个随机值?
考虑:
var myArray = ['January', 'February', 'March'];
如何使用JavaScript从这个数组中选择一个随机值?
当前回答
~~比Math.Floor()快得多,所以当涉及到使用UI元素生成输出的性能优化时,~~赢得了比赛。更多信息
var rand = myArray[~~(Math.random() * myArray.length)];
但是,如果您知道数组将有数百万个元素,那么您可能需要在位操作符和Math.Floor()之间重新考虑,因为位操作符对大数字的表现很奇怪。请参阅下面的输出示例。
var number = Math.floor(14444323231.2); // => 14444323231
var number = 14444323231.2 | 0; // => 1559421343
其他回答
我真的很惊讶没有人尝试使用本机随机值:
array[Date.now()%array.length]
对于长度超过160000000000的数组,它将不起作用,但我相信您永远不会创建这样的数组
UPD
至于你的问题是如何从名为myArray的数组中选择随机值(与len=3),解决方案应该是:
myArray[Date.now()%myArray.length]
var item = myArray[Math.floor(Math.random()*myArray.length)];
或相当短的版本:
var item = myArray[(Math.random()*myArray.length)|0];
示例代码:
var myArray = ['January', 'February', 'March']; var item = myArray[(Math.random()*myArray.length)|0]; console.log(“项目:”,项目);
下面是一个如何做到这一点的例子:
$scope.ctx.skills = data.result.skills;
$scope.praiseTextArray = [
"Hooray",
"You\'re ready to move to a new skill",
"Yahoo! You completed a problem",
"You\'re doing great",
"You succeeded",
"That was a brave effort trying new problems",
"Your brain was working hard",
"All your hard work is paying off",
"Very nice job!, Let\'s see what you can do next",
"Well done",
"That was excellent work",
"Awesome job",
"You must feel good about doing such a great job",
"Right on",
"Great thinking",
"Wonderful work",
"You were right on top of that one",
"Beautiful job",
"Way to go",
"Sensational effort"
];
$scope.praiseTextWord = $scope.praiseTextArray[Math.floor(Math.random()*$scope.praiseTextArray.length)];
为了寻找一句真正的俏皮话,我得出了这个结论:
['January', 'February', 'March'].reduce((a, c, i, o) => { return o[Math.floor(Math.random() * Math.floor(o.length))]; })
这与@Jacob Relkin的解决方案类似,但更普遍:
这是ES2015:
const randomChoice = arr => {
const randIndex = Math.floor(Math.random() * arr.length);
return arr[randIndex];
};
该代码的工作原理是在0到数组长度之间选择一个随机数,然后返回该下标处的项。