在尝试了合成操作和在画布上绘制图像后,我现在试图删除图像和合成。我怎么做呢?

我需要清除画布重绘其他图像;这可能会持续一段时间,所以我不认为每次都画一个新的矩形是最有效的选择。


当前回答

This is a Free hand drawing Canvas with a Clear Canvas Button. See this live example of a canvas which you can draw on and also when required clear it for redrawing clearRect() is used to delete the prersent canvas and fillRect() is used to again draw the initial canvas which was clean and had no drawings on it. var canvas = document.getElementById("canvas"), ctx = canvas.getContext("2d"), painting = false, lastX = 0, lastY = 0, lineThickness = 1; canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250); canvas.onmousedown = function(e) { painting = true; ctx.fillStyle = "#ffffff"; lastX = e.pageX - this.offsetLeft; lastY = e.pageY - this.offsetTop; }; canvas.onmouseup = function(e){ painting = false; } canvas.onmousemove = function(e) { if (painting) { mouseX = e.pageX - this.offsetLeft; mouseY = e.pageY - this.offsetTop; // find all points between var x1 = mouseX, x2 = lastX, y1 = mouseY, y2 = lastY; var steep = (Math.abs(y2 - y1) > Math.abs(x2 - x1)); if (steep){ var x = x1; x1 = y1; y1 = x; var y = y2; y2 = x2; x2 = y; } if (x1 > x2) { var x = x1; x1 = x2; x2 = x; var y = y1; y1 = y2; y2 = y; } var dx = x2 - x1, dy = Math.abs(y2 - y1), error = 0, de = dy / dx, yStep = -1, y = y1; if (y1 < y2) { yStep = 1; } lineThickness = 4; for (var x = x1; x < x2; x++) { if (steep) { ctx.fillRect(y, x, lineThickness , lineThickness ); } else { ctx.fillRect(x, y, lineThickness , lineThickness ); } error += de; if (error >= 0.5) { y += yStep; error -= 1.0; } } lastX = mouseX; lastY = mouseY; } } var button=document.getElementById("clear"); button.onclick=function clearcanvas(){ canvas=document.getElementById("canvas"), ctx = canvas.getContext('2d'); ctx.clearRect(0, 0, 250, 250); canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250);} #clear{border-radius:10px; font-size:8px !important; position:absolute; top:1px;} #canvas{border-radius:10px} <link href="https://www.w3schools.com/w3css/4/w3.css" rel="stylesheet"/> <button id="clear" class="w3-padding w3-xxlarge w3-pink" type="button">Clear Canvas</button> <canvas id="canvas"></canvas>

其他回答

我总是用这个

ctx.clearRect(0, 0, canvas.width, canvas.height)
window.requestAnimationFrame(functionToBeCalled)

NOTE

结合clearRect和requestAnimationFrame允许更流畅的动画,如果这是你想要的

假设canvas是一个canvas元素或者OffscreenCanvas对象,使用clearRect:

const context = canvas.getContext('2d');
context.clearRect(0, 0, canvas.width, canvas.height);

This is a Free hand drawing Canvas with a Clear Canvas Button. See this live example of a canvas which you can draw on and also when required clear it for redrawing clearRect() is used to delete the prersent canvas and fillRect() is used to again draw the initial canvas which was clean and had no drawings on it. var canvas = document.getElementById("canvas"), ctx = canvas.getContext("2d"), painting = false, lastX = 0, lastY = 0, lineThickness = 1; canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250); canvas.onmousedown = function(e) { painting = true; ctx.fillStyle = "#ffffff"; lastX = e.pageX - this.offsetLeft; lastY = e.pageY - this.offsetTop; }; canvas.onmouseup = function(e){ painting = false; } canvas.onmousemove = function(e) { if (painting) { mouseX = e.pageX - this.offsetLeft; mouseY = e.pageY - this.offsetTop; // find all points between var x1 = mouseX, x2 = lastX, y1 = mouseY, y2 = lastY; var steep = (Math.abs(y2 - y1) > Math.abs(x2 - x1)); if (steep){ var x = x1; x1 = y1; y1 = x; var y = y2; y2 = x2; x2 = y; } if (x1 > x2) { var x = x1; x1 = x2; x2 = x; var y = y1; y1 = y2; y2 = y; } var dx = x2 - x1, dy = Math.abs(y2 - y1), error = 0, de = dy / dx, yStep = -1, y = y1; if (y1 < y2) { yStep = 1; } lineThickness = 4; for (var x = x1; x < x2; x++) { if (steep) { ctx.fillRect(y, x, lineThickness , lineThickness ); } else { ctx.fillRect(x, y, lineThickness , lineThickness ); } error += de; if (error >= 0.5) { y += yStep; error -= 1.0; } } lastX = mouseX; lastY = mouseY; } } var button=document.getElementById("clear"); button.onclick=function clearcanvas(){ canvas=document.getElementById("canvas"), ctx = canvas.getContext('2d'); ctx.clearRect(0, 0, 250, 250); canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250);} #clear{border-radius:10px; font-size:8px !important; position:absolute; top:1px;} #canvas{border-radius:10px} <link href="https://www.w3schools.com/w3css/4/w3.css" rel="stylesheet"/> <button id="clear" class="w3-padding w3-xxlarge w3-pink" type="button">Clear Canvas</button> <canvas id="canvas"></canvas>

这是我使用的,不管边界和矩阵变换:

function clearCanvas(canvas) {
  const ctx = canvas.getContext('2d');
  ctx.save();
  ctx.globalCompositeOperation = 'copy';
  ctx.strokeStyle = 'transparent';
  ctx.beginPath();
  ctx.lineTo(0, 0);
  ctx.stroke();
  ctx.restore();
}

基本上,它保存了上下文的当前状态,并以globalCompositeOperation为copy绘制了一个透明像素。然后,恢复以前的上下文状态。

在webkit中,您需要将宽度设置为不同的值,然后您可以将其设置回初始值